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COORDINATES, GRAPHS AND LINES
RAFIZAH KECHIL, UiTM PULAU PINANG (Source: Cengage Learning,Hasfazilah Ahmat)
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At the end of this lesson, students should be able to:
• Find the absolute values of real. • Solve inequalities involving absolute values.
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Absolute Value : Definition of Absolute Value
The absolute value represent magnitude, or the distance between the origin and the point on the real number line.
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Example 7 – Finding Absolute Values
c. | – 4.3 | = 4.3 d. –| – 6 | = – (6) = –6
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Properties of Absolute Value
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Inequalities Involving Absolute Values
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Example 5 – Solving an Absolute Value Inequality
Solve each inequality. a. | x – 5 | < 2 Solution: a. | x – 5 | < 2 –2 < x – 5 < 2 –2 + 5 < x – < 2 + 5 3 < x < 7 The solution set is all real numbers that are greater than 3 and less than 7, which is denoted by (3, 7). Write original inequality. Write equivalent inequalities. | x – 5 | < 2: Solutions lie inside (3, 7). Add 5 to each part. Simplify.
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Example 5 – Solution b. | x + 3 | 7 x + 3 –7 or x + 3 7
cont’d b. | x + 3 | 7 x + 3 – or x + 3 7 x + 3 – 3 –7 – x + 3 – 3 7 – 3 x –10 x 4 The interval notation for this solution set is (-∞ ,–10][4,∞). The symbol is called a union symbol and is used to denote the combining of two sets. Write original inequality. Write equivalent inequalities. Subtract 3 from each side. Simplify. | x + 3 | 7: Solutions lie outside (–10, 4).
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Solving Linear
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Solving Linear
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Solving Rational
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At the end of this lesson, students should be able to:
Use the imaginary unit i to write complex numbers. Add, subtract, and multiply complex numbers. Use complex conjugates to write the quotient of two complex numbers in standard form. Find complex solutions of quadratic equations.
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Complex Numbers The imaginary unit i, defined as i = where i 2 = –1.
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Complex Numbers The set of real numbers is a subset of the set of complex numbers, as shown in Figure 1. Figure 1
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Complex Numbers : Algebraic Operation
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Example 1 – Adding and Subtracting Complex Numbers
a. (4 + 7i ) + (1 – 6i ) = 4 + 7i + 1 – 6i = (4 + 1) + (7i – 6i ) = 5 + i b. (1 + 2i ) – (4 + 2i ) = 1 + 2i – 4 – 2i = (1 – 4) + (2i – 2i ) = –3 + 0 = –3 Remove parentheses. Group like terms. Write in standard form. Remove parentheses. Group like terms. Simplify. Write in standard form.
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Example 1 – Adding and Subtracting Complex Numbers
cont’d c. 3i – (–2 + 3i ) – (2 + 5i ) = 3i + 2 – 3i – 2 – 5i = (2 – 2) + (3i – 3i – 5i ) = 0 – 5i = – 5i d. (3 + 2i ) + (4 – i ) – (7 + i ) = 3 + 2i + 4 – i – 7 – i = (3 + 4 – 7) + (2i – i – i ) = 0 + 0i = 0
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Complex Numbers Properties used when two complex numbers are multiplied. (a + bi )(c + di ) = a(c + di ) + bi(c + di ) = ac + (ad )i + (bc)i + (bd )i 2 = ac + (ad )i + (bc)i + (bd )(–1) = ac – bd + (ad )i + (bc)i = (ac – bd ) + (ad + bc)i Distributive Property Distributive Property i 2 = –1 Commutative Property Associative Property
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Example 2 – Multiplying Complex Numbers
a. 4(–2 + 3i ) = 4(–2) + 4(3i ) = – i b. (2 – i )(4 + 3i ) = 2(4 + 3i ) – i(4 + 3i ) = 8 + 6i – 4i – 3i 2 = 8 + 6i – 4i – 3(–1) = (8 + 3) +(6i – 4i ) = i Distributive Property Simplify. Distributive Property Distributive Property i 2 = –1 Group like terms. Write in standard form.
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Example 2 – Multiplying Complex Numbers
cont’d c. (3 + 2i )(3 – 2i ) = 3(3 – 2i ) + 2i(3 – 2i ) = 9 – 6i + 6i – 4i 2 = 9 – 6i + 6i – 4(–1) = 9 + 4 = 13 The product of two complex numbers can be a real number. Distributive Property Distributive Property i 2 = –1 Simplify. Write in standard form.
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Example 2 – Multiplying Complex Numbers
cont’d d. (3 + 2i )2 = (3 + 2i )(3 + 2i ) = 3(3 + 2i ) + 2i(3 + 2i ) = 9 + 6i + 6i + 4i 2 = 9 + 6i + 6i + 4(–1) = i – 4 = i Square of a binomial Distributive Property Distributive Property i 2 = –1 Simplify. Write in standard form.
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Complex Numbers: Complex Conjugates
This pairs of complex numbers of the form a + bi and a – bi, called complex conjugates. (a + bi )(a – bi ) = a2 – abi + abi – b2i 2 = a2 – b2(–1) = a2 + b 2
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Complex Numbers: Complex Conjugates
To write the quotient of a + bi and c + di in standard form, multiply the numerator and denominator by the complex conjugate of the denominator to obtain Standard form
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Example 4 – Writing a Quotient of Complex Numbers in Standard Form
Multiply numerator and denominator by complex conjugate of denominator. Expand. i 2 = –1 Simplify. Write in standard form.
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Complex Solutions of Quadratic Equations
When solving a quadratic equation, you often obtain a result such as , which is not a real number. By factoring out i = , we can write this number in standard form. The number i is called the principal square root of –3.
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Example 6 – Complex Solutions of a Quadratic Equation
Solve (a) x2 + 4 = 0 and (b) 3x2 – 2x + 5 = 0. Solution: a. x2 + 4 = 0 x2 = –4 x = 2i b. 3x2 – 2x + 5 = 0 Write original equation. Subtract 4 from each side. Extract square roots. Write original equation. Quadratic Formula
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Example 6 – Solution cont’d Simplify. Write in standard form.
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