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Notes 4 ECE 3318 Applied Electricity and Magnetism Spring 2017

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1 Notes 4 ECE 3318 Applied Electricity and Magnetism Spring 2017
Prof. David R. Jackson ECE Dept. Notes 4 Notes prepared by the EM Group University of Houston

2 The electric-field vector is the force vector for a unit charge.
+ - Note: The “test” charge is small enough so that it does not disturb the charge on the capacitor and hence the field from the capacitor. so The electric-field vector is the force vector for a unit charge. Units of electric field: [V/m]

3 Electric Field (cont.) Note: The electric-field vector may be non-uniform. Point charge q in free space:

4 Voltage Drop The voltage drop between two points is now defined. Volta
Comment: In statics, the line integral is independent of the shape of the path. (This will be proven later after we talk about the curl.)

5 Voltage Drop (Cont.) We now explore the physical interpretation of voltage drop. A test charge is moved from point A to point B at a constant speed (no increase in kinetic energy).

6 Voltage Drop (cont.) W ext = work done by observer in moving the charge. Hence

7 Voltage Drop (cont.) From the last slide: But we also have so or

8 Physical Interpretation of Voltage
Result: Conclusion: The voltage drop is equal to the change in potential energy of a unit test charge.

9 Parallel-plate capacitor
Physical Interpretation of Voltage Example: Point A is at a higher voltage, and hence a higher potential energy, than point B. + - Parallel-plate capacitor

10 Comments The electric field vector points from positive charges to negative charges. Positive charges are at a higher voltage, and negative charges are at a lower voltage. The electric field points from higher voltage to lower voltage. + -

11 The limits are vector points.
Review of Doing Line Integrals In rectangular coordinates, Hence Note: The limits are vector points. so Each integrand must be parameterized in terms of the respective integration variable. This requires knowledge of the path C.

12 Ideal parallel-plate capacitor assumption.
Example + - Find: E Assume: Ideal parallel-plate capacitor assumption.

13 Example (cont.) Evaluate in rectangular coordinates:

14 Example (cont.) Recall that Hence, we have

15 Example + - A proton is released at point A on the top plate with zero velocity. Find the velocity v(x) of the proton at distance x from the top plate (at point B). Conservation of energy:

16 Example (cont.) Hence: so

17 Example (cont.) V0 = 9 [V] h = 0.1 [m] q = 1.602 x 10-19 [C]
(See Appendix B of the Hayt & Buck book or Appendix D of the Shen & Kong book.) m = x [kg] Hence:

18 Note: 0 is often chosen to be zero, but this is not necessary.
Reference Point A reference point R is a point where the voltage is assigned. This makes the voltage unique at all points. The voltage at a given point is often called the potential . Integrating the electric field along C will determine the potential at point r. Note: 0 is often chosen to be zero, but this is not necessary.

19 Example + - Find the potential on the left terminal (cathode) assuming R is on right terminal (anode) and  = 0 at the reference point. + -

20 Example + - Find the potential on the right terminal (anode) assuming R is on left terminal (anode) and  = 0 at the reference point. + - This is the more usual choice for the reference point (on the negative terminal).

21 Example + - Find the potential function at x, 0 < x < h, assuming that the reference point R is on the bottom plate, and the voltage at R is zero. Also, Hence


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