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Wake-up Strong acids completely ionize in water. Explain what this means. Name the following acids/bases: a. HNO2 b. Hydrosulfuric acid c. Be(OH)2.

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Presentation on theme: "Wake-up Strong acids completely ionize in water. Explain what this means. Name the following acids/bases: a. HNO2 b. Hydrosulfuric acid c. Be(OH)2."— Presentation transcript:

1 Wake-up Strong acids completely ionize in water. Explain what this means. Name the following acids/bases: a. HNO2 b. Hydrosulfuric acid c. Be(OH)2

2 Neutralization Reactions using Titration Method
What is a titration? What’s the point?

3 Neutralization Reaction
The process that occurs when an acid and a base come in contact with each other to make a salt and water

4 What is a Titration? Lab method used to figure out the concentration of a reactant or reagent

5 Acid-Base Titration A solution containing a known concentration of base is slowly added to an acid until the acid is completely neutralized or vice versa

6 Known solution is in the Biuret (Titrant) Unknown and the Indicator
Titration Apparatus Known solution is in the Biuret (Titrant) Unknown and the Indicator

7 Phenolphthalein turns pink in base at 8 pH
Indicator A substance that indicates the degree of acidity or basicity of a solution through color changes Phenolphthalein turns pink in base at 8 pH

8 How to do a Titration

9

10 Graphical Representations
Titrations are represented graphically with end points [pH=7], and equivalence points [H+] = [OH-]. Steepest part of the curve where the pH rises the fastest

11 Compare the graphs of strong acids/bases with the graphs of weak acids/bases

12 MAVA = MBVB Titration Formula MA = Molarity of Acid
VA = Volume of Acid MB = Molarity of Base VB = Volume of Base

13 Example #1 A student neutralizes a 15 mL sample of vinegar (acetic acid) with mL of a 0.4 M NaOH solution. What is the molarity of the vinegar? MA = x VA = 15 mL MB = 0.4 M VB = mL (x)(15 mL) = (0.4 M)(31.85 mL) 0.85 M of vinegar

14 Example #2 It takes 83 mL of a 0.45 M NaOH solution to neutralize 235 mL of an HCl solution. What is the concentration of the HCl solution? MA = 0.45 M VA = 83 mL MB = x VB = 235 mL (0.45 M)(83 mL) = (x)(235 mL) 0.16 M of HCl

15 Bromothymol Blues Song


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