Presentation is loading. Please wait.

Presentation is loading. Please wait.

ASEN 5050 SPACEFLIGHT DYNAMICS Prox Ops, Lambert

Similar presentations


Presentation on theme: "ASEN 5050 SPACEFLIGHT DYNAMICS Prox Ops, Lambert"— Presentation transcript:

1 ASEN 5050 SPACEFLIGHT DYNAMICS Prox Ops, Lambert
Prof. Jeffrey S. Parker University of Colorado – Boulder Lecture 15: ProxOps, Lambert

2 Announcements Homework #5 is due next Friday 10/10
CAETE by Friday 10/17 Homework #6 will be due Friday 10/17 CAETE by Friday 10/24 Solutions will be available in class on 10/17 and online by 10/24. If you turn in HW6 early, me and I’ll send you the solutions to check your work. Mid-term Exam will be handed out Friday, 10/17 and will be due Wed 10/22. (CAETE 10/29) Take-home. Open book, open notes. Once you start the exam you have to be finished within 24 hours. It should take 2-3 hours. Reading: Chapter 6, 7.6 Lecture 15: ProxOps, Lambert

3 Space News Comet Siding Spring will pass by Mars on October 19th, making things really exciting for all of the Mars vehicles. Lecture 15: ProxOps, Lambert

4 Space News The “Rosetta Comet” or 67P/Churyumov-Gerasimenko fired its jets last week – just published. Lecture 15: ProxOps, Lambert

5 ASEN 5050 SPACEFLIGHT DYNAMICS Prox Ops
Prof. Jeffrey S. Parker University of Colorado – Boulder Lecture 15: ProxOps, Lambert

6 CW / Hill Equations Enter Clohessy/Wiltshire (1960) And Hill (1878)
(notice the timeline here – when did Sputnik launch? Gemini was in need of this!) Lecture 15: ProxOps, Lambert

7 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

8 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Use RSW coordinate system (may be different from NASA) Target satellite has two-body motion: The interceptor is allowed to have thrusting Then So, Lecture 15: ProxOps, Lambert

9 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
If we assume circular motion, Thus, Assume = 0 (good for impulsive DV maneuvers, not for continuous thrust targeting). CW or Hill’s Equations Lecture 15: ProxOps, Lambert

10 Assumptions Please Take Note: We’ve assumed a lot of things
We’ve assumed that the relative distance is very small We’ve assumed circular orbits These equations do fall off as you break these assumptions! Lecture 15: ProxOps, Lambert

11 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
The above equations can be solved (see book: Algorithm 48) leaving: So, given of interceptor, can compute of interceptor at future time. Lecture 15: ProxOps, Lambert

12 Applications What can we do with these equations?
Estimate where the satellite will go after executing a small maneuver. Rendezvous and prox ops! Examples. First from the book. Lecture 15: ProxOps, Lambert

13 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

14 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

15 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

16 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

17 Hubble’s Drift from Shuttle
RSW Coordinate Frame Lecture 15: ProxOps, Lambert

18 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

19 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

20 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
We can also determine DV needed for rendezvous. Given x0, y0, z0, we want to determine necessary to make x=y=z=0. Set first 3 equations to zero, and solve for Assumptions: Satellites only a few km apart Target in circular orbit No external forces (drag, etc.) Lecture 15: ProxOps, Lambert

21 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

22 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
Lecture 15: ProxOps, Lambert

23 Clohessy-Wiltshire (CW) Equations (Hill’s Equations)
NOTE: This is not the Delta-V, this is the new required relative velocity! Lecture 15: ProxOps, Lambert

24 CW/H Examples Scenario 1: Scenario 1b:
Use eqs to compute x(t), y(t), and z(t) RSW coordinates, relative to deployer. Note: in the CW/H equations, the reference state doesn’t move – it is the origin! Deployment: x0, y0, z0 = 0, Delta-V = non-zero Use eqs to compute x(t), y(t), and z(t) RSW coordinates, relative to reference. Initial state: non-zero Lecture 15: ProxOps, Lambert

25 Initial state in the RSW frame
CW/H Equations Rendezvous For rendezvous we usually specify the coordinates relative to the target vehicle and set x, y, and z to zero Though if there’s a docking port, then that will be offset from the center of mass of the vehicle. Define RSW targets: x, y, z (often zero) Initial state in the RSW frame Lecture 15: ProxOps, Lambert Target: some constant values in the RSW frame

26 CW/H Equations Rendezvous
For rendezvous we usually specify the coordinates relative to the target vehicle and set x, y, and z to zero Though if there’s a docking port, then that will be offset from the center of mass of the vehicle. Define RSW targets: x, y, z (often zero) This is easy if the targets are zero (Eq. 6-66) This is harder if they’re not! Velocity needed to get onto transfer Initial state in the RSW frame Lecture 15: ProxOps, Lambert Target: some constant values in the RSW frame

27 CW/H Equations Rendezvous
For rendezvous we usually specify the coordinates relative to the target vehicle and set x, y, and z to zero Though if there’s a docking port, then that will be offset from the center of mass of the vehicle. Define RSW targets: x, y, z (often zero) This is easy if the targets are zero (Eq. 6-66) This is harder if they’re not! Velocity needed to get onto transfer Initial state in the RSW frame The Delta-V is the difference of these velocities Lecture 15: ProxOps, Lambert Target: some constant values in the RSW frame

28 CW / H Scenario 3: A jetpack-wielding astronaut leaves the shuttle and then returns. Lecture 15: ProxOps, Lambert Shuttle: reference frame

29 CW / H Scenario 3: A jetpack-wielding astronaut leaves the shuttle and then returns. Result of deployment Lecture 15: ProxOps, Lambert Shuttle: reference frame

30 CW / H Scenario 3: A jetpack-wielding astronaut leaves the shuttle and then returns. Rendezvous trajectory (Eq 6-66) Result of deployment Lecture 15: ProxOps, Lambert Shuttle: reference frame

31 CW / H Scenario 3: A jetpack-wielding astronaut leaves the shuttle and then returns. Delta-V is the difference of these velocities. Rendezvous trajectory (Eq 6-66) Result of deployment Lecture 15: ProxOps, Lambert Shuttle: reference frame

32 Comparing Hill to Keplerian Propagation
Deviation: 100 meters 1 cm/s Position Error: ~1.4 meters/day Lecture 15: ProxOps, Lambert

33 Comparing Hill to High-Fidelity, e=0.15
Generally returns to 0.0 near one apsis Position Error: ~9.5 km/day Lecture 15: ProxOps, Lambert

34 Comparing Hill to High-Fidelity, e=0.73
Generally returns to 0.0 Position Error: ~4.2 km/day Lecture 15: ProxOps, Lambert

35 Analyzing Prox Ops Lecture 15: ProxOps, Lambert

36 Analyzing Prox Ops What happens if you just change x0?
Radial displacement? Lecture 15: ProxOps, Lambert

37 Analyzing Prox Ops Lecture 15: ProxOps, Lambert

38 Analyzing Prox Ops What happens if you just change vx0?
Radial velocity change? Lecture 15: ProxOps, Lambert

39 Analyzing Prox Ops Lecture 15: ProxOps, Lambert

40 Analyzing Prox Ops What happens if you just change vy0?
Tangential velocity change? Lecture 15: ProxOps, Lambert

41 Analyzing Prox Ops Lecture 15: ProxOps, Lambert

42 Analyzing Prox Ops What happens if you just change vz0?
Out-of-plane velocity change? Lecture 15: ProxOps, Lambert

43 Analyzing Prox Ops Lecture 15: ProxOps, Lambert

44 ASEN 5050 SPACEFLIGHT DYNAMICS Lambert’s Problem
Prof. Jeffrey S. Parker University of Colorado – Boulder Lecture 15: ProxOps, Lambert

45 Lambert’s Problem Lambert’s Problem has been formulated for several applications: Orbit determination. Given two observations of a satellite/asteroid/comet at two different times, what is the orbit of the object? Passive object and all observations are in the same orbit. Satellite transfer. How do you construct a transfer orbit that connects one position vector to another position vector at different times? Transfers between any two orbits about the Earth, Sun, or other body. Lecture 15: ProxOps, Lambert

46 Lambert’s Problem Given two positions and the time-of-flight between them, determine the orbit between the two positions. Lecture 15: ProxOps, Lambert

47 Orbit Transfer We’ll consider orbit transfers in general, though the OD problem is always another application. Lecture 15: ProxOps, Lambert

48 Orbit Transfer Note: there’s no need to perform the transfer in < 1 revolution. Multi-rev solutions also exist. Lecture 15: ProxOps, Lambert

49 Orbit Transfer Consider a transfer from Earth orbit to Mars orbit about the Sun: Lecture 15: ProxOps, Lambert

50 Orbit Transfer Orbit Transfer True Anomaly Change “Short Way”
Δν < 180° “Long Way” Δν > 180° Hohmann Transfer (assuming coplanar) Δν = 180° Type I 0° < Δν < 180° Type II 180° < Δν < 360° Type III 360° < Δν < 540° Type IV 540° < Δν < 720° Lecture 15: ProxOps, Lambert

51 Lambert’s Problem Given: Find: Numerous solutions available.
Some are robust, some are fast, a few are both Some handle parabolic and hyperbolic solutions as well as elliptical solutions All solutions require some sort of iteration or expansion to build a transfer, typically finding the semi-major axis that achieves an orbit with the desired Δt. Lecture 15: ProxOps, Lambert

52 Ellipse d1 d2 Lecture 15: ProxOps, Lambert

53 Ellipse d1 d2 d4 d3 Lecture 15: ProxOps, Lambert

54 Ellipse A transfer from r1 to r2 will be on an ellipse, with the central body occupying one focus. Where’s the 2nd focus? r1 r2 Lecture 15: ProxOps, Lambert

55 Ellipse A transfer from r1 to r2 will be on an ellipse, with the central body occupying one focus. Where’s the 2nd focus? r1 r2 Lecture 15: ProxOps, Lambert

56 Ellipse A transfer from r1 to r2 will be on an ellipse, with the central body occupying one focus. Where’s the 2nd focus? r1 r2 Lecture 15: ProxOps, Lambert

57 Ellipse A transfer from r1 to r2 will be on an ellipse, with the central body occupying one focus. Where’s the 2nd focus? r1 r2 Focus is one of these Try different a values until you hit your TOF Lecture 15: ProxOps, Lambert

58 Lambert’s Problem Lecture 15: ProxOps, Lambert

59 Lambert’s Problem Find the chord, c, using the law of cosines and
Define the semiperimeter, s, as half the sum of the sides of the triangle created by the position vectors and the chord We know the sum of the distances from the foci to any point on the ellipse equals twice the semi-major axis, thus Lecture 15: ProxOps, Lambert

60 Lambert’s Problem Lecture 15: ProxOps, Lambert

61 Lambert’s Problem The minimum-energy solution: where the chord length equals the sum of the two radii (a single secondary focus) Thus, (anything less doesn’t have enough energy) Lecture 15: ProxOps, Lambert

62 Lambert’s Problem Lambert’s Solution Elliptic Orbits Hyperbolic Orbits
Lecture 15: ProxOps, Lambert

63 Lambert’s Problem For minimum energy Lecture 15: ProxOps, Lambert

64 Universal Variables A very clear, robust, and straightforward solution. There are a few faster solutions, but this one is pretty clean. Begin with the general form of Kepler’s equation: # revolutions Transfer Duration Lecture 15: ProxOps, Lambert

65 Universal Variables Simplify Lecture 15: ProxOps, Lambert

66 Universal Variables Define Universal Variables:
Lecture 15: ProxOps, Lambert

67 Universal Variables Lecture 15: ProxOps, Lambert

68 Universal Variables Use the trigonometric identity
Lecture 15: ProxOps, Lambert

69 Universal Variables Now we need somewhere to go
Let’s work on converting this to true anomaly, via: Lecture 15: ProxOps, Lambert

70 Universal Variables Multiply by a convenient factoring expression:
Lecture 15: ProxOps, Lambert

71 Universal Variables Collect into pieces that can be replaced by true anomaly Lecture 15: ProxOps, Lambert

72 Universal Variables Substitute in true anomaly:
Lecture 15: ProxOps, Lambert

73 Universal Variables Trig identity again: Lecture 15: ProxOps, Lambert

74 Universal Variables Note: Lecture 15: ProxOps, Lambert

75 Universal Variables Use some substitutions:
Lecture 15: ProxOps, Lambert

76 Universal Variables Summary: Lecture 15: ProxOps, Lambert

77 Universal Variables It is useful to convert to f and g series (remember those!?) Lecture 15: ProxOps, Lambert

78 UV Algorithm Lecture 15: ProxOps, Lambert

79 A few details on the Universal Variables algorithm
Lecture 15: ProxOps, Lambert

80 Universal Variables Let’s first consider our Universal Variables Lambert Solver. Given: R0, Rf, ΔT Find the value of ψ that yields a minimum-energy transfer with the proper transfer duration. Applied to building a Type I transfer Lecture 15: ProxOps, Lambert

81 Single-Rev Earth-Venus Type I
-4π 4π2 Lecture 15: ProxOps, Lambert

82 Single-Rev Earth-Venus Type I
-4π 4π2 Lecture 15: ProxOps, Lambert

83 Note: Bisection method
-4π 4π2 Lecture 15: ProxOps, Lambert

84 Note: Bisection method
-4π 4π2 Lecture 15: ProxOps, Lambert

85 Note: Bisection method
-4π 4π2 Lecture 15: ProxOps, Lambert

86 Note: Bisection method
-4π 4π2 Lecture 15: ProxOps, Lambert

87 Note: Bisection method
-4π 4π2 Lecture 15: ProxOps, Lambert

88 Note: Bisection method
-4π 4π2 Lecture 15: ProxOps, Lambert

89 Note: Bisection method
-4π 4π2 Lecture 15: ProxOps, Lambert

90 Note: Bisection method
Time history of bisection method: Requires 42 steps to hit a tolerance of 10-5 seconds! Lecture 15: ProxOps, Lambert

91 Note: Newton Raphson method
Lecture 15: ProxOps, Lambert

92 Note: Newton Raphson method
Lecture 15: ProxOps, Lambert

93 Note: Newton Raphson method
Lecture 15: ProxOps, Lambert

94 Note: Newton Raphson method
Lecture 15: ProxOps, Lambert

95 Note: Newton Raphson method
Time history of Newton Raphson method: Requires 6 steps to hit a tolerance of 10-5 seconds! Note: This CAN break in certain circumstances. With current computers, this isn’t a HUGE speed-up, so robustness may be preferable. Lecture 15: ProxOps, Lambert

96 Note: Newton Raphson Log Method
Note log scale -4π 4π2 Lecture 15: ProxOps, Lambert

97 Single-Rev Earth-Venus Type I
-4π 4π2 Lecture 15: ProxOps, Lambert

98 Single-Rev Earth-Venus Type II
-4π 4π2 Lecture 15: ProxOps, Lambert

99 Interesting: 10-day transfer
-4π 4π2 Lecture 15: ProxOps, Lambert

100 Interesting: 950-day transfer
-4π 4π2 Lecture 15: ProxOps, Lambert

101 UV Algorithm Lecture 15: ProxOps, Lambert

102 Multi-Rev Seems like it would be better to perform a multi-rev solution over 950 days than a Type II transfer! Lecture 15: ProxOps, Lambert

103 A few details The universal variables construct ψ represents the following transfer types: Lecture 15: ProxOps, Lambert

104 Multi-Rev ψ ψ ψ ψ Lecture 15: ProxOps, Lambert

105 Earth-Venus in 850 days Type IV Lecture 15: ProxOps, Lambert

106 Earth-Venus in 850 days Heliocentric View Distance to Sun
Lecture 15: ProxOps, Lambert

107 Earth-Venus in 850 days Type VI Lecture 15: ProxOps, Lambert

108 Earth-Venus in 850 days Heliocentric View Distance to Sun
Lecture 15: ProxOps, Lambert

109 What about Type III and V?
Type V Type III Type VI Type IV Lecture 15: ProxOps, Lambert

110 Earth-Venus in 850 days Type III Lecture 15: ProxOps, Lambert

111 Earth-Venus in 850 days Heliocentric View Distance to Sun
Lecture 15: ProxOps, Lambert

112 Earth-Venus in 850 days Type V Lecture 15: ProxOps, Lambert

113 Earth-Venus in 850 days Heliocentric View Distance to Sun
Lecture 15: ProxOps, Lambert

114 Summary The bisection method requires modifications for multi-rev.
Also requires modifications for odd- and even-type transfers. Newton Raphson is very fast, but not as robust. If you’re interested in surveying numerous revolution combinations then it may be just as well to use the bisection method to improve robustness Lecture 15: ProxOps, Lambert

115 Types II - VI Lecture 15: ProxOps, Lambert


Download ppt "ASEN 5050 SPACEFLIGHT DYNAMICS Prox Ops, Lambert"

Similar presentations


Ads by Google