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Impulse Contents: Impulse/WB Area Under Force Graph Ft = mv Rocket Science Rocket Demos
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Change in momentum = Impulse
Impulse = F t where F = Force t = time that the force is exerted (F or t = 0???) Example: What impulse is imparted by exerting a 12 N force for 4.0 s? Impulse = F t = (12 N)(4.0 s) Impulse = 48 Ns
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Whiteboards Impulse 1 | 2
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What is the impulse of a 6.12 N force acting for 2.3 seconds?
14 Ns Impulse = F t Impulse = (6.12 N )(2.3 s)=14 Ns W
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A rocket engine is rated at 14 Ns of impulse, and burns for 1
A rocket engine is rated at 14 Ns of impulse, and burns for 1.7 seconds. What is the thrust of the engine? 8.2 N Impulse = F t 14 Ns = F(1.7 s) F = (14 Ns)/ (1.7 s) = 8.24 = 8.2 N W
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Impulse is area under = (40 N)(6.0s) = 240 Ns
Example - Impulse is area under F vs t graph t F 100 N 5.0 s Impulse is area under = (40 N)(6.0s) = 240 Ns
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Whiteboards 1 | 2 | 3
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What is the impulse? 100 N F t W 5.0 s
Average F = 70 N, t = 8.0 s, Impulse = (70 N)(8.0 s) = 560 Ns W 560 Ns
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What is the impulse? 100 N F t W 5.0 s
Impulse = (40 N)(3.0 s) + (70 N)(5.0 s)= 470 Ns W 470 Ns
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What is the impulse of the D12 engine?
Impulse = (10. N)(1.73 s-0.11 s) + (28 N-10 N)( ) = Ns (about 20 Ns) W 20 Ns
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Force, time, mass, and velocity Impulse = F t = mv
F = Force (N) t = Elapsed time (s) m = Mass (kg) v = Change in velocity (m/s) Example: A pitcher pitches a kg baseball at 40. m/s, and the batter hits it directly back at 50. m/s to the outfield. What is the average force exerted by the bat if the collision lasted .013 s? F t = mv (F )(.013 s) = (0.145 kg)(-90 m/s) F = (0.145 kg)(-90 m/s)/(.013 s) F = N ≈ -1.0x103 N (units/sign)
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Whiteboards Ft = mv 1 | 2 | 3
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What force for 10. seconds makes a 2
What force for 10. seconds makes a 2.0 kg rocket speed up to 75 m/s from rest? 15 N (m)(v) = (F )( t) (2.0 kg)(75 m/s) = (F )(10 s) F = (2.0 kg)(75 m/s)/(10 s) = 15 N
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A baseball bat exerts a force of 200. N on a. 50 kg ball for
A baseball bat exerts a force of 200. N on a .50 kg ball for .10 seconds. What is the ball’s change in velocity? 40. m/s (m)(v) = (F )( t) (.50 kg)(v) = (200. N )(.10 s) v = (200. N )(.10 s)/(.50 kg) = 40. m/s
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Jolene exerts a 50. N force for 3. 0 seconds on a stage set
Jolene exerts a 50. N force for 3.0 seconds on a stage set. It speeds up from rest to .25 m/s. What is the mass of the set? 6.0 x 102 kg (m)(v) = (F )( t) (m)(.25 m/s) = (50. N )(3.0 s) m = (50. N )(3.0 s)/(.25 m/s) = 600 kg = 6.0 x 102 kg
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One last thing: Deriving Newton’s second law: m v = F t Finally: F = m v = ma = p t t
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Rocket Propulsion Ft = mv So: F = engine thrust
t = time to burn fuel m = mass of fuel burned v = exhaust gas velocity Ft = mv
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Rocket Propulsion Example 1: A rocket burns fuel at a rate of 1.2 kg/s, with an exhaust velocity of 1250 m/s. What thrust does it develop? Ft = mv v = 1250 m/s m = 1.2 kg t = 1 s (F)(1 s) = (1.2 kg)(1250 m/s), F = 1500 N
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Rocket Propulsion Example 2: A model rocket engine develops 12 N of thrust with an exhaust velocity of 718 m/s. What is its fuel burn rate? Ft = mv F = 12 N v = 718 m/s m = ? kg t = 1 s (12 N)(1 s) = m(718 m/s), m = kg Burn rate = kg/s
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Whiteboards 1 | 2 | 3
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A certain rocket engine burns
A certain rocket engine burns kg of fuel per second with an exhaust velocity of 725 m/s. What thrust does it generate? 25.5 N Ft = mv F(1 s) = (.0352 kg)(725 m/s), F = 25.5 N W
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The Saturn V’s first stage engines generated 33. 82 MN of thrust (33
The Saturn V’s first stage engines generated MN of thrust (33.82 x 106 N) with an exhaust velocity of m/s. What was its fuel burn rate? 15,000 kg/s Ft = mv (33.82 x 106 N)(1 s) = m( m/s), m = 15,000 kg Burn Rate = 15,000 kg/s W
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A D12 engine generates 11. 80 N of thrust burning fuel at a rate of
A D12 engine generates N of thrust burning fuel at a rate of kg/s. What is the exhaust velocity? 825.2 m/s Ft = mv (11.80 N)(1 s) = (.0143 kg)v, v = = m/s W
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Which Rocket Accelerates faster?
B Demo – F14
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Rocket Propulsion Solid Fuel Engine: © Microsoft Encarta
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Rocket Propulsion Thrust of the Engine: F = mv t Big v means big F
Solid Fuel Engine: Big v means big F Big v also means lots of pressure Danger Will Robinson! © Microsoft Encarta
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© Estes
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m = .5 kg, Ft = 20 Ns Ft = m v 20 Ns = .5kg v
Lookout! m = .5 kg, Ft = 20 Ns Ft = m v 20 Ns = .5kg v v = ? (x for mph) © Estes
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Rocket Propulsion Liquid Fuel Engine: How do you keep it from tipping?
Why the “steam” coming off? © Microsoft Encarta
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Saturn V Rocket - Apollo missions
Escape Tower Command Module L.E.M Third stage Second stage First stage Saturn V Animation (Flash in IE)
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Ion Propulsion systems
Low thrust/high Δv 20-50 km/s exhaust velocity Dawn
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Gridded Xenon ion drive (Like Dawn has)
where’s the power come from? Gridded Xenon ion drive (Like Dawn has)
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How what is the “burn” rate for this engine?
The Dawn spacecraft has a mass of about 770 kg, and an ion drive with an exhaust velocity of 35,000 m/s that generates about 92 millinewtons of thrust. (.092 N) How what is the “burn” rate for this engine? Ft = mv (.092 N)(1.0 s) = m(35,000 m/s) m = E-06 kg/s How big a change in velocity can 50 kg of fuel give the spacecraft? The final mass will be 770 – 50 = 720 kg, on the average the spacecraft will have a mass of 745 kg So the delta v is approximately: (745 kg)(Δv) = (50 kg)(35,000 m/s) Δv ≈ 2350 m/s
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