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Remember to look for “basics”
Circle Theorem Remember to look for “basics” Angles in a triangle sum to 1800 Angles on a line sum to 1800 Isosceles triangles (radius) Angles about a point sum to 3600
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Name parts of a circle tangent Diameter radius chord
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MUST BE THE CENTER 400 800 THEOREM 1: ANGLE at the CENTRE of the CIRCLE is twice the angle at the circumference subtended by the same arc
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This rule can be hard to spot…..
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THIS IS THE ONE MOST PEOPLE DON’T SEE......
MUST BE THE CENTER 1150 2300 THIS IS THE ONE MOST PEOPLE DON’T SEE......
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LOOKS DIFFERENT BUT STILL THE CENTRE
800 400 LOOKS DIFFERENT BUT STILL THE CENTRE
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900 1800 SPECIAL CASE OF THE SAME RULE……… BUT MAKES A RULE IN ITS OWN RIGHT!!
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900 THEOREM 2: Every angle at the circumference of a SEMICIRCLE, that is subtended by the diameter of the semi-circle is a right angle.
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PALE BLUE AREA IS THE SEGMENT
RULE 3: Angles at the circumference in the same SEGMENT of a circle are equal
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PALE BLUE AREA IS THE SEGMENT
RULE 3: Angles at the circumference in the same SEGMENT of a circle are equal
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THEOREM 3: Angles at the circumference in the same SEGMENT of a circle are equal
NOTE: Will lead you to SIMILAR triangles (one is an enlargement of the other….)
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THEOREM 4: Opposite angles sum to 180 in a cyclic quadrilateral
CYCLIC QUADRILATEARAL MUST touch the circumference at all four vertices 890 1100 700 910 THEOREM 4: Opposite angles sum to 180 in a cyclic quadrilateral
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Enter the world of tangents and chords…..
A tangent is a line that touches a circle at one point only. This point is called the point of contact. A chord is a line that joins two points on the circumference. tangent chord
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Theorem 5 – A tangent is perpendicular to a radius
900 radius
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Theorem 6 – Tangents to a circle from the same point are equal in length
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Theorem 7 – The line joining an external point to the centre of a circle bisects the angle between the tangents 350 700 350
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Theorem 5&7 – combined can help you find the missing angles…..
900 x 350 700 350 y 900
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Theorem 8 – A radius bisects a chord at 900
MIDPOINT OF THE CHORD chord 900 radius And the chord will be cut perfectly in half!!!
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Theorem 9 – Alternate angle theorem
Need a tangent And a triangle that joins the tangent and two other points on the circumference of the circle
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Theorem 9 – Alternate angle theorem
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Theorem 9 – Alternate angle theorem
The angle between a tangent and a chord Is equal to the angle in the alternate segment
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Theorem 9 – Alternate angle theorem
The angle between a tangent and a chord Is equal to the angle in the alternate segment
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COMMON EXAM ERROR! IT IS ONLY A DIAMETER IF YOU ARE TOLD SO…
IS TO THINK THIS IS A DIAMETER – SO.. THIS MUST BE 900 – “TANGENT MEETS RADIUS” READ QUSETIONS CAREFULLY..
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Hope this has been useful – if you are still stuck, double check your “basics” from slide 2.
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