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Final Jeopardy Question
Exp. Equations Log Equations INV Equations Graphs 500 500 500 600 500 400 400 400 400 300 300 300 300 200 200 200 200 100 100 100 100 Final Jeopardy Question
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Category 1 500 pts No Calculator Solve Back
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Category 1 400 pts No Calculator Solve X=5/6 Back
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Category 1 300 pts No Calculator Solve e(x-3) = 35 X=ln(35) + 3 Back
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X=log(2848)/(4log5) No Calculator Solve 5(4x) = 2848 Category 1
200 pts No Calculator Solve 5(4x) = 2848 X=log(2848)/(4log5) Back
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Category 1 100 pts No Calculator Solve 16(3x +1) = 64 X=1/6 Back
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Find the exact solution
Category 2 500 pts Find the exact solution ln(3-x) - ln(2-x) = 1 X=(2e-3)/(e-1) Back
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Category 2 400 pts Solve without calc. log(8+x) = log(4-x) X=1 Back
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Category 2 300 pts Solve ln(1-3x) =5 X=(e5 - 1)/-3 Back
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Category 2 200 pts Solve ln6 5x = 3000 X=600/(ln6) Back
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log(x + 6)-log(x)=log(x + 2)
Category 2 100 pts Solve: log(x + 6)-log(x)=log(x + 2) X=2 Back
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Is h(x) one-to-one? Verify algebraically.
Category 3 500 pts Is h(x) one-to-one? Verify algebraically. Back
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Find the inverse of f(x), f(x) = 16(3x +1) +1
Category 3 400 pts Find the inverse of f(x), f(x) = 16(3x +1) +1 Back
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Category 3 300 pts Find the domain of Back
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Category 3 200 pts Find g-1(x) if g(x) = log(4-x) Back
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Find the inverse of h(x)
Category 3 100 pts Find the inverse of h(x) Back
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Category 4 500 pts No Calculator Solve 5(3x +1) = 64(6-x) Back
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Category 4 400 pts No Calculator Solve 5(x) = 64(6-x) Back
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Y=(2^(x-1) - 4)/-3 Find the inverse of j(x) = log2(4 - 3x) + 1
Category 4 300 pts Find the inverse of j(x) = log2(4 - 3x) + 1 Y=(2^(x-1) - 4)/-3 Back
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State the domain, range, any asymptotes, and the transformations of
Category 4 200 pts State the domain, range, any asymptotes, and the transformations of j(x) = log2(4 - 3x) compared to k(x) = log2(x) ANSWER Back
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(1,1) and (2,2) Name two points on k(x) = log2(x) + 1 Category 4
100 pts Name two points on k(x) = log2(x) + 1 (1,1) and (2,2) Back
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g(x) = 4(x + 1) - 2 compared to f(x) = 4x
Category 5 500 pts State the domain, range, two points, any asymptotes, and the transformations of g(x) = 4(x + 1) - 2 compared to f(x) = 4x ANSWER Back
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g-1(x) = log4(x+2) - 1 State the inverse function of
Category 5 400 pts State the inverse function of g(x) = 4(x + 1) - 2 g-1(x) = log4(x+2) - 1 Back
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Category 5 300 pts k(x) = bx, write the function t(x) that is reflected over the x-axis, horizontally shifted left five units and vertically shifted up two units. Y=-b(x+5) + 2 Back
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k(x) = bx, name two points on the graph.
Category 5 200 pts k(x) = bx, name two points on the graph. (0,1) and (1,b) Back
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k(x) = bx, how do you know that it is increasing or decreasing?
Category 5 100 pts k(x) = bx, how do you know that it is increasing or decreasing? If b>1, the graph increases If 0<b<1, then decreases Back
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Review: pp. 363-65 # 1,4,65,67,69,71,72,74, 75, & if needed 43-61 odd
Final Jeopardy Review: pp # 1,4,65,67,69,71,72,74, 75, & if needed odd Back
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Category 1 100 pts No Calculator Solve 16(3x +1) = 64 Back
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Category 1 200 pts No Calculator Solve 5(4x) = 2848 Back
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Category 1 300 pts No Calculator Solve e(x-3) = 35 Back
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Category 1 400 pts No Calculator Solve Back
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Category 1 500 pts No Calculator Solve Back
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log(x + 6)-log(x)=log(x + 2)
Category 2 100 pts Solve: log(x + 6)-log(x)=log(x + 2) Back
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Category 2 200 pts Solve ln6 5x = 3000 Back
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Category 2 300 pts Solve ln(1-3x) =5 Back
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Category 2 400 pts Solve without calc. log(8+x) = log(4-x) Back
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Find the exact solution
Category 2 500 pts Find the exact solution ln(3-x) - ln(2-x) = 1 Back
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Category 3 100 pts If I invest $3000 dollars at 6.8% for 20 years with interest compounded monthly, how much money will I have? Back
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Category 3 200 pts If I invest $3000 dollars for 35 years and end up with $60,000, what was my annual interest rate? Back
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Category 3 300 pts If I invest $3000 dollars for 35 years and end up with $60,000, but received interest quarterly. What was my interest rate? Back
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Category 3 400 pts The half life of carbon-14 is 5750 years. Ivory was found to have lost 35% of its carbon-14. How old was the ivory? Back
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Category 3 500 pts In 1985, the average consumption of beef was 80lbs per person. In 1996 it was 67 lbs. If exponential, when will it be 50lbs? Back
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Category 4 100 pts Name two points on k(x) = log2(x) + 1 Back
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State the domain, range, any asymptotes, and the transformations of
Category 4 200 pts State the domain, range, any asymptotes, and the transformations of j(x) = log2(4 - 3x) compared to k(x) = log2(x) Back
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Category 4 300 pts Find the inverse of j(x) = log2(4 - 3x) + 1 Back
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Category 4 400 pts Name two points on j(x) = log2(4 - 3x) + 1 Back
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Category 4 500 pts If f(x) = log(x), f(a) = 3n, f(b) = n, then the ratio of a:b is _______. Back
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k(x) = bx, how do you know that it is increasing or decreasing?
Category 5 100 pts k(x) = bx, how do you know that it is increasing or decreasing? Back
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k(x) = 7x, name two points on the graph.
Category 5 200 pts k(x) = 7x, name two points on the graph. Back
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j(x) = 7x +4 - 8, how does compare to j(x) = 7x?
Category 5 300 pts j(x) = 7x , how does compare to j(x) = 7x? Back
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Category 5 400 pts Find the inverse of j(x) = 7x +4 – 8. Back
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Verify j(x) is one to one algebraically.
Category 5 500 pts Verify j(x) is one to one algebraically. j(x) = 7x +4 – 8. Back
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Optional Review: pp. 337-340 # 1-6,21,33-41 odd, 67-71 odd, 83,
Final Jeopardy Optional Review: pp # 1-6,21,33-41 odd, odd, 83, Back
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Horizontal Asymptote y = -2 Shifts left one unit and down two units.
Category 5 500 pts D: (-,) R: (-2, ) Horizontal Asymptote y = -2 Shifts left one unit and down two units. Back
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j(x) = log2(4 - 3x) + 1 j(x) = log2[-3(x-4/3)] +1
Category 4 400 pts Back j(x) = log2(4 - 3x) + 1 j(x) = log2[-3(x-4/3)] +1 (1,0) and (2,1) are on y=log2x (-1,0) & (-2,1) due to the “-” (-1/3,0) & (-2/3,1) due to the “3” (1,0) & (2/3,1) due to the “4/3” (1,1) & (2/3,2) due to the “1”
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j(x) = log2(4 - 3x) + 1 j(x) = log2[-3(x-4/3)] +1
Category 4 200 pts Back j(x) = log2(4 - 3x) + 1 j(x) = log2[-3(x-4/3)] +1 the “-” reflects the graph over the y-axis, the “3” compresses the graph horizontally by a factor of 3, shifts right 4/3 and up one unit.
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Exponential Equations
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Logarithmic Equations
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Inverses $100_________________________________________ $200_________________________________________ $300_________________________________________ $400_________________________________________ $500_________________________________________
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Equation $600_________________________________________
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graphs $100_________________________________________ $200_________________________________________ $300_________________________________________ $400_________________________________________ $500_________________________________________
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