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Chapter 8 Continued – Radical Expressions and Equations
Multiplication & Division of Radical Expressions When multiplying radical expressions, you can just put everything that’s under a radical sign together under one big radical sign. Distributive Property: BE CAREFUL!
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Example 3 Multiply Example Multiply Notice that when ra adical expression has two terms, all radicals disappear when you multiply the expression by its conjugate. Try this one:
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Radical Expressions in Simplest Form
A radical expression is in simplest form if: The radicand contains no factor greater than 1 that is a perfect square. There is no fraction under the radical sign. There is no radical in the denominator of a fraction. is not in simplest form because there is a fraction under the radical sign. This can be simplified by taking the square root of the numerator and the denominator.
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Is not in simplest form because there is a radical expression in the denominator;
The way to simplify is to multiply both numerator and denominator by This doesn’t always work when there is a two-term expression with at least one radical term added to another term. UGH! The trick for these types is to multiply the numerator and denominator by the conjugate. SIMPLIFIED!
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Solving Equations Containing Radical Expressions
Property of Squaring Both Sides of an Equation If a and b are real numbers and a=b, then a2=b2 It’s very important to check your solution because some “solutions” actually make the original equation untrue. Example: Notice that when you get the constants on one side, your equation says that the radical expression must equal a negative number. This is impossible! Therefore there is NO SOLUTION to an equation like this.
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square both sides This is now a degree 2 equation so put it in standard form, factor it, then use zero-product rule. Impossible because the principal square root of a number can never be negative. Therefore -6 is not a possible solution. OK Therefore, only solution is {5}
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You try! Solve: a = Solve equation and exclude any extraneous solutions: m =
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Solve:
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