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5.1 Integer Exponents and Scientific Notation.

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Presentation on theme: "5.1 Integer Exponents and Scientific Notation."— Presentation transcript:

1 5.1 Integer Exponents and Scientific Notation

2 Using the Product Rule for Exponents
Example 1 Apply the product rule for exponents, if possible, in each case. (a) (b) (c) (d) Answer (a) (b) (c) (d)

3 Example 2 Using 0 as an Exponent Evaluate. (a) (b) (c) (d) Answer (a) (b) (c) (d)

4 Using Negative Exponents
Example 3 Using Negative Exponents Write with only positive exponents. (a) (b) (c) (d) Evaluate Answer (a) (b) (c) (d)

5 Using Negative Exponents
Example 4 Using Negative Exponents Evaluate. (a) (b) Answer (a) (b)

6 Using the Quotient Rule for Exponents
Example 5 Apply the quotient rule, if possible, and write each result with only positive exponents. (a) (b) (c) Answer (a) (b) (c) The quotient rule does not apply.

7 Using the Power Rules for Exponents
Example 6 Using the Power Rules for Exponents Simplify, using the power rules. (a) (b) (c) Answer (a) (b) (c)

8 Using Negative Exponents with Fractions
Example 7 Write with only positive exponents and evaluate. Answer

9 Using the Definitions and Rules for Exponents
Example 8 Simplify. Assume that all variables represent nonzero real numbers. (a) (b) (c) (d) Answer (a)

10 Using the Definitions and Rules for Exponents (continued)
Example 8 (b) (c) (d)

11 Writing Numbers in Scientific Notation
Example 9 Write each number in scientific notation. (a) 29,800,000 (b) Answer (a) 29,800,000 = 2.98 × 107 (b) = 5.03 × 10–8

12 Converting from Scientific Notation to Standard Notation
Example 10 Write each number in standard notation. (a) 2.51 × 103 (b) –6.8 × 10–4 Answer (a) 2.51 × 103 = 2510 (b) –6.8 × 10–4 = –

13 Using Scientific Notation in Computation
Example 11 Evaluate Answer

14 Using Scientific Notation to Solve Problems
Example 12 The distance to the Sun is 9.3 × 107 miles. How long would it take a rocket traveling at 3.2 × 103 miles per hour to reach the Sun? Answer d = rt, so It will take about 2.9 × 104 or 29,000 hours to reach the sun.


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