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Charles Law.

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Presentation on theme: "Charles Law."— Presentation transcript:

1 Charles Law

2 At higher temperatures, the particles in a gas have greater kinetic energy.
The volume of a gas is directly proportional to temperature when the pressure (P) and number of moles (n) are constant. T V T V To be an accurate direct proportion, the line must go through the origin volume temperature V1 = V2 T T2

3

4 New Temperature Scale Kelvin K = °C + 273
This new scale allows a direct proportion and no need for negative temperature values MUST USE FOR ALL GAS LAWS!! Standard temperature

5 Absolute zero Zero kelvin Lowest temperature possible
All molecule motion stops Never been achieved

6 Ex. A sample of helium occupies 473 cm3 at 36°C
Ex. A sample of helium occupies 473 cm3 at 36°C. What will be the volume when temperature is increased to 94°C? V1= 473 cm3 T1 = = 309 K V2 = ? T2 = = 367 K V1 = V2 T1 T2 V2 (473 cm3) = (309 K) (367 K) (473 cm3)(367 K) = (309 K)V2 V2 = 562 cm3 (309 K) (309 K)

7 Combined Gas Law

8 Put Boyle’s and Charles’ Law together to make the Combined Gas Law
P1V1 = P2V2 T1 T2

9 Ex. A gas has a volume of 7. 84 mL at 71. 8 kPa and 25. 0°C
Ex. A gas has a volume of 7.84 mL at 71.8 kPa and 25.0°C. What will be the volume at STP? P1 = 71.8 kPa V1 = 7.84 mL T1 = = 298 K P2 = kPa V2 = ? T2 = = 273 K P1V1 = P2V2 T1 T2 (71.8 kPa)(7.84 mL) = ( kPa)V2 298 K 273 K (71.8 kPa)(7.84 mL)(273 K) = ( kPa)(273 K)V2 ( kPa)(298 K) ( kPa)(273 K) V2 = 5.09 mL


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