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Chapter 16: Equilibrium in Acid-Base Systems
16.2b: Predicting Acid-Base Reactions
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Predicting Rxtn. Equilibria
B-L theory does not explain why certain protons are attracted more than others we must look at relative strengths of acids and bases both collision-reaction and Bronsted-Lowry theory deal with proton transfer we use a combination of concepts to help us predict which acid-base rxtn. is most dominant and observable in a system where multiple reactions can be taking place
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Predicting Rxtn. Equilibria con’t
Collision-rxtn theory in an A-B system collisions of all entities are always happening however the only significant rxtn is that between the SA and SB other proton transfer has a negligible effect on the system Bronsted-Lowry theory a proton will only transfer if an acid collides with a base that is a stronger proton attractor a proton can transfer multiple times until with the strongest base once the transfer from SA to SB has occurred, proton remains
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Guide for predicting reaction
Restrictions for proton transfer in aqueous solution Assume unless otherwise informed H3O+ is strongest acid entity in aqueous sol’n, all SA are written as H3O+ OH- is strongest base entity in aqueous sol’n, exceptions are ionic oxides where the oxide ion can be written as OH- (K2O) no entity can react as a base if it is a weaker base than water, conj. base of SA are not bases A-B system eqtn. represents a single proton transfer between entities in a 1:1 mole ratio the SA and SB are both present and reacting in approx. equal concentrations refer to acid-base strength table in data booklet and LSM 16.2a summary 2 for 5 step method
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Relative equilibrium positions
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Relative equilibrium positions
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Example Predict the products and direction in which the rxtn. between sulphate ions and acetic acid will proceed. SO CH3COOH <---> ? + ? Sol’n 1)List all entities SO4 2- , CH3COOH , H20 2)Label as B-L acid/base according to A-B strength table B A A,B 3)Identify SA and SB present CH3COOH -- SA SO SB
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Example con’t 4)Write eqtn. showing transfer of one proton from SA to SB and predict conjugates SO CH3COOH <---> HSO4- + CH3COO- SB SA CA CB 5)Predict approx. position of the equilibrium -since SO42- is above CH3COOH, the equilibrium is to the left and the reactants are favoured - <50% is used over the equilibrium arrows <50% SO CH3COOH <----> HSO4- + CH3COO-
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Homework Textbook p.731 #9,12,13,15 p. 735 #3,4 LSM 16.2a summary 2
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