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Chapter 2 Review Geometric Reasoning.

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1 Chapter 2 Review Geometric Reasoning

2 2.1 Inductive Reasoning Vocabulary: Tasks:
Inductive Reasoning → reasoning based on patterns Conjecture → statement you believe to be true Counterexample → example that shows a conjecture is false. Tasks: Use patterns to find the next term in a pattern. Given information, write a conjecture. Provide counterexamples to false statements.

3 2.2 Conditional Statements
Vocabulary: Conditional Statements : if-then statements (p →q) Hypothesis: “If” part of conditional statement (p) Conclusion: “Then” part of conditional statement (q) Converse: q → p Inverse : ~p → ~q Contrapositive : ~q → ~p Tasks: Write conditional statements Identify the hypothesis and conclusion Write and/or identify the inverse, converse or contrapositive. Determine if they are true or false. If false provide a counterexample.

4 2.3 Deductive Reasoning Vocabulary: Tasks
Deductive reasoning: reasoning based on facts. Tasks Verify correct use of/use Law of Detachment If there is precipitation and the temperature is below 32F, then it will snow. It is snowing. CONJECTURE: There is precipitation and the temperature is below 32F. Why is this invalid? What would a valid use of detachment say? Law of Syllogism If an animal is a duck, then it has webbed feet. If an animal has webbed feet, then it can swim. A Mallard is a duck. Write an appropriate conclusion.

5 2.5 Algebraic Proofs Algebraic Properties (p. 11)

6 2.6/7: Geometric Proofs Given: Prove: is a right angle. Statements
1 2 B A C 3 Given: is a right angle. Prove: are complementary. Statements Reasons is a right angle. 1. Given 2. 2. Definition of right angle 3. 4. 5. 5. Definition of congruent angles 6. 7. 7. Definition of complementary mBAC = 90 Angle Addition Postulate Substitution Prop. m  m Substitution Prop.    are comp.

7 Given: m  mR    Prove: 2  3
1 Q P N M O R 3 4 Given: m  mR    Prove: 2  3 Statements Reasons 1. Given 2. m = m 2. 3. m+ m = mMOP m3+ m4 = mROP 3. 4. m+ m =90 m3+ m4 =90 4. 5. 5. Transitive Property 6. m+ m = m3+ m1 6. 7. 7. Subt. Prop. = 8. 2  3 8. m  mR    Def. of   add. Post. Substitution Prop. m1 + m2  m3 + m4 Substitution Prop. m2  m3 Def. of 

8 Prove:  is supplementary to 
1 4 3 k 2 Given:    Prove:  is supplementary to  Statements Reasons 1.    1. 2. m = m 2. 3.   are supplementary 3 4 are supplementary 3. 4. m+ m =180 m3+ m4 =180 4. 5. m+ m = m3+ m4 5. 6. m+ m = m3+ m1 6. 7. m = m3 7. 8. m+ m3 =180 8. 9.  is supplementary to  9. Given Def. of  Linear Pair Theorem Def. of supplementary Transitive Property (substitution prop) Substitution Property Subtraction Prop. Of = Substitution Property Def. of supplementary


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