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Appendix A7 Complex Numbers

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1 Appendix A7 Complex Numbers
Honors Pre-Calculus Appendix A7 Complex Numbers

2 Objectives Add, Subtract, Multiply, and Divide Complex Numbers
Graph Complex Numbers Solve Quadratic Equations in the Complex Number System

3 Complex Numbers

4 Complex Numbers ๐‘ฅ 2 =โˆ’1 does not have any real solutions because when any number is multiplied by itself we get a positive number To remedy this situation we can introduce a number, called the imaginary unit, which we will denote by ๐’Š, whose square is -1; that is, ๐’Š ๐Ÿ =โˆ’๐Ÿ

5 Complex Numbers Complex numbers are numbers of the form ๐’‚+๐’ƒ๐’Š where ๐’‚ and ๐’ƒ are real numbers. The real number ๐’‚ is called the real part of the number ๐’‚+๐’ƒ๐’Š; the real number ๐’ƒ is called the imaginary part of ๐’‚+๐’ƒ๐’Š. Examples: ๐Ÿ‘+๐Ÿ๐’Š 3 is the real part, 2 is the imaginary part. ๐Ÿ•.๐Ÿ+๐…๐’Š 7.2 is the real part, ๐œ‹ is the imaginary part.

6 Comparing, Adding and Subtracting Complex Numbers
We can only compare complex numbers in terms of equality. ๐‘Ž+๐‘๐‘–=๐‘+๐‘‘๐‘– is true if and only if ๐‘Ž=๐‘, and ๐‘=๐‘‘ Sum of Complex Numbers ๐‘Ž+๐‘๐‘– + ๐‘+๐‘‘๐‘– = ๐‘Ž+๐‘ + ๐‘+๐‘‘ ๐‘– Difference of Complex Numbers ๐‘Ž+๐‘๐‘– โˆ’ ๐‘+๐‘‘๐‘– = ๐‘Žโˆ’๐‘ + ๐‘โˆ’๐‘‘ ๐‘–

7 Comparing, Adding and Subtracting Complex Numbers
If 7+๐‘ฅ๐‘–=๐‘ฆ+2๐‘– then ๐‘ฆ=7, and ๐‘ฅ=2 If 3๐‘ฅ+4๐‘–=12+2๐‘ฆ๐‘– then: ๐‘ฅ=4, ๐‘ฆ=2 Adding 3+2๐‘– + 4+3๐‘– =7+5๐‘– 2+5๐‘– +(4+2๐‘–) =6+7๐‘–

8 Comparing, Adding and Subtracting Complex Number (continued)
3+5๐‘– โˆ’(2+2๐‘–) (1+3๐‘–) 2+5๐‘– โˆ’ 1+5๐‘– 1 2+4๐‘– โˆ’ 2โˆ’2๐‘– 6๐‘–

9 Multiplying Complex Numbers
๐‘Ž+๐‘๐‘– ๐‘+๐‘‘๐‘– = ๐‘Ž๐‘โˆ’๐‘๐‘‘ + ๐‘Ž๐‘‘+๐‘๐‘ ๐‘– Proof: ๐‘Ž+๐‘๐‘– ๐‘+๐‘‘๐‘– =๐‘Ž ๐‘+๐‘‘๐‘– +๐‘๐‘–(๐‘+๐‘‘๐‘–) =๐‘Ž๐‘+๐‘Ž๐‘‘๐‘–+๐‘๐‘๐‘–+๐‘๐‘‘ ๐‘– 2 =๐‘Ž๐‘+๐‘๐‘‘ โˆ’1 + ๐‘Ž๐‘‘+๐‘๐‘ ๐‘– = ๐‘Ž๐‘โˆ’๐‘๐‘‘ + ๐‘Ž๐‘‘+๐‘๐‘ ๐‘–

10 Multiplying Complex Numbers (continued)
Examples: 5+2๐‘– 2+3๐‘– 10+15๐‘–+4๐‘–+6 ๐‘– 2 =4+19๐‘– (5โˆ’2๐‘–)(2+3๐‘–) 10+15๐‘–โˆ’4๐‘–โˆ’6 ๐‘– 2 =16+11๐‘– 2+๐‘– 3+2๐‘– 6+4๐‘–+3๐‘–+2 ๐‘– 2 =4+7๐‘– 2+3๐‘– 2โˆ’3๐‘– 4โˆ’6๐‘–+6๐‘–โˆ’9 ๐‘– 2 =4+9=13

11 Complex Conjugate If ๐’›=๐’‚+๐’ƒ๐’Š is a complex number, then its conjugate, denoted by ๐‘ง is defined as ๐’› =๐’‚โˆ’๐’ƒ๐’Š The product of a complex number and its conjugate is a nonnegative number. That is, if ๐’›=๐’‚+๐’ƒ๐’Š, then ๐’› ๐’› = ๐’‚+๐’ƒ๐’Š ๐’‚โˆ’๐’ƒ๐’Š = ๐’‚ ๐Ÿ + ๐’ƒ ๐Ÿ

12 Complex Conjugate (continued)
Examples: If ๐’›=๐Ÿ+๐Ÿ‘๐’Š its complex conjugate is ๐’› =๐Ÿโˆ’๐Ÿ‘๐’Š ๐’› ๐’› = ๐Ÿ+๐Ÿ‘๐’Š ๐Ÿโˆ’๐Ÿ‘๐’Š = ๐Ÿ ๐Ÿ + ๐Ÿ‘ ๐Ÿ =๐Ÿ๐Ÿ‘ If ๐’›=๐Ÿโˆ’๐Ÿ๐’Š its complex conjugate is ๐’› =๐Ÿ+๐Ÿ๐’Š ๐’› ๐’› = ๐Ÿโˆ’๐Ÿ๐’Š ๐Ÿ+๐Ÿ๐’Š = ๐Ÿ ๐Ÿ + ๐Ÿ ๐Ÿ =๐Ÿ“ If ๐’›=๐Ÿโˆ’๐’Š its complex conjugate is ๐’› =๐Ÿ+๐’Š ๐’› ๐’› = ๐Ÿโˆ’๐’Š ๐Ÿ+๐’Š = ๐Ÿ ๐Ÿ + ๐Ÿ ๐Ÿ =๐Ÿ“

13 Properties of Conjugates
( ๐‘ง) =๐‘ง ๐‘ง+๐‘ค = ๐‘ง + ๐‘ค ๐‘งโˆ™๐‘ค = ๐‘ง โˆ™ ๐‘ค

14 Writing the Reciprocal of a Complex Number
1 2+3๐‘– 1 2+3๐‘– โˆ™ 2โˆ’3๐‘– 2โˆ’3๐‘– = 1(2โˆ’3๐‘–) (2+3๐‘–)(2โˆ’3๐‘–) = 2โˆ’3๐‘– 4+9 = 2 13 โˆ’ 3 13 ๐‘– 1 4โˆ’5๐‘– 1 4โˆ’5๐‘– 4+5๐‘– 4+5๐‘– = 4+5๐‘– = ๐‘–

15 Writing the Quotient of a Complex Number
3+2๐‘– 2+3๐‘– 3+2๐‘– 2+3๐‘– โˆ™ 2โˆ’3๐‘– 2โˆ’3๐‘– = 6+4๐‘–โˆ’9๐‘– = 12โˆ’5๐‘– 13 = โˆ’ 5 13 ๐‘–

16 Writing the Quotient of a Complex Number
2+3๐‘– 4โˆ’5๐‘– (2+3๐‘–) (4โˆ’5๐‘–) (4+5๐‘–) (4+5๐‘–) = 8+12๐‘–+10๐‘–โˆ’ = โˆ’7+22๐‘– 41 =โˆ’ ๐‘–

17 Powers of ๐‘–

18 Evaluating Powers of ๐‘– ๐‘– 37 = ๐‘– 36 โˆ™๐‘–= ๐‘– 4 9 โˆ™๐‘–= 1 9 โˆ™๐‘–=๐‘– ๐‘– 111 = ( ๐‘– 4 ) 108 โˆ™ ๐‘– 3 = โˆ™ ๐‘– 2 โˆ™๐‘–=โˆ’๐‘– ๐‘– 23 = ( ๐‘– 2 ) 11 โˆ™๐‘–= โˆ’1 11 โˆ™๐‘–=โˆ’๐‘–

19 Evaluating Powers of a Complex Number
(2+3๐‘–) 3 (๐‘ฅ+๐‘Ž) 3 = ๐‘ฅ 3 +3๐‘Ž ๐‘ฅ 2 +3 ๐‘Ž 2 ๐‘ฅ+ ๐‘Ž 3 (2+3๐‘–) 3 = ๐‘– ๐‘– 2 2+ (3๐‘–) 3 =8+36๐‘–โˆ’54+27 โˆ’๐‘– =โˆ’46+9๐‘– (3+2๐‘–) 2 (๐‘ฅ+๐‘Ž) 2 = ๐‘ฅ 2 +2๐‘Ž๐‘ฅ+ ๐‘Ž 2 (3+2๐‘–) 2 = โˆ™2๐‘–โˆ™3+ (2๐‘–) 2 =9+12๐‘–โˆ’4=5+12๐‘–

20 Homework Pg A


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