Download presentation
Presentation is loading. Please wait.
Published byMuriel Logan Modified over 6 years ago
1
PHYSICS 231 Lecture 23: material science and pressure
liquid solid gas Remco Zegers Walk-in hour: Monday 9:15-10:15 am Helproom PHY 231
2
States of matter PHY 231
3
Phase transformations
PHY 231
4
solids ordered crystalline amorphous PHY 231
5
The deformation of solids
Stress: Tells something about the force causing the deformation Strain: Measure of the degree of deformation For small stress, strain and stress are linearly correlated. Strain = Constant*Stress Constant: elastic modulus The elastic modulus depends on: Material that is deformed Type of deformation (a different modulus is defined for different types of deformations) PHY 231
6
The Young’s modulus Beyond the elastic limit an object
is permanently deformed (it does not return to its original shape if the stress is removed). PHY 231
7
example An architect wants to design a 5m high circular pillar with
a radius of 0.5 m that holds a bronze statue that weighs 1.0E+04 kg. He chooses concrete for the material of the pillar (Y=1.0E+10 Pa). How much does the pillar compress? 5m PHY 231
8
Ultimate strength Ultimate strength: maximum force per unit area a material can withstand before it breaks or fractures. Different for compression and tension. PHY 231
9
example A builder is stacking 1 m3 cubic concrete blocks. Each blocks
weighs 5E+03 kg. The ultimate strength of concrete for compression is 2E+07 Pa. How many blocks can he stack before the lowest block is crushed? PHY 231
10
The Shear Modulus x PHY 231
11
Moving earth crust 100 m 30 m A tectonic plate in the lower crust (100 m deep) of the earth is shifted during an earthquake by 30m. What is the shear stress involved, if the upper layer of the earth does not move? (S=1.5E+10 Pa) PHY 231
12
Bulk Modulus Compressibility: 1/(Bulk modulus) PHY 231
13
example What force per unit area needs to be applied to compress
1 m3 water by 1%? (B=0.21E+10 Pa) PHY 231
14
Some typical elastic moduli
PHY 231
15
Density PHY 231
16
Pressure Pressure=F/A (N/m2=Pa) Same Force, different pressure PHY 231
17
example A nail is driven into a piece of wood with a force of 700N.
What is the pressure on the wood if Anail=1 mm2? A person (weighing 700 N) is lying on a bed of such nails (his body covers 1000 nails). What is the pressure exerted by each of the nails? PHY 231
18
Fpressure-difference= PA
Force and pressure Air (P=1.0E+5 Pa) P=0 Vacuum A F What is the force needed to move the lit? Force due to pressure difference: Fpressure=PA If A=0.01 m2 (about 10 by 10 cm) then a force F=(1.0E+5)*0.01=1000N is needed to pull the lit. Fpressure-difference= PA PHY 231
19
Magdeburg’s hemispheres
Otto von Guericke (Mayor of Magdeburg, 17th century) PHY 231
20
Pascal’s principle Pascal’s principle: a change in pressure applied
to a fluid that is enclosed is transmitted to the whole fluid and all the walls of the container that hold the fluid. HOLDS FOR A FLUID FULLY ENCLOSED ONLY PHY 231
21
Pascal’s principle In other words then before: a change in pressure applied to a fluid that is enclosed in transmitted to the whole fluid and all the walls of the container that hold the fluid. P=F1/A1=F2/A2 If A2>>A1 then F2>>F1. So, if we apply a small force F1, we can exert a very large Force F2. Hydraulic press demo PHY 231
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.