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Algebra substitution
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Substitution a = 3 b = 4 c = 2 a + b + c = 3 a + b + c 4 2 = 9
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Substitution a = 3 b = 4 c = 2 3b + c = 3 x b + c 4 2 = 14
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Substitution a = 3 b = 4 c = 2 a2 + c = a2 + c 3 2 = 9 + 2 = 11
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Substitution a = 3 b = 4 c = 2 4a – c2 = 4 x a - c2 = 4 x 3 – 22
= 12 – 4 = 8
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Substitution a = 3 b = 4 c = 2 ab - 2 = a x b - 2 = 4 x 3 – 2 = 12 – 2
= 10
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Exercise 1 a = 3 b = 4 c = 2 4a + c 8. b + c a – c 2
7b – 14c (a + b) b2 - c abc ab + bc ab – (10 + c) 10bc + 5b
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Exercise 1 a = 3 b = 4 c = 2 4a + c 14 8. b + c 3 a – c 1 2
7b – 14c (a + b) 35 b2 - c abc 24 ab + bc 20 ab – (10 + c) 0 10bc + 5b 100
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Exercise 2 a = 3 b = 4 c = 2 Find 3 different formulae to give an answer of 0 Find 3 different formulae to give an answer of 2
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