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Chapter 20 Static Electricity
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Calculate: 6.4 x 10274 x 1.5 x 10-162 8.0 x 10-254 7.5 x 10175 x 2.0 x 10-225 =
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The study of charges that can be collected and held in one place
Electrostatics The study of charges that can be collected and held in one place
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Come up with examples where charge differences build up in nature, and describe the consequences
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Caused by an electron imbalance as electrons move
Charge Caused by an electron imbalance as electrons move
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In neutral atoms the number of electrons = the number of protons
Atomic Charge In neutral atoms the number of electrons = the number of protons
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Opposite charges attract & like charges repel
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The charge of an object leaks off into water molecules in air
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Charged objects eventually return to their neutral state
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Holding a charge is easy on dry days & difficult on humid days
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Materials like metals that allow electrons or charges to move
Conductors Materials like metals that allow electrons or charges to move
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Copper, silver, gold, aluminum, & graphite
Common Conductors Copper, silver, gold, aluminum, & graphite
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Materials that will not allow electrons or charges to move easily
Insulators Materials that will not allow electrons or charges to move easily
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Glass, dry wood, plastic, rubber, & dry air
Common Insulators Glass, dry wood, plastic, rubber, & dry air
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Anything that can absorb lots of electrons
Electron Sink Anything that can absorb lots of electrons
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Common Electron Sinks People, Earth, etc
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A device used to detect electrical charge
Electroscope A device used to detect electrical charge
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Define: Conductor Insulator Electron Sink
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Charge Redistribution
Conduction Induction
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Charge by touching a charged body to a neutral body
Charge by Conduction Charge by touching a charged body to a neutral body
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Charge by moving a charged body near a neutral body
Charge by Induction Charge by moving a charged body near a neutral body
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Charge Separation on Neutral Objects
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- - - + - - - + - - - + - + - + - + + + - + + + - + + +
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- - - + - - - + - - - + - + - + - + + + - + + + - + + +
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Force caused by the attraction or repulsion of charges
Electrical Force Force caused by the attraction or repulsion of charges
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Electrical force must be much greater than gravitational force
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Coulomb’s Law Force between charges is proportional to charge & inversely proportional to distance between charges
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Coulomb’s Law F qAqB
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Coulomb’s Law 1 d2 F
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Coulomb’s Law qAqB d2 F
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Fe Formula qAqB dAB2 Fe = K
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Electric Constant 9.0 x 109 Nm2 C2 K =
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Identify another formula that is very similar to the electrical force formula
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Define: Charge by Induction Charge by Conduction
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Gravity Formula mAmB dAB2 Fg = G
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Calculate the electrical force occurring when a ball with a charge of 2.0 x 10-8 C is 12 mm from another ball with a charge of -3.0 x 10-8 C:
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Calculate the electrical force occurring when a ball with a charge of 3.0 x 10-4 C is 12 mm from another ball with a charge of -6.0 x 10-6 C:
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Millikens Oil Droplet Experiment
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+ plate Fup Fup = Fdown Fdown qoqp d2 m1m2 d2 Fdown = G = mg Fup = K
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qoqp d2 K = mg mgd2 Kqp qo =
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Electron Charge 1.60 x C C = Coulombs
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Calculate the force between 2 electrons 8.0 x 10-3 nm apart:
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Calculate the force between the electron & the nucleus of hydrogen: 4
Calculate the force between the electron & the nucleus of hydrogen: 4.0 x 10-2 nm apart:
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Calculate: Fe on B dAB = 4.0 mm dBC = 3.0 mm qA = - 4.0 x 10-5 C
qB = 3.0 x 10-5 C qC = 9.0 x 10-5 C
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Calculate the force between 2 particles 1.2 x 10-3 mm apart:
q1 = 4.0 x 10-5C q2 = x 10-4C
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Calculate: Fe on A dAB = 4.0 mm dBC = 3.0 mm qA = - 4.0 x 10-5 C
qB = 3.0 x 10-5 C qC = 9.0 x 10-5 C
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Calculate: Fe on C dAB = 4.0 mm dBC = 3.0 mm qA = -4.0 x 10-2 C
qB = 3.0 x 10-2 C qC = 6.0 x 10-2 C
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Calculate the charge of a particle 3
Calculate the charge of a particle 3.0 mm away from a magnet that can produce a force of N with a charge of C.
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Calculate: Fe on B dAB = 5.0 mm dBC = 10.0 mm qA = -4.0 x 10-3 C
qB = 3.0 x 10-3 C qC = 6.0 x 10-3 C C
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Explain, on the atomic level, how any substance can build up an electric charge.
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Calculate: Fe on C dAC = 5.0 nm dBC = 3.0 nm qA = 4.0 x 10-3 C
qB = 3.0 x 10-3 C qC = 5.0 x 10-3 C
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Calculate: Fe on B dAB = 6.0 nm dBC = 5.0 nm qA = 4.0 x 10-3 C
g B C qA = 4.0 x 10-3 C = 44o = 37o = 40o Small = 30o qB = 3.0 x 10-3 C qC = 5.0 x 10-3 C
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Explain how to attain a charge & the conditions necessary for attaining that charge.
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