1. DRILL
Solve for x:
220°
(2x+ 5)°
100°

2. 12.6 Segment Lengths in Circles
Geometry
Mr. Calise

3. Objectives/Assignment
Find the lengths of segments of chords.
Find the lengths of segments of tangents and secants.

4. Finding the Lengths of Chords
When two chords intersect in the interior of a circle, each chord is divided into two segments which are called segments of a chord. The following theorem gives a relationship between the lengths of the four segments that are formed.

5. Theorem 12.14
If two chords intersect in the interior of a circle, then the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.
EA • EB = EC • ED

6. Proving Theorem 12.14
You can use similar triangles to prove Theorem
Given: , are chords that intersect at E.
Prove: EA • EB = EC • ED

7. Proving Theorem 12.14
Paragraph proof: Draw and Because C and B intercept the same arc, C  B. Likewise, A  D. By the AA Similarity Postulate, ∆AEC  ∆DEB. So the lengths of corresponding sides are proportional. =
Lengths of sides are proportional.
EA • EB = EC • ED
Cross Product Property

8. Ex. 1: Finding Segment Lengths
Chords ST and PQ intersect inside the circle. Find the value of x.
RQ • RP = RS • RT
Use Theorem 10.15
Substitute values.
9 • x = 3 • 6
9x = 18
x = 2
Simplify.
Divide each side by 9.

9. 12 2x 10 15

10. Segments of Tangents and Secants
In the figure shown, PS is called a tangent segment because it is tangent to the circle at an end point. Similarly, PR is a secant segment and PQ is the external segment of PR.

11. Theorem 12.16
If a secant segment and a tangent segment share an endpoint outside a circle, then the product of the length of the secant segment and the length of its external segment equal the square of the length of the tangent segment.
(EA)2 = EC • ED

12. 10 6 x

13. 8 12

14. Finding Segment Lengths (BA)2 = BC • BD Use Theorem 10.17
(5) = x • (x + 4)
Substitute values.
Simplify.
25 = x2 + 4x
Write in standard form.
0 = x2 + 4x - 25
Use Quadratic Formula.
x =
x =
Simplify.
Use the positive solution because lengths cannot be negative. So, x =  3.39.

15. Theorem 12.15
If two secant segments share the same endpoint outside a circle, then the product of the length of one secant segment and the length of its external segment equals the product of the length of the other secant segment and the length of its external segment.
EA • EB = EC • ED

16. Finding Segment Lengths
Find the value of x.
RP • RQ = RS • RT
Use Theorem 10.16
9•(11 + 9)=10•(x + 10)
Substitute values.
180 = 10x + 100
Simplify.
80 = 10x
Subtract 100 from each side.
8 = x
Divide each side by 10.

17. 10 6 x 15

18. Ex. 3: Estimating the radius of a circle
Aquarium Tank. You are standing at point C, about 8 feet from a circular aquarium tank. The distance from you to a point of tangency is about 20 feet. Estimate the radius of the tank.

19. Solution (CB)2 = CE • CD Use Theorem 10.17 (20)2  8 • (2r + 8)
Substitute values.
Simplify.
400  16r + 64
Subtract 64 from each side.
336  16r
Divide each side by 16.
21  r
So, the radius of the tank is about 21 feet.

20. Congratulations on Finishing the Geometry Curriculum
Chapter 12 Test on Wednesday!
REVIEW Days June 3rd, 4th, 7th, 8th, 9th, 10th, 11th, 14th (PD 3 Only), 15th (PD 3 Only)
FINAL EXAM
PD 2: Tuesday June 15th (7:55 – 9:30)
PD 3: Tuesday June 15th (12:30 – 2:05)