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Secants, Tangents and Angle Measures
Chapter 10-6
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Find measures of angles formed by lines intersecting on or inside a circle.
secant Find measures of angles formed by lines intersecting outside the circle. Standard Students prove and use theorems involving the properties of parallel lines cut by a transversal, the properties of quadrilaterals, and the properties of circles. (Key) Standard Students prove and solve problems regarding relationships among chords, secants, tangents, inscribed angles, and inscribed and circumscribed polygons of circles. (Key) Lesson 6 MI/Vocab
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Tangent-Chord (or secant) Theorem
If a tangent and a chord intersect at a point on a circle, then the measure of each angle formed is one half its intercepted arc 100o X Y mX = ½ (100o) mX = 50o mY = ½ (260o) mY = 130o
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Secant-Tangent Angle 110o Answer: 55 Lesson 6 Ex2
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A. 122 B. 58 C. 106 D. 116 A B C D Lesson 6 CYP2
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2-Chord (or Secant) Theorem
If 2 chords intersect in the interior of a circle, then the measure of the angle formed is one half of the sum of the arcs intercepted by the angle and its vertical angle. 100o X 40o mX = ½ ( ) mX = ½ (140) mX = 70o
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Secant-Secant Angle Method 1 Lesson 6 Ex1
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Secant-Secant Angle Method 2 Answer: 98 Lesson 6 Ex1
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A. 42 B. 84 C. 96 D. 138 A B C D Lesson 6 CYP1
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2-Line Theorem If 2 lines intersect on the exterior of a circle, then the measure of the angle formed is one half of the difference of the 2 intercepted arcs.
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Example: 100o X 40o mX = ½ ( ) mX = ½ (60) mX = 30o
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Secant-Secant Angle Find x. Answer: 17 Lesson 6 Ex3
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Find x. A. 76 B. 73 C. 111 D. 146 A B C D Lesson 6 CYP3
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JEWELRY A jeweler wants to craft a pendant with the shape shown
JEWELRY A jeweler wants to craft a pendant with the shape shown. Use the figure to determine the measure of the arc at the bottom of the pendant. 360 – x Answer: 220 x Lesson 6 Ex4
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PARKS Two sides of a fence to be built around a circular garden in a park are shown. Use the figure to determine the measure of A. A. 75 B C. 105 D. 52.5 A B C D Lesson 6 CYP4
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Secant-Tangent Angle Find x. 141° 62° x° 62 = (141 – x) 124 = 141 – x –17 = –x 17 = x Answer: x = 17 Lesson 6 Ex5
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Find x. A. B. 5 C. 9 D. A B C D Lesson 6 CYP5
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Homework Chapter 10.6 Pg 603 6 – 26, 32 – 34, 55 – 57
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