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8-4 Properties of Logarithms
Hubarth Algebra II
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Properties of Logarithms
For any positive number π, π, and π, πβ 1, ππ π π ππ=ππ π π π+ππ π π π Product Property πππ π π π = πππ π πβ πππ π π Quotient Property πππ π π π₯ =π₯ πππ π π Power Property
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Ex. 1 Identify the Properties of Logarithms
State the property or properties used to rewrite each expression. π. logβ‘6 = logβ‘2 + logβ‘3 Product Property: log 6 = log (2β’3) = log 2 + log 3 b. ππ π π π₯ 2 π¦ =2ππ π π π₯β πππ π π¦ Quotient Property: logb = logb x2 β logb y x2 y Power Property: ππππ π₯2 β ππππ π¦ = 2 ππππ π₯ β ππππ π¦
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Ex. 2 Simplifying Logarithms
Write each logarithmic expression as a single logarithm. a. log4 64 β log4 16 log4 64 β log4 16 = log4 Quotient Property 64 16 = log4 4 = Simplify. b. 6 log5 x + log5 y 6 log5 π₯ + log5 π¦ = log5 π₯6 + log5 π¦ Power Property = log5 (π₯6π¦) Product Property ππ log4 64 β log4 16 = log4 4, πππ 6 log5 π₯ + log2 π¦ = log5 (π₯6π¦).
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Ex. 3 Expanding Logarithms
Expand each logarithm. a. πππ 7 ( π‘ π’ ) = log7 t β log7 u Quotient Property b. logβ‘(4π3) = logβ‘4 + logβ‘π3 Product Property = logβ‘4 + 3 logβ‘π Power Property
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Practice State the property or properties used to rewrite each expression. a. πππ 5 2+ πππ 5 6= πππ b. 3 πππ π 4β3 πππ π 2= πππ π 8 Product Property Power Property Quotient Property 2. Write 3 log 2+πππ4βπππ16 as a single logarithm. logβ‘2 3. Can you write 3 πππ 2 9β πππ 6 9 as a single logarithm? Explain. No, they have different bases 4. Expand each logarithm. a. πππ 2 7π b. πππ ( π¦ 3 ) 2 c. πππ 7 π 3 π 4 πππ 2 7+ πππ 2 π 2 log π¦ β2 log 3 3 πππ 7 π+4 πππ 7 π
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