1. Chapter 7
Politeknik Telkom 2008

2. Device of Wireless Network
PCMCIA
Radio device

3. Vendor D-Link

4. Vendor 3com

5. Vendor
Belkin
Linksys
Broadcom

6. PoE
Power over Ethernet (PoE) is mekanism to supply power through network device, ex : switch, hub

7. PoE

8. Class of power

9. Device vs Power Requirement

10. Class of power

11. Type of Antenna
Omnidirectional
Directional / Sectoral

12. Omnidirectional Antenna

13. Sectoral Antenna

14. Lobe Lobe is radiation pattern in an antenna
Lobe for omnidirectional antenna
Horisontal lobe
Vertical lobe

15. Lobe sectoral / directional
horisontal
vertical
Directional

16. Angle

17. Angle Parameter : Hb = height of base station (meter)
Hr = height of receiver (meter)
A = angle of antenna (degree)
Distance (km)

18. Exercise 1
A base station has height 30 meter from the ground and receiver has height 10 meter. Distance between base station to receiver are 3 km.
Find angle of antenna in the base station ?

19. Anwer exercise 1 A = tan-1 [(Hb-Hr)/(distancex5280)]
= tan-1 [(30-10)/(3x5280]
= tan-1 [20/15840]
= 0,072°

20. Radius

21. Radius Parameter : H = height of antenna (meter)
A = tilt angle of antenna
BW = width of beam

22. Exercise 2
A base station has height 30 meter, with beamwitdh = 10°, A=0,2°
Find :
Inner radius distance ?
Outer radius distance ?

23. Answer exercise 2 = [30/Tan(0,2+(10/2))]/5280 = [30/Tan(5,2)]/5280
= [30/0,09]/5280
= 0,063 km
= 63 meter

24. Answer exercise 2 = [30/Tan(0,2+(10/2))]/5280 = [30/Tan(-4,8)]/5280
= [30/0,09]/5280
= 0,063 km
= 63 meter

25. Attenuation Loss/gain vs power (Loss) -3 dB = - ½ x power
(Gain) +3 dB = 2 x power (double power)
(gain) +6 dB = 4 x power (increasing power 4x)

26. Attenuation type obstacle vs loss Additional Loss (dB) Obstruction
Open space
Window (nonmetallic tint) 3
Window (metallic tint)
5 – 8
Light wall (drywall)
Medium wall (wood) 10
Heavy wall (15 cm solid core)
15 – 20
Very heavy wall (30 cm solid core)
20 – 25
Floor/ceiling (solid core)
Floor/ceiling (heavy solid core)

27. Attenuation

28. Exercise 3
Hb =100 meter, hm=5 meter, and lamda=1.116 meter, distance between transmitter and receiver 5000 meter. Assume gain antenna 8 dB and 0 dB for Access Point and receiver.
Find :
A. Free space attenuation
B. Reflection attenuation

29. Answer exercise 3 Gb  8 dB = 10 log Gb Gb = 6,3 Gm  0 dB = 10 log Gm

30. Answer exercise 3