1. Scalars
A scalar is any physical quantity that can be completely characterized by its magnitude (by a number value)
Mathematical operations involving scalars – follow rules of elementary algebra
In text represented with letters in italic type
Examples: mass, volume, length

2. Vectors Possess a magnitude, direction, and sense
Represented graphically by an arrow (tail, tip or head) SHOW
Magnitude: proportional to the length of arrow
Direction: defined by angle between reference axis and line of action of the arrow
Sense: indicated by the arrowhead
In text, vector symbolized by boldface type, A, and its magnitude (always positive) by |A | or simply A
In slides, vector symbolized by boldface type, A, and magnitude by regular type, A
In handwritten work, vector represented by letter with an arrow over it, its magnitude by letter enclosed in absolute value symbol or by letter itself SHOW
Obey parallelogram law of addition
Examples: position, force, moment

3. Multiplication and division of a vector by a scalar
Product of a vector, A, and a scalar, a
Vector, aA
Magnitude, aA
Sense of aA is the same as A provided a is positive, it is opposite to A if a is negative
Division can be converted to multiplication and then laws of multiplication applied, A/a = (1/a) A, a≠0
Product is associative with respect to scalar multiplication
a(bA) = (ab)A
Product is distributive with respect to scalar addition
(a + b)A = aA + bA
Product is distributive with respect to vector addition
a(A + B) = aA + aB

4. Vector addition Parallelogram law SHOW
Join the tails
Draw parallel dashed lines from the head of each vector to the intersection at a common point
Resultant, R, is the diagonal of the parallelogram (extends from the tails of the two vectors to the intersection of the dashed lines)
Special case – two vectors collinear – parallelogram law reduces to an algebraic or scalar addition, R = A + B
Triangular construction (head-to-tail fashion) SHOW
Adding B to A
Connect the tail of vector B to the head of vector A
Resultant, R, extends from the tail of vector A to the head of vector B
Vector addition is commutative, A + B = B + A
Vector addition is associative, (A + B) + D = A + (B + D)

5. Vector subtraction Difference between two vectors A and B SHOW
Subtraction defined as a special case of addition
R’ = A – B = A + (-B) = A + (-1)B
SHOW

6. Resolution of a vector
Vector may be resolved into two “components” having known lines of action by using the parallelogram law
SHOW
Starting at the head of R, extend dashed line parallel to a until it intersects b, likewise dashed line parallel to b until it intersects a
Two components A and B are then drawn such that they extend from the tail of R to the points of intersection
R is resolved into the vector components A and B

7. Problems in Statics involving force (a vector quantity)
Find the resultant force, knowing its components
Resolve a known force into its components

8. Procedure for analysis – addition of forces
Apply parallelogram law
Sketch vector addition using parallelogram law
Determine interior angles from geometry of the problem (recall sum total of interior angles of parallelogram = 360°)
Label known angles and known forces
Redraw half portion of constructed parallelogram to show triangular head-to-tail addition components
Unknowns can be determined from known data on triangle and use of trigonometry
If no 90° angle, law of sines and/or law of cosines may be used SHOW
EXAMPLES (pgs 29-32)

9. Vector components parallel to x and y axes (Cartesian components)
F can be resolved into its vector components Fx and Fy parallel to the x and y axes, F = Fx + Fy
Unit vectors i and j designate directions along the x and y axes
i and j vectors have a dimensionless magnitude of unity
Their direction will be described analytically by a “+” or “-” depending on whether they are pointing along the positive or negative x or y axis
SHOW
F = Fxi + Fyj (Cartesian vector form)
F’ = F’x(-i) + F’y(-j) = - F’x(i) - F’y(j)
The magnitude of each component of F is always a positive quantity, represented by the scalars Fx and Fy
The magnitude of F is given in terms of its components by the Pythagorean theorem,
The direction angle θ, which specifies the orientation of the force, is determined from trigonometry,
From this point forward i and j will simply be written in regular type since by definition they are vectors

10. Addition of vectors in terms of their (Cartesian) components
F1 = (F1xi + F1yj), F2 = (F2xi + F2yj), F3 = (F3xi + F3yj)
FR = F1 + F2 + F3
FR = (F1xi + F1yj) + (F2xi + F2yj) + (F3xi + F3yj)
FR = F1xi + F2xi + F3xi + F1yj + F2yj + F3yj
FR = (F1x + F2x + F3x) i + (F1y + F2y + F3y) j
FR = FRxi + FRyj
FRx = F1x + F2x + F3x or FRx = ∑ Fx
FRy = F1y + F2y + F3y or FRy = ∑ Fy
EXAMPLES (pgs 40-43)

11. Rectangular components of a 3-D vector
Assume right-handed coordinate system
A = Ax + Ay + Az SHOW
Cartesian vector notation, A = Axi + Ayj + Azk
Magnitude of Cartesian vector
A = (Ax2 + Ay2 + Az2)1/2
SHOW
Direction of Cartesian vector
cos α = Ax/A, cos β = Ay/A, cos γ = Az/A

12. Unit vector Unit vector has a magnitude of 1 and specifies a direction
If a unit vector uA and a vector A have the same direction → A can be written as the product of its magnitude A and the unit vector uA, A = A uA
uA (dimensionless) defines the direction and sense of A
A (has dimensions) defines the magnitude of A
A unit vector having the same direction as A is represented by uA = A/A

13. Using the unit vector to obtain the direction cosines
A unit vector in the direction of A (A = Axi + Ayj + Azk)
uA = A/A = Ax/A i + Ay/A j + Az/A k
uA = A/A = uAxi + uAyj + uAzk
(Ax/A = uAx = cos α, Ay/A = uAy = cos β, Az/A = uAz = cos γ)
uA = A/A = cos α i + cos β j + cos γ k
(uA has a magnitude 1 and recalling that A = (Ax2 + Ay2 + Az2)1/2)
1 = (cos 2 α + cos2 β + cos2 γ)1/2
Squaring both sides
1 = cos 2 α + cos2 β + cos2 γ
Equation can be used to determine one of the coordinate direction angles if the other two are known

14. Addition and subtraction of 3-D Cartesian vectors
A = (Axi + Ayj + AZk), B = (Bxi + Byj + BZk)
R = A + B = (Ax + Bx) i + (Ay + By) j + (Az + Bz) k
R’ = A - B = (Ax - Bx) i + (Ay - By) j + (Az - Bz) k
FR = ∑ F = ∑ Fxi + ∑ Fyj + ∑ Fzk
EXAMPLES (pgs 52-55)

15. Position vector
If r extends from point A (xA, yA, zA) to point B (xB, yB, zB)
SHOW
rAB = (xB – xA) i + (yB – yA) j + (zB – zA) k
The i, j, k components of the position vector rAB may be formed by taking the coordinates at the head of the vector (point B, (xB, yB, zB)) and subtracting the corresponding coordinates of the tail of the vector (point A, (xA, yA, zA))

16. Force vector directed along a line
The direction of a force can be specified by two points through which its line of action passes
Formulate F in a Cartesian vector form, realizing it has the same direction as the position vector r directed from point A to point B (A and B are points on a cord along F)
F = Fu = F (r/r)
Procedure for analysis
Determine position vector r directed from A to B, and compute its magnitude r
Determine the unit vector u = r/r which defines the direction of both r and F
Determine F by combining its magnitude F and direction u
F = Fu
EXAMPLES (pgs 65-68)

17. Dot product Dot product of vectors A and B, A∙B, “A dot B”
A∙B = AB cos θ (where 0°≤θ≤180°), SHOW
The result is a scalar, not a vector
The dot product is also referred to as the scalar product of vectors
Applicable laws of operation
Commutative law: A∙B = B∙A
Multiplication by a scalar: a (A∙B) = (aA)∙B = A∙(aB) = (A∙B) a
Distributive law: A∙(B + D) = (A∙B) + (A∙D)
Cartesian vector formulation
i∙i = (1)(1) cos 0° = 1
i∙j = (1)(1) cos 90° = 0
i∙k = (1)(1) cos 90° = 0
Similarly, j∙j = 1, k∙k = 1, j∙k = 0

18. Dot product of two general vectors
A∙B = (Axi + Ayj + AZk)∙(Bxi + Byj + BZk)
= AxBx (i∙i) + AxBy (i∙j) + AxBZ (i∙k)
+ AyBx (j∙i) + AyBy (j∙j) + AyBz (j∙k)
+ AzBx (k∙i) + AzBy (k∙j) + AzBz (k∙k)
= AxBx + AyBy + AzBz

19. Applications of dot product
Determining the angle formed between two vectors or intersecting lines
(recall A∙B = AB cos θ)
θ = cos-1 (A∙B/AB), 0°≤θ≤180°
A∙B is computed from A∙B = AxBx + AyBy + AzBz
if A∙B = 0 → θ = 90° → A is perpendicular to B

20. Applications of dot product (continued)
Components of a vector parallel and perpendicular to a line (aa’)
SHOW
Parallel
For Ap (projection of A onto line aa’) → Ap = A cos θ
Direction of line specified by the unit vector u (u=1)
Ap = A cos θ = (A)(1) cos θ = A∙u [and Ap = (A∙u)(u)]
The scalar projection of A along a line is determined from the dot product of A and the unit vector u which defines the direction of the line
If Ap is positive, then Ap has a sense which is the same as u
If Ap is negative, then Ap has the opposite sense to u
Perpendicular
A = Ap + An → An = A - Ap
An → An = A sin θ, θ = cos-1 (A∙u/A)
Or by Pythagorean Theorem An = (A2 – Ap2)1/2
EXAMPLES (pg 76-80)