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Patterns & Proportions

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Presentation on theme: "Patterns & Proportions"— Presentation transcript:

1 Patterns & Proportions
Unit 1 - Science

2 Simple Proportions If Y is directly proportional to X then…
…If X doubles, Y will __________. Double

3 Directly Proportional Equation:
k X

4 How do I solve for K? Graph Y vs. X & the slope = k
(k is called the proportionality constant).

5 Natural Graph vs. Linearized Graph
Don’t Need Y X

6 Let’s Try An Example: You are curious if there is a relationship between the height of a child and its weight. You collect the following data by measuring all the children on your street…

7 Here is the data you collect:
Height (in) Weight (lbs.) 25 31 29 35 33 44 41 51 45 54

8 Graph the information on the graph grid in your notes.

9 Your graph should look similar to this:
Height and Weight Relationship of Babies Weight (lbs) Height (in)

10 Next Steps: Write the EQUATION FORM: Y= kx Circle your cross points.
Solve for K. K = (50-0)/(40-0) = 50/40 = 1.25

11 So our real world equation is:
1.25 h Where W is the weight & h is the height.

12 Summing it up! Answer: 65 lbs
Based on the shape of your graph, the weight of a child is directly proportional to height. This means if a child is THREE times as tall it will weigh 3 times as much! Use your real world equation to predict how much a child would weigh if she was 52 inches tall. Answer: 65 lbs

13 Now try it on your own! Go back to your turtle graph and determine the real world equation.
K = 0.6 and real world equation is d=0.6t

14 Now let’s do a real world application
Now let’s do a real world application. Follow the instructions for the Spring Lab found below.

15 Simple Proportions If Y is inversely proportional to X then…
…If X doubles, Y will __________. Half

16 Inversely Proportional Equation:
k __ X

17 How do I solve for K? Graph Y= 1 __ X & the slope = k

18 Natural Graph vs. Linearized Graph
Y Y X 1/x

19 Inversely Proportional Example:
You are curious if there is a relationship between the time you study for a test and the number of points you miss. You keep track of your test scores for the year…

20 Here is the data you collect:
Time (min) Missed (pts.) 5 10 25 2 40 1 50

21 Graph the information on the first graph grid in your notes.

22 Your graph should look similar to this:
How study time affects my grade Missed (pts.) Time (min)

23 Now we need to linearize the graph:
To do this we will graph 1/x and Y. First we need to change our data table.

24 Our new data table will look like this:
1/x Y 1/5 = .2 10 1/10 = .1 5 1/25 =.04 2 1/40 = .025 1 1/50 = .02

25 Graph the information on the second graph grid in your notes.

26 Your graph should look similar to this:
1/x

27 Next Steps: Write the EQUATION FORM: Y= k/x Circle your cross points.
Solve for K. K = (4-3)/( ) = 1/.02 = 50

28 So our real world equation is:
P = 50 __ t Where P is the points & t is the study time.

29 Summing it up! Based on the shape of your graph, the points lost on a test are Inversely proportional to Study time. This means if you study FIVE times you will loose 1/5 as many points! (See studying helps!) Use your real world equation to predict how many points you would miss if you only studied for 2 minutes. Answer: 25 points

30 Now try it on your own! Go back to your medication graph from the basic graphs lab and determine the real world equation.

31 Now let’s do a real world application
Now let’s do a real world application. Follow the instructions for the Mass Lab found on the next page.


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