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Long & Synthetic Division
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1st write as a division problem.
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Correct x2 What would you multiply x by to get x3 ?
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Multiply x2 by (x-7) and write under dividend
Then subtract by adding the opposite
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Correct 5x What would you multiply x by to get 5x2 ?
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Multiply 5x by (x-7) and write under the previous difference
Then subtract by adding the opposite
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Correct 40 What would you multiply x by to get 40x?
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Multiply 40 by (x-7) and write under the previous difference
Then subtract by adding the opposite
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This is the remainder
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Show x-3 is a factor of then rewrite with x-3 times the quotient
Because the remainder is zero x-3 is a factor
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Show x-5 is a factor of then rewrite with x-5 times the quotient
Because the remainder is zero x-5 is a factor
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P343 1 – 13 odd Divide using long division. Write your answer as
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Write the coefficients of the numerator adding any place holders
Use Synthetic Division to do the long division problem Write the opposite of the constant term 1 7 35 280 5 40 284 Write the coefficients of the numerator adding any place holders Multiply by 7 Add Drop the Coefficient Down Synthetic Division only works when the denominator is x-a where a is a constant
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Synthetic Division 7 35 280 1 5 40 284 The quotient will always be degree 1 less than the degree of the numerator
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Synthetic Division Write the opposite of the constant term 7 35 280 284 1 5 40 These are the coefficients of the quotient This is the remainder
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Use Synthetic Division to divide
3 -12 40 -120 -120 -10 30 30 -20 Multiply by -4 Add
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Use synthetic division
2 4 8 14 28 4 7 14 33
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Remainder Theorem: Let f be a polynomial function
Remainder Theorem: Let f be a polynomial function. If f(x) is divided by x-c, then the remainder is f(c) If you divide a polynomial function synthetically by a number the remainder is the value that would result if you plugged that number in the equation for x These two numbers will always be the same
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= -305 Use synthetic division to find
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Factor Therorem:Let f be a polynomial function
Factor Therorem:Let f be a polynomial function. Then x-c is a factor of f(x) if and only if f(c)=0 Since f(5)=0 then synthetically dividing by 5 will give a remainder of 0 and x-5 has to be a factor of f(x)
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Is x-3 is a factor of : If (x-3) is a factor of g(x) when we divide it into g(x) it will have no remainder. So we can write g(x) as What does g(3)=
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Show x+1 is a factor of g(x) then write g(x) as the product of x+1 and the quotient
-1 4 -4 What does g(-1)=
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Write answers in the form
P344 21,23,27,29,31,33,35,37
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