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nth Roots and Rational Exponents
Section 5.1 beginning on page 238
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The Basics π π₯ π =π₯ ( π π₯ ) π =π₯ π π π π
π π₯ π =π₯ Pg. 239 in your textbook π π ( π π₯ ) π =π₯ **We will only have two solutions when the radicand is positive and the root is even.** Pg. 238 in your textbook
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Finding nth Roots Example 1: Find the indicated real nth root(s) of a.
a) n = 3, a = b) n = 4, a = 81 3 β216 4 81 =β6 =Β±3 Monitoring Progress: Find the indicated nth root(s) of a. 1) n=4, a=16 2) n=2, a=-49 3) n=3, a=-125 4) n=5, a =243 4 16 =Β±2 3 β125 =β5 β49 βππ ππππ ππππ’π‘ππππ 5 243 =3
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Rational Exponents Example 2: Evaluate each expression
a) b) β3 5 (Write without negative or rational exponents before evaluating the roots and then the powers) = = 1 ( 5 32 ) 3 = = 1 8 b) 32 β3 5 a) = ( 16 ) 3 = 4 3 =64 Monitoring Progress: Evaluate the expression without using a calculator 5) ) 9 β ) ) = 1 243 =32 =27 =1
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Approximating Example 3: Evaluate each expressing using a calculator. Round your answer to two decimal places (to the nearest hundredth). a) b) c) ( 4 7 ) 3 β1.55 β2.54 β4.30 Monitoring Progress: Evaluate the expression using a calculator. Round your answer to two decimal places when appropriate. 9) ) β ) ( 4 16 ) 5 12) ( 3 β30 ) 2 β2.05 β0.06 =32 β9.65
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Solving Equations Using nth Roots
To solve an equation of the form π’ π =π, where u is an algebraic expression, take the nth root of each side. Example 4: Find the real solution(s) of (a) 4 π₯ 5 =128 (b) (π₯β3) 4 =21 4 (π₯β3) 4 = 4 21 π₯ 5 =32 5 π₯ 5 = 5 32 π₯β3=Β± 4 21 π₯=3Β± 4 21 (exact solution) π₯=2 π₯= π₯=3β 4 21 (approximate solutions) π₯β5.14 π₯β0.86
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Solving Equations Using nth Roots
Monitoring Progress: Find the real solution(s) of the equation. Round your answer to two decimal places when appropriate. 13) 8 π₯ 3 = ) π₯ 5 =512 15) (π₯+5) 4 = ) (π₯β2) 3 =β14 π₯=2 π₯=4 π₯=β3 πππ π₯=7 π₯ββ0.41
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