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Lecture 22 Pumping Lemma for Context Free Languages
CSCE 355 Foundations of Computation Lecture 22 Pumping Lemma for Context Free Languages Topics: Normal forms Pumping Lemma for CFLs Closure properties November 19, 2008
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Last Time: New: Useless symbols:
generating symbols, useful symbols Algorithm for generating and reachable symbols Removal of useless symbols Removal of epsilon productions; Removal of unit productions Chomsky normal form New: Chomsky Hierarchy Pumping Lemma for Context Free Languages
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Algorithm for generating and reachable symbols
Useless symbols: generating symbols, useful symbols Algorithm for generating and reachable symbols Removal of useless symbols Removal of epsilon productions; Removal of unit productions Chomsky normal form
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Chomsky Normal Form A CFG (Context Free Grammar) is in Chomsky Normal form if productions are one of the following two forms: A BC A a References
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Conversion to Chomsky Normal Form
Remove: ε-productions, unit productions A BCDE A abc In general For each terminal ‘a’ create a new non-terminal Na with Na a added as a production A B1B2…Bk create a new non-terminals C1C2…Ck and replace the production with A B1C1 and Ci Bi+1Ci+1 for i=1,…k-3 Ck-2 Bk-1Bk
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Example
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Regular Grammars A CFG is regular if all productions are of the form:
A a or A aB Note sentential forms in a derivation based on a regular grammar have a unique form! What is it ? Grammar NFA construction Create a state for each nonterminal. A aB means δ(A, a) = B and A a means δ(A, a) = Qfinal and
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Example
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Chomsky Hierarchy http://en.wikipedia.org/wiki/Chomsky_hierarchy
Grammar Languages Automaton Production rules (constraints) Type-0 Recursively enumerable Turing machine α β no restrictions Type-1 Context-sensitive Linear-bounded non-deterministic Turing machine αAβ αγβ Type-2 Context-free Non-deterministic pushdown automaton A α Type-3 Regular DFA A a or A aB
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Chomsky Hierarchy Venn Diagram
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Backus Naur Form (BNF) Backus Naur Form John Backus Peter Naur
N ::= α | … | β (just a CFG) John Backus Fortran compiler Peter Naur
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Greibach Normal Form Each production RHS starts with a terminal
A aα or S ε
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Showing Languages are not CFLs
Recursive productions A a A | b B B a | b D aDb | d A * α A β
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Pumping Lemma for CFLs Let L be a CFL. Then there exists a constant n such that if z is a string in L of length at least n, then we can write z = uvwxy such that |vwx| =< n |vx| > 0 uviwxi y is in L for all i >= 0.
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Idea behind proof Assume CNF (or do for L(G)-{ε}) Consider Parse Tree
Sufficiently long string z, means the parse tree must be sufficiently big.
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Similarities to Pumping Lemma for Regular Languages
Given an arbitrary n. Carefully choose z in L (depending on n) with |z| >= n. Then for any partition z = uvwxy that satisfies |vx| > 0 |vwx| <= n We must be able to “pump”, i.e. uviwxiy is in L for all i >= 0
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Example L = {anbncn | n > 0}
Given L as above, suppose we chose n for the Pumping Lemma (for CFLs). Choose z = Consider arbitrary partition of z = uvwxy satisfying | vwx| =< n |vx| > 0 Then show …
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Example
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Homework 7.1.4 7.1.3 7.1.6
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