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Variation Algebra 2/Trig Unit 3 Day 1
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Variation Relationship between two or more variables using ONLY multiplication or division Equation uses k (a variation constant) to express the relationship between the two variables
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Direct Variation π¦= 1 5 π₯ π¦=3π₯ π=3 π= 1 5 Equation: π¦=ππ₯
Alternative: π= π¦ π₯ Phrase: x and y vary directly In an x-y table, As x increases, y increases β absolute value of k is > 1 As x decreases, y decreases β absolute value of k is < 1 X Y 1 3 2 6 9 4 12 5 15 X Y 30 6 25 5 15 3 1 π¦= 1 5 π₯ π= 1 5 π¦=3π₯ π=3
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Inverse Variation π¦= 30 π₯ π=30 Equation: π¦= π π₯ Alternative: π=π¦π₯
Phrase: x and y vary inversely In an x-y table, As x increases, y decreases βabsolute value of k is >1 As x decreases, y increases βabsolute value of k is <1 π¦= π₯ = 1 2 β 1 π₯ π= π ππ π= 1 2 X Y 10 0.05 8 0.0625 3 0.1 6 2 0.25 X Y 5 6 4 7.5 3 10 2 15 1 30 π¦= 30 π₯ π=30
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Joint Variation Direct Equation: π=πππ Phrase: z varies joint directly with x and y Inverse Equation: π= π ππ Phrase: z varies joint inversely with x and y Now that you have notes on direct, inverse, and joint variation, log in to the Socrative to answer a few questions. The questions refer to #1-8 on the top of the next page in your notes. When you finish the Socrative, come back to the powerpoint slides.
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Neither Variation β relationships between x and y that use more than just multiplication or division
Linear Equations - π¦=ππ₯+π Quadratic Equations - π¦=π π₯ 2 +ππ₯+π
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Determining k values π= π ππ β k = π π π=ππβ k = 5
Now that you know the type of variation for each example #1-8, state the k value for the variation. Just as a reminder: π= π ππ β k = π π π=ππβ k = 5
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Want to stop here and try the examples on your own?
Yes β close the powerpoint, log off your computer and return it to the cart. No β keep clicking through the slides to see the examples and copy them into your notes
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Example 9 Calculate the value of k. Write the equation, and then solve for y given a value of x. a. The variables x and y vary inversely, when x = 5 then y = 8. Inverse equation β π¦= π π₯ Sub in values given β 8= π 5 Solve for k β 5β8= π 5 β5 40=π Write the equation β π¦= 40 π₯ b. Find the value of y when x = -2. π¦= 40 π₯ π¦= 40 β2 π¦=β20
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Examples 10, 11, 12 Determine the type and equation given the table.
Complete the columns for π¦ π₯ and π¦βπ₯. Use the information above to decide if the variation is direct, inverse, or neither. If it is direct or inverse, the value you found that was the same for every row is the k value in the equation. DIRECT VARIATION π¦ π₯ = the same number for every row of the table INVERSE VARIATION π¦βπ₯ = the same number for every row of the table
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All done! Close the powerpoint Log off Return the laptop to the cart
Pick up a practice worksheet and continue with those problems
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