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Examination of properties reveals why

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Presentation on theme: "Examination of properties reveals why"— Presentation transcript:

1 Examination of properties reveals why
Why “periodic?” Examination of properties reveals why

2 Learning objectives Define ionization energy and electron affinity
Describe periodic trend in atomic and ionic radius and ionization energy Predict order of atomic/ionic sizes using concept of shielding and periodic table

3 Properties show periodic variation

4 Periodic trends in atomic size

5 Atoms and ions Ions are created by removing or adding electrons
Positive ions are smaller than the neutral atoms Negative ions are larger than the neutral atoms

6 Isoelectronic ions Isoelectronic ions have same number of electrons
Na [Ne]3s1; Mg [Ne]3s2; Al [Ne]3s23p1 Na+ [Ne]+; Mg2+ [Ne]2+; Al3+ [Ne]3+ P [Ne]3s23p3; S [Ne]3s23p4; Cl [Ne]3s23p5 P3- [Ar]3-; S2- [Ar]2-; Cl- [Ar]- Isoelectronic cations, higher charged ions are smaller (nuclear attraction is stronger) Na+ > Mg2+ > Al3+ Isoelectronic anions, higher charged ions are larger (nuclear attraction is weaker) P3- > S2- > Cl-

7 Ionization energy: energy required to remove electron from isolated gaseous atom: A(g) = A+(g) + e

8 Electron affinity: energy released when electron is added to isolated gaseous atom: A(g) + e = A-(g)

9 Explain these trends Atomic radius decreases across period, even though atomic number increases Ionization energy increases – electrons more tightly held

10 Shielding and effective nuclear charge
The “shell” picture helps to explain these observations Electrons in same shell experience stronger attraction to nucleus as shell fills Nearly full – high charge Nearly empty – low charge


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