1. Wed, 3/29 SWBAT… multiply two binomials using the FOIL method
Agenda
WU (10 min)
Multiplying two binomials (20 min)
Warm-Up:
Simplify: 3ab(5a2 – a – 2) + 2a(b + 1)
Solve: 5(9w + 2) = 3(8w – 7) + 17
Solve: 3(2n – 3) – 1 = -4(2n + 1) + 8
HW#6: Multiplying two binomials
15a3b – 3a2b – 4ab + 2a
w = -2/3
n = 1

2. SWBAT…multiply two binomials using the FOIL method Mon, 4/4
Agenda
WU (10 min)
Observations (5 min)
Multiplying two binomials (15 min)
Work on HW (15 min)
Warm-Up: Find each product:
1.) (x + 4)(x – 2)
2.) (2y – 7)(3y + 5)
3.) (4a – 5)(2a – 9)
HW #6 & #7: Multiplying binomials
1.) x2 + 2x – 8
2.) 6y2 – 11y – 35
3.) 8a2 – 46a + 45

3. Multiply two binomials using FOIL method
To multiply two binomials, find the sum of the products
(x – 2)(x + 3)
F the First terms O the Outer terms I the Inner terms L the Last terms F O F L I O
= (x)(x)
+ (x)(3)
+ (-2)(x)
+ (3)(-2) L I
= x2 + 3x – 2x – 6
= x2 + x – 6

4. Find each product: = x2 + 2x – 8 2.) (2y – 7(3y + 5)L
1. (x + 4)(x – 2)
2.) (2y – 7(3y + 5)
3.) (4a – 5)(2a – 9)
= (x)(x)
+ (x)(-2)
+ (4)(x)
+ (4)(-2) I O
= x2 – 2x + 4x – 8
= x2 + 2x – 8

5. Observations
The expression (x + 4)(x – 2) is read as “the quantity of x plus 4 times the quantity of x minus 2”
FOIL is a memory tool, the order in which the terms are multiplied is not important, as long as four products are found.
Notice that when the two linear expressions are multiplied, the result is a quadratic (degree 2).

6. SWBAT…multiply two binomials using the FOIL method Mon, 3/19
Agenda
WU (10 min)
Multiplying two binomials application problems (20 min)
Math fun! (5 min)
Work on HW#5 (10 min)
Warm-Up: Multiply each special product:
1.) (x + 4)2 Square of a Sum
2. (x – 6)2 Square of a Difference
3. (x + 2)(x – 2) Product of a Sum and a Difference
Homework: HW#5 & HW#6
Answers:
1.) (x + 4)2 = (x + 4)(x + 4) = x2 + 8x + 16
2.) (x – 6)2 = (x – 6)(x – 6) = x2 – 12x + 36
3.) (x + 2)(x – 2) = x2 – 4

7. Write an expression to represent the area of the blue shaded region.
(4x2 – 25) – (x2 – 4) = 3x2 – 21

8. Write an expression to represent the area of the shaded region.
(4x2 – 36) – (x2 – 4) = 3x2 – 32

9. Write an expression that represents the area of the court.
VOLLEYBALL
The dimensions of a volleyball court are represented by a width of 6y – 5 feet and a length of 3y + 4 feet.
Write an expression that represents the area of the court.
The length of a volleyball court is 31 feet. Find the area of the court.
(a) A = LW
A = (6y – 5)(3y + 4) = = 18y2 + 24y – 15y – 20 = 18y2 + 9y – 20
(b) L = 3y + 4
31 = 3y + 4
3y = 27
y = 9
18y2 + 9y – 20
18(92) + 9(9) – 20
– 20
1519 ft2

10. Take out HW#6: Multiplying two binomials

11. C

12. C

13. D

14. A rectangular prism has dimensions x, x + 3, 2x + 5
A rectangular prism has dimensions x, x + 3, 2x Find the volume of the prism in terms of x.
x(x + 3) = x2 + 2x
(x2 + 3x)(2x + 5) = 2x3 + 11x2 + 15x

15. Antonia is carpeting two of the rooms in her house
Antonia is carpeting two of the rooms in her house. The dimensions are shown in the figures. What is the total area to be carpeted.
x – 2 x
x(x + 3) = x2 + 3x
(x – 2)(x + 5) = x2 + 3x – 10
(x2 + 3x) + (x2 + 3x – 10) = 2x2 + 6x – 10
x + 5
x + 3