1. Table 4(Lawrence, Justin, Paul, Jaehoon)
#22, 26,30,34
Table 4(Lawrence, Justin, Paul, Jaehoon)

2. #22
If Ben invests $4000 at 4% interest per year, how much additional money must he invest at 5.5% annual interest to ensure that the interest he receives each year is 4.5% of the total amount invested?
Identify the variable: x=additional money for invest
Translate from the words to algebra: Ben invest 4000$ 4.5% per year A, he needs to invest x 5.5% per year B, such that A+B=4.5%(4000+X)
Set up the model:0.04(4000)+0.055(X)+0.045(4000+x)
0.04(4000)+0.055(X)+0.045(4000+x)
40(4000)+55(x)=45(4000+x)
55x-45x=
10x=20000
X=2000

3. #26
A woman earns 15% more than her husband. Together they make $69,875 per year. What is the husband’s annual salary?
X = Husband’s annual salary
1.15X = Woman’s annual salary
+___________________________
2.25X = Their annual salary = $69,875
69,875/2.25 = 31,056 = X
Husband’s annual salary is $31,056

4. Father’s age = f | Daughter’s age = d
#30
A father is four times as old as his daughter. In 6 years, he will be three times as old as she is. How old is the daughter now?
Father’s age = f | Daughter’s age = d
f/ 4 = d
f= 4d
(f+ 6) / 3 = d + 6
f + 6 = 3d + 18
= f = 3d +12
Since f = 4d
4d = 3d +12
= d = 12
Daughter’s age is 12

5. #34
Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have?
Equation: 0.05(2x+5)+0.1(2x)+0.25(x)=3
0.55x+0.25=3
0.55X=2.75
X=5
Answer: 15 nickel, 10 dimes, 5 quarters
# of nickel: 2x+5
# of dime: 2x
# of quarter: x