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Factor Theorem
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C2: Algebra Factor theorem
KUS objectives BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem Starter: Expand
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Consider the function f(x) = x2 + 3x - 10 Factorise it:
BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem Introduction: Consider the function f(x) = x2 + 3x - 10 Factorise it: Then: You can now sketch the graph of f(x). The Factor Theorem states that if f(a) = 0 for a polynomial f(x) then (x – a) is a factor of the polynomial f(x). f(x) = (x + 5)(x – 2) f(-5) = 0 and f(2) = 0
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Notes 1 If f(p) = 0, then (x – p) is a factor of f(x) f(x) A function of x, any equation f(p) The function of x with a value p substituted in For example; Show that (x – 2) is a factor of x3 + x2 – 4x - 4 x3 + x2 – 4x - 4 Substitute in x = 2 – (4x2) - 4 Work out each term – = 0 So because f(2) = 0, (x – 2) is a factor of the original equation
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(x – 3) is a factor of 𝑓 𝑥 = 𝑥 3 −3 𝑥 2 −9𝑥+27
Notes 2 The Factor Theorem states that if f(a) = 0 for a polynomial f(x) then (x – a) is a factor of the polynomial f(x). for example (x – 3) is a factor of 𝑓 𝑥 = 𝑥 3 −3 𝑥 2 −9𝑥+27 𝑓 3 = (3) 3 − − =0 Since 𝑥 3 −3 𝑥 2 −9𝑥+27= 𝑥−3 𝑥 2 −9 When x = 3 the bracket = 0 so f(x) = 0
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WB 6a If f(p) = 0, then (x – p) is a factor of f(x) f(x) A function of x, any equation f(p) The function of x with a value p substituted in For example; Factorise 2x3 + x2 – 18x - 9 2x3 + x2 – 18x - 9 Substitute in values of x to find a factor x = 1 – = -24 x = 2 – = -25 x = 3 – So (x – 3) is a factor = 0
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If f(p) = 0, then (x – p) is a factor of f(x)
WB 6b If f(p) = 0, then (x – p) is a factor of f(x) f(x) A function of x, any equation f(p) The function of x with a value p substituted in For example; Factorise 2x3 + x2 – 18x – 9 Now we know (x – 3) is a factor, divide by it to find the quotient The quotient is 2x2 + 7x + 3 2x2 + 7x + 3 x - 3 2x x2 – 18x - 9 2x3 – 6x2 7x2 – 18x - 9 Third, divide 3x by x = 3 Then, work out 3(x – 3) and subtract from what you have left Second, divide 7x2 by x = 7x Then, work out 7x(x – 3) and subtract from what you have left First, divide 2x3 by x = 2x2 Then, work out 2x2(x – 3) and subtract from what you started with 7x2 – 21x 3x - 9 3x - 9
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If f(p) = 0, then (x – p) is a factor of f(x)
WB 6c If f(p) = 0, then (x – p) is a factor of f(x) f(x) A function of x, any equation f(p) The function of x with a value p substituted in For example; Factorise 2x3 + x2 – 18x – 9 given that f(3) = 0 (x – 3) is a factor (2x2 + 7x + 3) is the quotient (x – 3)(2x2 + 7x + 3) You can also factorise the quotient 2 numbers that multiply to give +3, and add to give +7 when one has doubled… (x – 3)(2x + 1)(x + 3)
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b) Find a given that (𝑥−2) is a factor of 𝑥 3 + 𝑎𝑥 2 – 4𝑥+6.
BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem WB 7 a) Given that (x + 1) is a factor of 4x4 – 3x2 + a, find the value of a. 4x4 – 3x2 + a If (x + 1) is a factor, then using -1 will make the equation = 0 0 = 4(-14) – 3(-12) + a 0 = 4 – a Work out each term 0 = a Solve the equation to find the value of a -1 = a b) Find a given that (𝑥−2) is a factor of 𝑥 3 + 𝑎𝑥 2 – 4𝑥+6. (2)3 + a(2)2 - 4(2) + 6 = 0 4a + 6 = 0 𝒂 =− 𝟑 𝟐
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So 𝑥 3 −2 𝑥 2 −8𝑥=(𝑥+2)( 𝑥 2 −4𝑥) 𝑥 2 −4𝑥 𝑥 +2 𝑥 3 −4𝑥 2 +2𝑥 2 −8𝑥
Algebra division: Divide by a bracket using table of values Divided by 𝑥 2 −4𝑥 𝑥 +2 𝑥 3 −4𝑥 2 +2𝑥 2 −8𝑥 𝑟𝑒𝑚𝑎𝑖𝑛𝑑𝑒𝑟 0 Use EWB pen to complete the example So 𝑥 3 −2 𝑥 2 −8𝑥=(𝑥+2)( 𝑥 2 −4𝑥)
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So 𝑥 3 +9 𝑥 2 +26𝑥+24=(𝑥+3)( 𝑥 2 +6𝑥+8) 𝑥 2 +6𝑥 +8 𝑥 +3 𝑥 3 +6𝑥 2 +8𝑥
Algebra division: Divide by a bracket using table of values Divided by 𝑥 2 +6𝑥 +8 𝑥 +3 𝑥 3 +6𝑥 2 +8𝑥 +3𝑥 2 +18𝑥 +24 𝑟𝑒𝑚𝑎𝑖𝑛𝑑𝑒𝑟 0 Use EWB pen to complete the example So 𝑥 3 +9 𝑥 2 +26𝑥+24=(𝑥+3)( 𝑥 2 +6𝑥+8)
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1. Show that (x – 2) is a factor of x3 - 4x2 + x + 6.
BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem Practice 1 1. Show that (x – 2) is a factor of x3 - 4x2 + x + 6. Hence factorise the expression completely. 2. Factorise the expression x3 - 3x2 - 10x + 24. Hence solve the equation x3 - 3x2 - 10x + 24 = 0. 3. If (x – 2) is a factor of f(x) = x3 - 3x2 + a, find the value of a. 4. Determine whether or not (x – 3) is a factor of the expression, x3 - 6x2 + 5x + 12.
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Use the factor theorem to show that the following are factors, and hence fully factorise
Practice 2 easy harder is a factor of is a factor of is a factor of is a factor of is a factor of is a factor of is a factor of is a factor of is a factor of is a factor of
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Check your answer using Geogebra
BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem WB 8 Factorise the cubic polynomial f(x) = x3 – 2x2 – x + 2 and hence sketch the graph of the function. Check your answer using Geogebra
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Check your answer using Geogebra
BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem WB 9 Express f(x) = x3 + x2 – 5x + 3 as the product of three linear factors. Hence: a) Sketch the graph of the function. b) Solve the equation x3 + x2 – 5x + 3 = 0 Check your answer using Geogebra
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Check your answer using Geogebra
BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem WB 10: Factorise the cubic polynomial f(x) = x3 + 3x2 – 12x – 14 Hence: a) Sketch the graph of the function. b) Solve f(x) = 0 Check your answer using Geogebra
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The polynomial 𝑝(𝑥)is given by 𝑝 𝑥 = 𝑥 3 −19𝑥−30
BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem WB11 exam question The polynomial 𝑝(𝑥)is given by 𝑝 𝑥 = 𝑥 3 −19𝑥−30 Use the factor theorem to show that 𝑥+2 is a factor of 𝑝(𝑥) Express 𝑝 𝑥 as the product of three linear factors
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factor theorem challenge
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One thing to improve is –
KUS objectives BAT perform algebraic long division BAT factorise cubic functions and other expressions BAT recall and use the Factor Theorem self-assess One thing learned is – One thing to improve is –
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