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C.k.pithawalla college of enginnering & technology
Prepared by: Sr.no Name Enrollment no. 1 Nayani paril 2 Patel Nikunj 3 Parmar Mihir 4 Patel Adarsh 5 Patel Bhavin
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Topics: Euler’s Euqation Bernolli’s Equation Energy Correction Factor
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Euler’s Equation Define a function along a trajectory.
y(a,x) = y(0,x) + ah(x) Parametric function Variation h(x) is C1 function. End points h(x1) = h(x2) = 0 Find the integral J If y is varied J must increase x2 y(a, x) y(x) x1
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Parametrized Integral
Write the integral in parametrized form. Condition for extremum Expand with the chain rule Term a only appears with h Apply integration by parts … for all h(x)
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Euler’s Equation It must vanish for all h(x) This is Euler’s equation
h(x1) = h(x1) = 0 It must vanish for all h(x) This is Euler’s equation
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Geodesic A straight line is the shortest distance between two points in Euclidean space. Curves of minimum length are geodesics. Tangents remain tangent as they move on the geodesic Example: great circles on the sphere Euler’s equation can find the minimum path.
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Soap Film Find a surface of revolution. Find the area y
Minimize the function y (x2, y2) (x1, y1)
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Action next Motion involves a trajectory in configuration space Q.
Tangent space TQ for full description. The integral of the Lagrangian is the action. Find the extremum of action Euler’s equation can be applied to the action Euler-Lagrange equations Q q’ q next
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Energy Conservation (Bernoulli’s Equation)
Integration of Euler’s equation Bernoulli’s equation Flow work + kinetic energy + potential energy = constant Dx Under the action of the pressure, the fluid element moves a distance Dx within time Dt The work done per unit time DW/Dt (flow power) is p A
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Energy Conservation (cont.)
It is valid for incompressible fluids, steady flow along a streamline, no energy loss due to friction, no heat transfer. Determine the velocity and mass flow rate of efflux from the circular hole (0.1 m dia.) at the bottom of the water tank (at this instant). The tank is open to the atmosphere and H=4 m Examples: 1 p1 = p2, V1=0 H 2
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Energy Equation(cont.)
Example: If the tank has a cross-sectional area of 1 m2, estimate the time required to drain the tank to level 2. 1 First, choose the control volume as enclosed by the dotted line. Specify h=h(t) as the water level as a function of time. h(t) 2 20 40 60 80 100 1 2 3 4 time (sec.) water height (m) 2.5e-007 h ( ) t
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Energy conservation (cont.)
Energy added, hA (ex. pump, compressor) Generalized energy concept: Energy loss, hL (ex. friction, valve, expansion) Energy extracted, hE (ex. turbine, windmill) hL loss through valves heat exchanger hA hE pump turbine hL, friction loss through pipes hL loss through elbows condenser
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Energy conservation(cont.)
Examples: Determine the efficiency of the pump if the power input of the motor is measured to be 1.5 hp. It is known that the pump delivers 300 gal/min of water. 6-in dia. pipe 4-in dia.pipe hE=hL=0, z1=z2 1 pump 2 Q=300 gal/min=0.667 ft3/s=AV V1=Q/A1=3.33 ft/s V2=Q/A2=7.54 ft/s zo Z=15 in Mercury (m=844.9 lb/ft3) water (w=62.4 lb/ft3) 1 hp=550 lb-ft/s
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Energy conservation (cont.)
Example (cont.)
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Frictional losses in piping system
R: radius, D: diameter L: pipe length w: wall shear stress P2 Consider a laminar, fully developed circular pipe flow w p P+dp Darcy’s Equation:
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Energy Conservation (cont.)
Energy: E=U(internal thermal energy)+Emech (mechanical energy) =U+KE(kinetic energy)+PE(potential energy) Work: W=Wext(external work)+Wflow(flow work) Heat: Q heat transfer via conduction, convection & radiation dE=dQ-dW, dQ>0 net heat transfer in dE>0 energy increase and vice versa dW>0, does positive work at the expense of decreasing energy, dE<0 U=mu, u(internal energy per unit mass), KE=(1/2)mV2, PE=mgz Wflow=m(p/) Their difference is due to external heat transfer and work done on flow
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Energy Conservation (cont.)
Heat in q=dQ/dt Work out dW/dt
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Energy Conservation(cont.)
Example: Superheated water vapor is entering the steam turbine with a mass flow rate of 1 kg/s and exhausting as saturated steam as shown. Heat loss from the turbine is 10 kW under the following operating condition. Determine the power output of the turbine. From superheated vapor table: hin= kJ/kg P=1.4 Mpa T=350 C V=80 m/s z=10 m 10 kw P=0.5 Mpa 100% saturated steam V=50 m/s z=5 m From saturated steam table: hout= kJ/kg
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Energy correction factor
Kinetic energy per unit mass Potential energy per unit mass
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Energy Equation Reynolds Transport Theorem b = e ; Bsys = E
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Work Rate of Work Shaft work work done by a mechanical device which crosses the CS Flow work work done by pressure forces on the CS Viscous work work done by viscous stresses at the CS
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Flow Work Work occurs at the CS when a force associated with the normal stress of the fluid acts over a distance. The normal stress equals the negative of the fluid pressure.
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Energy Equation
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Kinetic Energy Correction Factor
For nonuniform flows, this term requires special attention We can modify this kinetic energy term by a dimensionless factor, a, so that the integral is proportional to the square of the average velocity where and Kinetic energy correction factor so
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Energy Equation for Pipe Flow
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Thank You
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