1. Relational Algebra - Select & Project
Given the following tables:
employee (person_name, gender, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Select
Find all people who work in “First Bank Corporation”
company_name=“First Bank Corporation”(works)
Project
Find all company names
company_name(company)

2. Relational Algebra - Union & Intersection
Given the following tables:
employee (person_name, gender, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Union
Find every person who is either an employee or a manager (there is automatic duplicate elimination in all algebra operations)
person_name(employee)∪manager_name(manages)
Intersection
Find all persons that are both employee and manager.
person_name(employee)∩manager_name(manages)

3. Relational Algebra – Set Difference
Given the following tables:
employee (person_name, gender, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Set Difference
Find all persons that are employee but not manager.
person_name(employee) – manager_name(manages)

4. Relational Algebra – Cartesian Product & Natural Join
Given the following tables:
employee (person_name, gender, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Cartesian Product
Produces all possible combinations of records from employee and works.
employee  works
Natural Join
Show the employee names, city, and the salary for their jobs (for employees who work in some company).
person_name, city, salary(employee works)

5. Relational Algebra – Division
Given the following tables:
employee (person_name, gender, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Division
Find all persons that work in all companies.
(person_name, company_name(works))  (company_name(company))

6. Exercises Given the following tables:
employee (person_name, gender, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Find the names of all the “female” employees who work in the company “XX”.

7. Relational Algebra & Tuple Relational Calculus
Given the following tables:
employee (person_name, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Find the name of all employees who earn more than $10,000
person_name (salary > “10000” (works))

8. Relational Algebra & Tuple Relational Calculus
Given the following tables:
employee (person_name, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Find the cities of the companies that “Jay” works for
company.city (company (person_name = “Jay” (works)))

9. Exercises Given the following tables:
employee (person_name, street, city)
works (person_name, company_name, salary)
company (company_name, city)
manages (company_name, manager_name)
Find the names and cities of employees who work for “First Bank Corporation”
Emphasize that the scope of s is indicated by the following bracket and should be carefully specified.