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Do Now What is a chemical bond?
Homework Check Do Now What is a chemical bond? What is the difference between an ionic bond and a covalent bond? What is the difference between resonance structures and isomers? What are the five types of molecular geometry and bond angles we learned?
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Do Now What is a chemical bond? A force that holds atoms together
What is the difference between an ionic bond and a covalent bond? Ionic bonds involve the transfer of electrons while covalent bonds involve sharing of electrons
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Do Now What is the difference between resonance structures and isomers? Resonance structures are two or more correct Lewis dot structures where the atoms are connected the same way but the electrons are distributed differently Isomers are two or more molecules with the same chemical formula but different structures
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Do Now What are the five types of molecular geometry and bond angles we learned? Linear, 180° Trigonal Planar, 120° Tetrahedral, 109.5° Trigonal Pyramidal, 107.5° Bent, 104.5°
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Answers to Homework
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Test 7 - Covalent Bonding
Honors Test: 25 questions, 9 pages Chemistry Test: 17 questions, 6 pages This is a hard test Period Cold Call Date Test Date 3 Wed, Apr 27 Fri, Apr 29 4 Thu, Apr 28 6 Mon, May 2 7
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Department Night No Department Nights on Wednesday
Faculty Meeting Department Night moved to Thursday
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Easy Lewis Dot Structures
Write this in your notes Easy Lewis Dot Structures Students will be able to draw Lewis dot structures using an easier method
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Background There is lots to know about Lewis dot structures
single bonds, double bonds, triple bonds, coordinate covalent bonds octets, suboctets, expanded octets, odd electron structures charges, formal charges, resonance structures Now that we know all of this, we can learn an easier method for finding the correct Lewis dot structure of a molecule
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Comments on Easy Method
The easy method has advantages: Easier Faster Usually gives correct answer The easy method also has disadvantages: Series of rules must be memorized & followed precisely to ensure correct answer Users who don't truly understand bonding theory can get lost on challenging molecules
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Write this in your notes
6 Steps of Easy Method Add up all electrons Arrange all non-H atoms Connect all non-H atoms using e pairs Complete octets using e pairs and bonds to H Create multiple bonds to finish all octets Calculate formal charges to get best structure Lots of details on handout
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Detailed Steps of Easy Method Steps 1-5
Add up all electrons add up all valence electrons, then add or subtract for charge divide the total by 2 to get pairs & assign pairs to each H Arrange all non-H atoms start with least electronegative alone in the center Connect all non-H atoms using e pairs can create expanded octets for atoms of Period 3 or higher Complete octets using e pairs and bonds to H start with more electronegative atoms on outside use both e pairs and bonds to H if isomers possible, draw structures for each Create multiple bonds to finish all octets
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Detailed Steps of Easy Method Step 6
Calculate formal charges to get best structure For Period 2 elements, the best structure is defined as: Never exceeds octet rule (suboctets okay, but no expanded octets) Lowest formal charges on the most appropriate atoms For Period 3 and higher elements, the best structure is defined as: Expanded octets okay Lowest formal charges 0 for all atoms is the best +1 and ‒1 are tolerable, but the number of atoms with charges should be minimized +2 and ‒2 are very unstable & exceptionally rare Most appropriate atoms Negative formal charge on more electronegative atom Positive formal charge on less electronegative atom
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Br2 Br Br 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 14 / 2 = 7 e pairs 0 bonded to H 4) Complete octets using e pairs and bonds to H 5) Create multiple bonds to finish all octets Br Br 6) Calculate formal charges to get best structure
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Check for Understanding 1
OF2 PCl3
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O2 O O 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 12 / 2 = 6 e pairs 0 bonded to H 4) Complete octets using e pairs and bonds to H 5) Create multiple bonds to finish all octets O O
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O2 O O 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 12 / 2 = 6 e pairs 0 bonded to H 4) Complete octets using e pairs and bonds to H 5) Create multiple bonds to finish all octets O O 6) Calculate formal charges to get best structure
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Check for Understanding 2
CO2
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Elements from Period 3 and higher can form expanded octets
PCl5 1) Add up all electrons 2) Arrange all non-H atoms 5 + 5(7) = 40 e 3) Connect all non-H atoms using e pairs 40 / 2 = 20 e pairs 0 bonded to H 4) Complete octets using e pairs and bonds to H P Cl 5) Create multiple bonds to finish all octets 6) Calculate formal charges to get best structure Elements from Period 3 and higher can form expanded octets
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Check for Understanding 3
SF6
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CH4O C O 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 14 / 2 = 7 e pairs 4 bonded to H 4) Complete octets using e pairs and bonds to H C O
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H C O H O C H H When completing octets, first start by making bonds to hydrogen. Place these so that each element gets its normal number of bonds Carbon normally has 4 bonds. It has one to oxygen, so add three bonds to hydrogen to get a total of 4 bonds Oxygen normally has 2 bonds. It has one to carbon, so add one bond to hydrogen to get a total of 2 bonds Now used the non-bonding electrons to complete octets
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H H O C H O C +1 ‒1 +2 ‒2 O C If you can give all atoms their "normal" number of bonds, they should all have formal charges of zero If you have a structure that satisfies the octet rule and all atoms have a zero formal charge, it is usually the best, or one of the best possible structures. You can always examine isomers based on the position of the hydrogens . . . . . . but resulting structures are often worse on formal charges
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CH4O H H C O H H 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 14 / 2 = 7 e pairs 4 bonded to H 4) Complete octets using e pairs and bonds to H H 5) Create multiple bonds to finish all octets H C O H H 6) Calculate formal charges to get best structure
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Check for Understanding 4
HNO2 Make both isomers based on bonding to hydrogen Calculate formal charge to find the best structure
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CO3‒2 O C 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 24 / 2 = 12 e pairs 0 bonded to H 4) Complete octets using e pairs and bonds to H O C 5) Create multiple bonds to finish all octets
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If asked, be sure to show resonance structures
CO3‒2 1) Add up all electrons 2) Arrange all non-H atoms 4 + 3(6) + 2 = 40 e 3) Connect all non-H atoms using e pairs 24 / 2 = 12 e pairs 0 bonded to H ‒1 4) Complete octets using e pairs and bonds to H O C 5) Create multiple bonds to finish all octets 6) Calculate formal charges to get best structure If asked, be sure to show resonance structures
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Check for Understanding 5
NH4+1 NO3‒1
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COCl2 Cl C O Cl 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 24 / 2 = 12 e pairs 0 bonded to H 4) Complete octets using e pairs and bonds to H Cl B 5) Create multiple bonds to finish all octets C O A Cl
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O C Cl O C Cl O C Cl 6) Calculate formal charges to get best structure
‒1 +1 O C Cl B O C Cl B 6) Calculate formal charges to get best structure A O C Cl A
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Check for Understanding 6
CNO‒1 (N in center)
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BF3 F B 1) Add up all electrons 2) Arrange all non-H atoms
3) Connect all non-H atoms using e pairs 24 / 2 = 12 e pairs 0 bonded to H 4) Complete octets using e pairs and bonds to H F B 5) Create multiple bonds to finish all octets
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Is there a structure with better formal charges?
BF3 1) Add up all electrons 2) Arrange all non-H atoms 3 + 3(7) = 24 e 3) Connect all non-H atoms using e pairs 24 / 2 = 12 e pairs 0 bonded to H +1 ‒1 4) Complete octets using e pairs and bonds to H F B 5) Create multiple bonds to finish all octets 6) Calculate formal charges to get best structure Is there a structure with better formal charges?
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The structure with the suboctet is actually preferred
BF3 3 + 3(7) = 24 e 24 / 2 = 12 e pairs 0 bonded to H +1 ‒1 F B F B The structure with the suboctet is actually preferred
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Check for Understanding 7
BeCl2 AlH3
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Homework In SO4‒2, S is the central atom and all O's are bonded directly to it. Draw the Lewis dot structure where all atoms get an octet Compute the formal charge Explore expanded octets and their formal charges to find the best structure Draw line and composite resonance structures of the best structure
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The second part of this lesson can be broken off to replace octet rule violators. The current octet rule violators was not well understood. Use the benefits of the formal charge to show why the suboctet and expanded octet exist. CO2 could have a triple bond between oxygen and carbon, but formal charges show it will not be favored.
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Do Now Below is step 5 of the easy method for CO2. Shown are two ways to finish the octet on C. Which is the better structure and why? CO2 4 + 2(6) = 16 e 16 / 2 = 8 e pairs O C O C O C Structure B Structure A
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O C O C O C Structure B Structure A
‒1 +1 O C Structure B Structure A Structure A is better. All atoms in structure A have formal charges of 0. In structure B, two atoms have formal charges that are not 0, including a +1 formal charge on highly electronegative oxygen.
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Test 7 - Covalent Bonding
Honors Test: 25 questions, 9 pages Chemistry Test: 17 questions, 6 pages This is a hard test Period Cold Call Date Test Date 3 Wed, Apr 27 Fri, Apr 29 4 Thu, Apr 28 6 Mon, May 2 7
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CBr4
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