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Unit 3 - Day 5 Polynomial Long Division
Objective: SWBAT determine if (x-c) is a factor of a polynomial, through long division, and the factor theorem.
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Simplify the following: 3(x2 + 8x) - 2(2x2 - 6x - 9) ½(3x - 1)(2x - 3)
Warm Up Simplify the following: 3(x2 + 8x) - 2(2x2 - 6x - 9) ½(3x - 1)(2x - 3) Use long division to divide 548 by 3. For #2, write out the solution as a division statement to relate to p(x) / d(x) = q(x) + r(x)/d(x) And as a product statement to relate to q(x) * d(x) +r(x) = p(x)
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So we can add, subtract, and multiply polynomials together
So we can add, subtract, and multiply polynomials together...what about divide? (3x3 + 4x2 - 2x - 1) ÷ = (x + 4)
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x + 4 3x3 + 4x2 - 2x - 1 Demonstrate right next to the numerical example. Point out the similarities
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You try: (1-a) Polynomial Division ~worksheet~
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p(x) ÷ d(x) = q(x) + r(x)/d(x)
p(x) = q(x) × d(x) + r(x) Relate back to numerical example in warm up
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When we divide p(x) by (x - c), the remainder r(x) is equal to p(c).
Remainder Theorem: When we divide p(x) by (x - c), the remainder r(x) is equal to p(c). Relate back to numerical example from warm up
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When p(c) = 0, then (x - c) is a factor of the polynomial p(x).
Factor Theorem: When p(c) = 0, then (x - c) is a factor of the polynomial p(x). Relate back to numerical example from warm up
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You try: (1-b) Is (x-2) a factor of the polynomial?
Apply factor/remainder theorem. Find P(2)!!!
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Is there an easier way to divide polynomials?
Yes, it’s called Synthetic Division
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(3x3 + 4x2 - 2x - 1) ÷ = (x + 4) -4 Note that this only works with factors in the form of (x-c) or (ax-c) Relate to long division
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(2x4 - 3x2 +4) ÷ = (x - 2) 2 Example with coefficients of zero
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Classwork: Polynomial Division ~worksheet~
HW: Finish worksheet
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