Presentation is loading. Please wait.

Presentation is loading. Please wait.

Chapter 22 Statistics.

Similar presentations


Presentation on theme: "Chapter 22 Statistics."— Presentation transcript:

1 Chapter 22 Statistics

2 Learning Unit Objectives
#22 Business Statistics Learning Unit Objectives LU22.1 Mean, Median, and Mode Define and calculate the mean Explain and calculate a weighted mean Define and calculate the median Define and identify the mode

3 Learning Unit Objectives
#22 Business Statistics Learning Unit Objectives LU22.2 Frequency Distributions and Graphs Prepare a frequency distribution Prepare bar, line, and circle graphs Calculate price relatives and cost comparisons

4 Learning Unit Objectives
#22 Business Statistics Learning Unit Objectives Measures of Dispersion (Optional Section) LU22.3 Explain and calculate the range Define and calculate the standard deviation Estimate percentage of data by using standard deviations

5 Terminology Median - A measurement that indicates the center of the data (Average) Mean - Average used to indicate a single value that represents an entire group of numbers Mode - a measurement that records values. The value that occurs most often

6 Mean Mean = Sum of all values Number of values
What is the mean of the following daily sales? Sun. Mon. Tues. Wed. Thur. Fri. Sat. $400 $100 $68 $115 $120 $68 $180 Mean = $400 + $100 + $68 + $115 + $120 +$68 + $180 = $150.14 7

7 Weighted Mean Weighted Mean = Sum of products Sum of frequencies
What is the weighted mean (GPA) for the student? Credit Grade Points Courses attempted received (Credits x Grade) Intro to Comp 4 A (4 x 4) Psychology B 9 (3 x 3) English Comp B (3 x 3) Business Law C (2 x 3) Business Math 3 B 9 (3 x 3) 49 = 3.1 16

8 Finding the Median of a Group of Values
Step 1. Orderly arrange values from the smallest to the largest Find the median age , 35, 87, 23, 50 Step 2. Find the middle value Odd number of values: Median is the middle value. Divide the total number of numbers by 2. (5/2 = 2 ½). The next-higher number is the median. B. Even number of values: Median is the average of the two middle values. 23, 35, 42, 50, 87 Find the median age , 35, 87, 50 35, 42, 50, 87 2 46

9 3 is the mode since it is listed 4 times
The value that occurs most often If two or more numbers appear most often, you may have two or more modes. If all the values are different, there is no mode 3 is the mode since it is listed 4 times 3, 4, 5, 6, 3, 8, 9, 3, 5, 3

10 Frequency Distribution
A way of collecting and organizing raw data Price of Tally Frequency Computer $1, llll 5 2, l 1 3, llll 5 4, l 1 5, ll 2 6, ll 2 7, l 1 8, l 1 9, l 1 10, l 1 Computer costs 1000 7000 4000 5000 3000 2000 8000 9000 6000 10000 Frequency distribution table

11 Bar Graph Frequency of purchase Price of Computers 2000 4000 6000 8000
10000 Price of Computers

12 Bar Graph Class Frequency $1000 - $ 3,000.99 11 $3001 - 5,000.99 3
$ $ 3, $ , $ , $ , $ , Frequency of purchase $3,001- $5,000.99 $7,001- $9,000.99

13 Average cost of College
Line Graph Average cost of College tuition Year

14 Circle Graph Revenues 1st Qtr. $20,400 2nd Qtr $27,400 3rd Qtr $90,000
12.9% 12.9% 17.3% 56.9% Revenues 1st Qtr. $20,400 2nd Qtr $27,400 3rd Qtr $90,000 4th Qtr $20,400

15 Find the range of the following values:
Measure of Dispersion Measure of Dispersion – a number that describes how the numbers of a set of data are spread out or dispersed. Range – The difference between the two extreme values (highest and lowest) in a group of values or a set of data. Range = Highest value – Lowest value Find the range of the following values: 83.6, 77.3, 69.2, 93.1, 85.4, 71.6 Range = 93.1 – 69.2 = 23.9

16 Index Numbers Price relative = Current price x 100 Base year’s price
A computer cost $850 today relative to a cost of $1,300 some 5 years ago. What is the relative price? $850 x = = 65.4 $1,300

17 Consumer Price Index (in percent)
Expense Atlanta Chicago NY LA Food Housing Clothing Medical care

18 Intended to measure the spread of data around the mean
Standard Deviation Intended to measure the spread of data around the mean Step 6. Find the square root ( ) of the number obtained in Step 5. This is the standard deviation Step 5. Divide the sum of the squared deviations by n - 1, where n equals the number of pieces of data Step 4. Sum all squared deviations Step 3. Square each deviation (multiply the deviation by itself) Step 2. Subtract the mean from each piece of data to find each deviation Step 1. Find the mean of the set of data

19 Standard Deviation Data Set A x x x x x
Step 1 ( ) = 6 (Mean) 5 Step 2 Step 3 Data Data-Mean (Data-Mean) = = = = 4 16 = 6 36 Total (Step 4) Step 5: Divide by n-1: = = 23.5 Step 6: The square root of is 4.8 Data Set A x x x x x The standard deviation of data set A is 4.8

20 Standard Deviation Data Set B x x x x x
Step 1 ( ) = 6 (Mean) 5 Step 2 Step 3 Data Data-Mean (Data-Mean) = = = = = Total (Step 4) Step 5: Divide by n-1: = = 5.5 Step 6: The square root of is 2.3 Data Set B x x x x x The standard deviation of data set A is 2.3

21 Problem 22-19 .35 x 360 = 126 .28 x 360 = 100.8 .20 x 360 = 72 .17 x 360 = 61.2 Misc. 17% Transportation 35% Food and entertainment % Hotel 28%

22 Problem 22-20 Frequency $0- $5.99 5 5 $6- $11.99 3 3 $12- $17.99 4 4
Intervals Tally Frequency $0- $ $6- $ $12- $ $18- $

23 Problem 22-21 Tally Day Bagels Product 150 9 9 x 150 = 1,350
7, 510 7,510/ 30 = = 250 Bagels

24 Problem 22-22 Thousands of dollars


Download ppt "Chapter 22 Statistics."

Similar presentations


Ads by Google