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6.6 Vectors
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Direction: 45⁰ Magnitude=5 5 45⁰
Vector: A vector is a quantity that has both magnitude and direction It is customary to represent a vector by using an arrow terminal point A vector is drawn as a directed line segment, the arrow shows the direction. It does not mean it is a ray. 5 45⁰ initial point Direction: 45⁰ Magnitude=5
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Direction: 45⁰ Magnitude=5 5
Vector: A vector is a quantity that has both magnitude and direction A vector has no position. These are all the same vector 5 Magnitude=5 Direction: 45⁰
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Direction: 45⁰ Magnitude=5 5
The position vector has its initial point at the origin 5 Magnitude=5 Direction: 45⁰
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Direction: 45⁰ Magnitude=5 5
The position vector has its initial point at the origin 5 Magnitude=5 Direction: 45⁰
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This is the unit vector i
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This is the vector 2i
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This is the vector 3i
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This is the unit vector j
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This is the vector 2j
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This is the vector 3j
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The position vector has its initial point at the origin and can be represented as the sum of component vectors i and j
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The position vector has its initial point at the origin and can be represented as the sum of component vectors i and j
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This is the position vector for w=2i+3j
Since it is difficult to write vectors using bold print by hand we can also represent this vector as
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This is the position vector for v=-2i-3j
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Draw three representations of the vector u=i-2j on the graph, be sure to make one the position vector.
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Draw three representations of the vector u=-2i+j on the graph, be sure to make one the position vector.
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Vector v has initial point P and terminal point Q
Vector v has initial point P and terminal point Q. Write v in ai+bj form. Subtract the coordinates of the terminal point from the coordinates of the initial point. P Q
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Vector v has initial point P and terminal point Q
Vector v has initial point P and terminal point Q. Write v in ai+bj form. Q P
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Vector v has initial point P and terminal point Q
Vector v has initial point P and terminal point Q. Write v in ai+bj form. Q P
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Find the magnitude 3 -4
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To find the magnitude of a vector
-2 -5
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To find the magnitude of a vector
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Draw three representations of the vector w=3i - 2j
Write the vector v with initial point P (-6,1) and terminal point Q (-2,-3) in ai+bj form. Find the magnitude of the following vectors. u= -12i -5j w= -10j
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P odd
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You can multiply a vector by a scalar
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You can multiply a vector by a scalar.
Find
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Find 3w -6u
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You can add two vectors geometrically by placing the terminal point of one at the initial point of the other. Find The sum is represented by the resultant vector
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You can add two vectors algebraically by adding the corresponding components of the two vectors.
Find
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Add algebraically and graphically
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You can subtract vectors by adding the opposite of the second vector
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You can subtract two vectors algebraically by subtracting the corresponding components of the two vectors
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You can subtract vectors by adding the opposite of the second vector
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You can subtract two vectors algebraically by subtracting the corresponding components of the two vectors
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Notebook Link
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Find Algebraically.
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Find Geometrically
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Find Geometrically
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Show geometrically and algebraically
P 751 # Geometrically & Algebraically, #25 – 32Algebraically Show geometrically and algebraically Show algebraically
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Find the vector v in ai+bj given the magnitude and the angle it makes with the positive x-axis.
4 b a
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Find the vector v in ai+bj given the magnitude and the angle it makes with the positive x-axis.
3
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Find the vector v in ai+bj given the magnitude and the angle it makes with the positive x-axis.
3 a
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Find the vector v in ai+bj given the magnitude and the angle it makes with the positive x-axis.
2
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Find the vector v in ai+bj given the magnitude and the angle it makes with the positive x-axis.
4 b a
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The jet stream is blowing at 40 mph and the direction N30°E
The jet stream is blowing at 40 mph and the direction N30°E. Express its velocity as a vector v in terms of i and j. N 40mph W E S
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A child pulls a wagon with a force of 25lbs on the handle that makes an angle 40° with the ground. Express its velocity as a vector v in terms of i and j. 25lbs
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Find the magnitude , to the nearest hundredth and the direction angle θ, to the nearest tenth of a degree . 10 6
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Find the magnitude , to the nearest hundredth and the direction angle θ, to the nearest tenth of a degree . 7 -2
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Find the magnitude , to the nearest hundredth and the direction angle θ, to the nearest tenth of a degree . 5 -10
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Unit Vector : A vector whose magnitude is one.
In many applications of vectors it is helpful to find to find the unit vector with the same direction as a given vector. 1 3 The unit vector for w
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5 4 3 Find the unit vector having the same direction as vector v. 5/5
4/5 3 3/5
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Find the unit vector having the same direction as vector v.
4 -2
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Find the unit vector having the same direction as vector v.
1 -3
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P – 45 odd, 47 – 50, 61-63,65,66
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Airspeed Vector + Windspeed Vector = Groundspeed Vector
Compass Heading True Bearingg Airspeed vector Airspeed – Speed relative to the air or speed if there was no wind. Compass Heading – The direction the plane would travel if there was no wind or the direction the engine is pushing the plane. This is the direction of the airspeed vector. Groundspeed – The speed of the plane relative to the ground or the speed of the plane with the wind. True Bearing or True Course – The direction the plane flies with the wind pushing it or the direction relative to the ground. This is the direction of the groundspeed vector. Wind Speed – Speed of the wind.
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Directions and Bearings
The direction to a point is stated as the number of degrees east or west of north or south. For example, the direction of A from O is N30ºE. B is N60ºW from O. C is S70ºE from O. D is S80ºW from O. Note: N30ºE means the direction is 30º east of north.
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N E W S N E W S N E W S N E W S
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Two forces F1 and F2, of magnitude 10 and 30 pounds respectively, act on an object. The direction of F1 is N20°E and the direction of F2 is N65°E. Find the magnitude and direction of the resultant force. 20° 10lbs 70° 20° 65° 30lbs 65° 25° 20° 65°
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Two forces F1 and F2, of magnitude 10 and 30 pounds respectively, act on an object. The direction of F1 is N20°E and the direction of F2 is N65°E. Find the magnitude and direction of the resultant force. 20° 65° 37.74 22.08 37.74 lbs. 30.61
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Two F1 and F2 forces, of magnitude 30 and 60 pounds respectively, act on an object. The direction of F1 is N10°E and the direction of F2 is N60°E. Find the magnitude and direction of the resultant force. 10° 30lbs 80° 10° 60° 60lbs 60° 30° 10° 60°
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Two F1 and F2 forces, of magnitude 30 and 60 pounds respectively, act on an object. The direction of F1 is N10°E and the direction of F2 is N60°E. Find the magnitude and direction of the resultant force. 82.54 59.54 51.96 82.54 lbs.
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A pilot whose plane can maintain an airspeed of 350 miles/hr sets the compass at N 15° E and is blown off course by a 90 mph wind blowing due east . What is the groundspeed and the true bearing of the plane. 15° 350 mph 75° 90 350 mph 15°
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Angle with the positive x-axis 61.89°
A pilot whose plane can maintain an airspeed of 350 miles/hr sets the compass at N 15° E and is blown off course by a 90 mph wind blowing due east . What is the groundspeed and the true bearing of the plane. 383.28 350 mph 338.07 15° 180.59 Groundspeed: mph Angle with the positive x-axis 61.89° The groundspeed of the plane is mph and the true bearing is N28°E.
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A boat whose speed in still water is 20 mph is traveling across a river perpendicular to the 5 mph current. What is the actual speed the boat is traveling and at what angle is the boat blown off course. 5 mph 20 mph 20.62 The actual speed of the boat is mph and it is blown off course at an angle of 14°
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P – 74, 83, 84
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Wkst
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An airplane pilot with an airspeed of 400 miles/hour orients her plane due Southwest
(45 degrees South of West). The plane encounters a 100 mile/hour wind blowing towards the east. Determine the groundspeed and the true bearing of the plane. 225° 45° 400 mph 100 225° 45° 400 mph 100
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Angle with positive x-axis = 237.12°
An airplane pilot with an airspeed of 400 miles/hour orients her plane due Southwest (45 degrees South of West). The plane encounters a 100 mile/hour wind blowing towards the east. Determine the groundspeed and the true bearing of the plane. 225° 237.12° 45° 32.88° 400 mph 336.79 100 Groundspeed: mph Angle with positive x-axis = ° The groundspeed of the plane is mph the true bearing of the plane is S33°W
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