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Section 8.2 Day 4
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Tomorrow: Quiz Use backside of note card used for 8.1 HW Quiz 8.1 – 8.2…when? Test 8.1 – 8.2…when? -- Both sides of 1 note card
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Reject, not reject, or accept null hypothesis?
P-value = % confidence 2) P-value = % confidence 3) P-value = significance level of 0.1
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Reject, not reject, or accept null hypothesis?
P-value = % confidence P-value < α = 0.05 so reject Ho 2) P-value = % confidence 3) P-value = significance level of 0.1
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Reject, not reject, or accept null hypothesis?
P-value = % confidence P-value < α = 0.05 so reject Ho 2) P-value = % confidence P-value > α = 0.01 so do not reject Ho 3) P-value = significance level of 0.1
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Reject, not reject, or accept null hypothesis?
P-value = % confidence P-value < α = 0.05 so reject Ho 2) P-value = % confidence P-value > α = 0.01 so do not reject Ho 3) P-value = significance level of 0.1 P-value < α = 0.1 so reject Ho
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Types of Errors Reasoning of significance tests often compared to that of a jury trial.
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Types of Errors Reasoning of significance tests often compared to that of a jury trial.
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Types of Errors
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Types of Error and Power
Type I Error: rejecting a true null hypothesis
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Types of Error and Power
Type I Error: rejecting a true null hypothesis The probability of making a Type I error is equal to the significance level, α, of the test. P(Type I error) = α
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Types of Error and Power
Type I Error: To decrease the probability of a Type I error, make α smaller. We make α smaller by increasing the confidence level.
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Types of Error and Power
Type I Error: To decrease the probability of a Type I error, make α smaller. We make α smaller by increasing the confidence level. Confidence level α 90% 95% 99%
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Types of Error and Power
Type I Error: To decrease the probability of a Type I error, make α smaller. Changing sample size has no effect on the probability of a Type I error.
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Types of Error and Power
If the null hypothesis is false, you can not make a Type I error. Type I Error: rejecting a true null hypothesis
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Types of Error and Power
Type II Error: Failing to reject a false null hypothesis.
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Types of Error and Power
Type II Error: Failing to reject a false null hypothesis. To decrease the probability of making Type II error: Increase sample size or Make significance level, α, larger
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Types of Error and Power
If null hypothesis is true, you can not make a Type II error.
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Types of Error and Power
Power: the probability of rejecting the null hypothesis.
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Types of Error and Power
Power: the probability of rejecting the null hypothesis. When null hypothesis is false, you want to reject it. Therefore you want the power to be large.
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Types of Error and Power
When null hypothesis is false, you want to reject it. Therefore you want the power to be large. Power = 1 – probability of Type II error How do you increase the power?
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Types of Error and Power
Power = 1 – probability of Type II error How do you increase the power? decrease probability of Type II error
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Types of Error and Power
Power = 1 – probability of Type II error How do you increase the power? decrease probability of Type II error Take larger sample or make α larger
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Page 511, P30
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Page 511, P30 critical value associated with significance level of 0.12?
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Page 511, P30 (a) critical value associated with significance level of 0.12? invNorm(0.06) is about ± 1.55
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Page 511, P30 (b) What significance level is associated with critical values of z* of ?
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Page 511, P30 (b) What significance level is associated with critical values of z* of ? 2[normalcdf(-1EE99, -1.73)] =
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Page 513, P42
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Page 513, P42 (a) Name: One-sided significance test for a proportion
One-sided because question asks whether poll results imply less than half of adults are satisfied.
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Page 513, P42 Conditions: Problem states this is a random sample
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Page 513, P42 Conditions: Problem states this is a random sample
Both npo = 1000(0.5) = 500 and n(1 – po) = 1000(1 – 0.5) = 500 are at least 10.
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Page 513, P42 Conditions: Problem states this is a random sample
Both npo = 1000(0.5) = 500 and n(1 – po) = 1000(1 – 0.5) = 500 are at least 10. Number of adults in U.S. is at least 10(1000) = 10,000
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Page 513, P42 (b) (Recall, null hypothesis has form p = po)
H0 : p = 0.5, where p is proportion of all adults in the U.S. who would say they are satisfied with the quality of K–12 education in the nation
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Page 513, P42 (b) (Recall, null hypothesis has form p = po)
H0 : p = 0.5, where p is proportion of all adults in the U.S. who would say they are satisfied with the quality of K–12 education in the country Ha: p < 0.5 Question asks whether poll results imply less than half of adults are satisfied.
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Page 513, P42 (c) po = 0.5, x = 46%(1000) = 460, n = 1000, p < po
Use 1-PropZTest z is approx ; P-value is approx
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Page 513, P42 (d) No significance level was given, so use
α = 0.05 and confidence level of 95%. I reject the null hypothesis because the P-value of is less than the significance level of α = 0.05.
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Page 513, P42 (d) No significance level was given, so use
α = 0.05 and confidence level of 95%. I reject the null hypothesis because the P-value of is less than the significance level of α = 0.05. There is sufficient evidence to support the claim that less than a majority of adults in the United States are satisfied with the quality of K–12 education.
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Page 513, P42 (d) I reject the null hypothesis because the
test statistic, z, of about is outside the critical value of There is sufficient evidence to support the claim that less than a majority of adults in the United States are satisfied with the quality of K–12 education.
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Page 511, P33 Name of test?
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Page 511, P33 Two-sided significance test for a proportion.
Carry out the four steps in a test of the null hypothesis that half of the bookstores in the United States sell DVDs. Hypotheses in symbols?
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Page 511, P33 Two-sided significance test for a proportion.
Carry out the four steps in a test of the null hypothesis that half of the bookstores in the United States sell DVDs. Ho: p = 0.5
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Page 511, P33 Two-sided significance test for a proportion.
Carry out the four steps in a test of the null hypothesis that half of the bookstores in the United States sell DVDs. Ho: p = 0.5 Ha: p ≠ 0.5
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Page 516, E41 Name of test?
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Page 516, E41 One-sided significance test for a proportion.
Determine whether the increase in the proportion of mutations is statistically significant Hypotheses in symbols?
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Page 516, E41 One-sided significance test for a proportion.
Determine whether the increase in the proportion of mutations is statistically significant Ho: p = 0.02
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Page 516, E41 One-sided significance test for a proportion.
Determine whether the increase in the proportion of mutations is statistically significant Ho: p = 0.02 Ha: p > 0.02
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Page 514 E27 Name of test?
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Page 514 E27 Two-sided significance test for a proportion
test the claim that 60% of the students in school carry backpacks to school
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Page 515, E33
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Page 515, E33
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis The hypothesis you assume is true in the test
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis The hypothesis you assume is true in the test
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis Rejecting Ho when Ho is really true
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis Rejecting Ho when Ho is really true
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis z-score of the sample statistic
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis z-score of the sample statistic
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis Half the width of the confidence interval
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis Half the width of the confidence interval
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis Not rejecting Ho when Ho is really false
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis Not rejecting Ho when Ho is really false
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis The hypothesis you are seeking evidence for
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis The hypothesis you are seeking evidence for
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis The probability of seeing a result this extreme or more extreme
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis The probability of seeing a result this extreme or more extreme
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis statistic +/- (critical value of z)(std dev of statistic)
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis statistic +/- (critical value of z)(std dev of statistic)
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis A standard for Ho rejection: also called z*
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis A standard for Ho rejection: also called z*
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis A standard for Ho rejection: also called the alpha-level
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Vocabulary A) margin of error B) z-statistic
C) Type I error D) Type II error E) critical value of z F) significance level G) P-value H) confidence interval I) null hypothesis J) alternative hypothesis A standard for Ho rejection: also called the alpha-level
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Page 511, P33
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Page 511, P33 Step 1: Two-sided significance test for a proportion.
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Page 511, P33 Conditions: (1) Problem states this was random sample
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Page 511, P33 Conditions: (1) Problem states this was random sample
(2) npo = 500(0.5) = 250 and n(1 – po) = 500(0.5) = 250 are both at least 10
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Page 511, P33 Conditions: (1) Problem states this was random sample
(2) npo = 500(0.5) = 250 and n(1 – po) = 500(0.5) = 250 are both at least 10 (3) Total number of bookstores in U.S. is greater than 10(500) = 5000.
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Page 511, P33 Step 2: State hypotheses.
Ho: p = 0.5, where p is proportion of all U.S. bookstores that sell DVDs
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Page 511, P33 Step 2: State hypotheses.
Ho: p = 0.5, where p is proportion of all U.S. bookstores that sell DVDs Ha: p ≠ 0.5
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Page 511, P33 Step 3: Compute test statistic and draw sketch
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Page 511, P33 Step 3: Compute test statistic and draw sketch
1-PropZTest po: 0.5 x: 265 n: 500 prop ≠ po
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Page 511, P33 Step 3: Compute test statistic and draw sketch
1-PropZTest po: 0.5 x: z ≈ 1.34 n: P-value ≈ 0.18 prop ≠ po
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Page 511, P33 Not given level of significance so use = 0.05 and critical values of z* = ± 1.96 Step 3 (con’t):
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Page 511, P33 Step 4: Write conclusion in context.
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Page 511, P33 Step 4: Write conclusion in context.
I do not reject the null hypothesis because the P-value of 0.18 is greater than the significance level of a = 0.05.
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Page 511, P33 Step 4: Write conclusion in context.
I do not reject the null hypothesis because the P-value of 0.18 is greater than the significance level of a = 0.05. There is not sufficient evidence to support the claim that the proportion of bookstores in the U.S. that sell DVDs is not half.
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Page 513, P42 Hypotheses?
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Page 513, P42 Ho: p = 0.5, where p is the proportion of adults in the U.S. who say they are satisfied with the quality of K-12 education in the nation.
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Page 513, P42 Ho: p = 0.5, where p is the proportion of adults in the U.S. who say they are satisfied with the quality of K-12 education in the nation. Ha: p < 0.5 Does this imply that less than a majority are satisfied?
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Page 512, P35
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Page 512, P35 B. The proportion of all households that are multigenerational this year.
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Page 513, E25 Which of these is not a true statement?
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Page 513, E25 Which of these is not a true statement?
(The 95% confidence interval is 0.82 to 0.96). D. If 75% of all dogs wear a collar, then you are reasonably likely to get a result like the one from this sample.
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Page 515, E35
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Page 515, E35 Suppose the newspaper’s percentage is actually right.
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Page 515, E35
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Page 515, E36
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Page 515, E36 Suppose the newspaper’s percentage is actually wrong.
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Page 515, E36 Suppose the newspaper’s percentage is actually wrong.
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Page 516, E41
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Page 516, E41
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Page 516, E41
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Page 516, E41
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Page 516, E41
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Page 511, P28
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Page 511, P28 B. Assuming that Ho is true, the P-value is the probability of observing a value of a test statistic at least as far out in the tails of the sampling distribution as is the value of the test statistic, z, from your sample.
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Questions?
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Suppose that in a random sample of 500 households, you find that 309 households have a computer.
Test the claim that 56.5% of all households in the United States have a computer. Use a significance level of α = 0.01.
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Name of Test This is a two-sided significance test for a proportion.
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Conditions 1) We are told this is a random sample from a binomial population.
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Conditions 1) We are told this is a random sample from a binomial population. 2) npo = 500(0.565) = 282.5 n(1 – po) = 500(0.435) = 217.5; so both are at least 10
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Conditions 1) We are told this is a random sample from a binomial population. 2) npo = 500(0.565) = 282.5 n(1 – po) = 500(0.435) = 217.5; so both are at least 10 3) the number of households in the U.S. is at least 10(500) = 5000
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Hypotheses Ho: p = 0.565, where p is the proportion of households in the U.S. that have a computer
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Hypotheses Ho: p = 0.565, where p is the proportion of households in the U.S. that have a computer Ha: p
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Suppose that in a random sample of 500 households, you find that 309 households have a computer.
Test the claim that 56.5% of all households in the United States have a computer. Use a significance level of α = 0.01.
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Test Statistic and P-value
1-PropZTest po: 0.565 x: 309 n: 500 prop po
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Test Statistic and P-value
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Conclusion Do not reject the null hypothesis at the 0.01 significance level because the P-value of is greater than 0.01. There is not sufficient evidence to support the claim that the percent of all households in the U.S. that have computers is not 56.5%.
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Conclusion Do not reject the null hypothesis at the 99% confidence level because the test statistic of ± 2.39 is within the critical values interval of ± There is not sufficient evidence to support the claim that the percent of all households in the U.S. that have computers is not 56.5%.
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