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nth Roots and Rational Exponents

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1 nth Roots and Rational Exponents
Section 5.1 beginning on page 238

2 The Basics 𝑛 π‘₯ π‘š =π‘₯ ( 𝑛 π‘₯ ) π‘š =π‘₯ π‘š 𝑛 π‘š 𝑛
𝑛 π‘₯ π‘š =π‘₯ Pg. 239 in your textbook π‘š 𝑛 ( 𝑛 π‘₯ ) π‘š =π‘₯ **We will only have two solutions when the radicand is positive and the root is even.** Pg. 238 in your textbook

3 Finding nth Roots Example 1: Find the indicated real nth root(s) of a.
a) n = 3, a = b) n = 4, a = 81 3 βˆ’216 4 81 =βˆ’6 =Β±3 Monitoring Progress: Find the indicated nth root(s) of a. 1) n=4, a=16 2) n=2, a=-49 3) n=3, a=-125 4) n=5, a =243 4 16 =Β±2 3 βˆ’125 =βˆ’5 βˆ’49 β†’π‘π‘œ π‘Ÿπ‘’π‘Žπ‘™ π‘†π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘›π‘  5 243 =3

4 Rational Exponents Example 2: Evaluate each expression
a) b) βˆ’3 5 (Write without negative or rational exponents before evaluating the roots and then the powers) = = 1 ( 5 32 ) 3 = = 1 8 b) 32 βˆ’3 5 a) = ( 16 ) 3 = 4 3 =64 Monitoring Progress: Evaluate the expression without using a calculator 5) ) 9 βˆ’ ) ) = 1 243 =32 =27 =1

5 Approximating Example 3: Evaluate each expressing using a calculator. Round your answer to two decimal places (to the nearest hundredth). a) b) c) ( 4 7 ) 3 β‰ˆ1.55 β‰ˆ2.54 β‰ˆ4.30 Monitoring Progress: Evaluate the expression using a calculator. Round your answer to two decimal places when appropriate. 9) ) βˆ’ ) ( 4 16 ) 5 12) ( 3 βˆ’30 ) 2 β‰ˆ2.05 β‰ˆ0.06 =32 β‰ˆ9.65

6 Solving Equations Using nth Roots
To solve an equation of the form 𝑒 𝑛 =𝑑, where u is an algebraic expression, take the nth root of each side. Example 4: Find the real solution(s) of (a) 4 π‘₯ 5 =128 (b) (π‘₯βˆ’3) 4 =21 4 (π‘₯βˆ’3) 4 = 4 21 π‘₯ 5 =32 5 π‘₯ 5 = 5 32 π‘₯βˆ’3=Β± 4 21 π‘₯=3Β± 4 21 (exact solution) π‘₯=2 π‘₯= π‘₯=3βˆ’ 4 21 (approximate solutions) π‘₯β‰ˆ5.14 π‘₯β‰ˆ0.86

7 Solving Equations Using nth Roots
Monitoring Progress: Find the real solution(s) of the equation. Round your answer to two decimal places when appropriate. 13) 8 π‘₯ 3 = ) π‘₯ 5 =512 15) (π‘₯+5) 4 = ) (π‘₯βˆ’2) 3 =βˆ’14 π‘₯=2 π‘₯=4 π‘₯=βˆ’3 π‘Žπ‘›π‘‘ π‘₯=7 π‘₯β‰ˆβˆ’0.41

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