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Riemann Sums and the Definite Integral
Lesson 5.3
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Why? Why is the area of the yellow rectangle at the end = b a
The yellow rectangle is the sum of the differences between right and left sums! a b
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Review We partition the interval into n sub-intervals
Evaluate f(x) at right endpoints of kth sub-interval for k = 1, 2, 3, … n f(x)
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Limit of a Sum a b For a function f(x), the area under the curve from a to b is where x = (b – a)/n and Consider the region bounded by f(x) = x2 the axes, and the lines x = 2 and x = 3
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Limit of a Sum Now So
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Limit of a Sum Continuing …
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Review a b Sum We expect Sn to improve thus we define A, the area under the curve, to equal the above limit. f(x) Look at Java demo
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Riemann Sum Partition the interval [a,b] into n subintervals a = x0 < x1 … < xn-1< xn = b Call this partition P The kth subinterval is xk = xk-1 – xk Largest xk is called the norm, called ||P|| Choose an arbitrary value from each subinterval, call it
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Riemann Sum Form the sum This is the Riemann sum associated with
the function f the given partition P the chosen subinterval representatives We will express a variety of quantities in terms of the Riemann sum
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The Riemann Sum Calculated
Consider the function 2x2 – 7x + 5 Use x = 0.1 Let the = left edge of each subinterval Note the sum
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The Riemann Sum We have summed a series of boxes
If the x were smaller, we would have gotten a better approximation f(x) = 2x2 – 7x + 5
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The Definite Integral The definite integral is the limit of the Riemann sum We say that f is integrable when the number I can be approximated as accurate as needed by making ||P|| sufficiently small f must exist on [a,b] and the Riemann sum must exist
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Example Try We will use 4 "slices" n = 4 Use summation on calculator.
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Example Note increased accuracy with smaller x
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Limit of the Riemann Sum
The definite integral is the limit of the Riemann sum.
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Properties of Definite Integral
Integral of a sum = sum of integrals Factor out a constant Dominance
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Properties of Definite Integral
Subdivision rule f(x) a c b
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Area As An Integral The area under the curve on the interval [a,b] A
f(x) A a c
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Distance As An Integral
Given that v(t) = the velocity function with respect to time: Then Distance traveled can be determined by a definite integral Think of a summation for many small time slices of distance
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Assignment Section 5.3 Page 314 Problems: 3 – 49 odd
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