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Analysis of Linear and quadratic polynomials

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Presentation on theme: "Analysis of Linear and quadratic polynomials"— Presentation transcript:

1 Analysis of Linear and quadratic polynomials
L(x) = ax + b, x a variable; a, b unspecified constants Basic question: determine when L(x) < 0 , L(x) = 0, L(x) >0 In terms of a and b We can work this out geometrically, using the x-intercept and slope of L(x):

2 Question: For what values of x is L(x) = 3*x – 8 positive?
Question: Suppose a line is given parameterically: x = 5t + 2, y = -3t + 4 For what values of x is y positive?

3 Question: Suppose L(x) = 4x – 3hx + d.
For what values of x is L(x) < 0?

4 Problem: The weight w(t) of an object is a linear polynomial
in t. It is found by experiment that w(4) = 29 and w(7) = 29 – 1/10. For what values of t is w(t) >0?

5 Quadratic case: Q(x) = ax^2 + bx + c For what values of x is Q(x) positive? For what values of x is Q(x) negative? Case 1: If Q(x) factors into a(x-u)(x-v) we can easily answer it: Need this basic fact: The product of a bunch of numbers is negative When an ____ number of them are negative.

6 Problem: For what values of x is Q(x)= -3/7(x-8)(x+5) negative?

7 Use of completing the square to handle the general case.
Completing the square on x^2 + cx

8 Example: For what values of x is x^2 + 4x – 7 positive?

9 Extreme points of quadratics: a number p is called an extreme point of
the quadratic Q(x) = ax^2 + bx + c if Q(p) >= Q(x) for all x or Q(p) <= Q(x) for all x. In the first case, Q(p) is a maximum value of Q(x) In the second case, Q(p) is minimum value.

10 Theorem: For the quadratic Q(x) = ax^2 + bx + c, the number p = -b/(2a)
Is the extreme point of Q(x). Furthermore, Q(p) is a maximum if a < 0 and a minimum if a > 0.

11 Application: A ball is thrown into the air by a 5 foot thrower.
At time t, its height above the ground is h(t) = -16t^2 + 50t + 5. when does it get to its highest point, how high is it then, and when does it hit the ground ?

12 Problem: A quadratic Q(x) has an extreme Q(3) = 5 and a root Q(7) = 0. Find Q(0).


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