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Session 10 – Straight Line Graphs
GCSE Maths
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Coordinates Graphs contain 2 axes, the horizontal one is called the x axis, the vertical is called the y axis (x,y) like a claw-grab machine move horizontal then vertical So the coordinate (3,2) is three horizontal then 2 vertical
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The line y=x What are the coordinates of all the points on this line?
We can also use a table to show these values What is y when x = -1 x -1 1 2 3 4 y
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So there are 4 quadrants, and both x and y can have negative values
The point (0,0) is called the origin
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At every point on the x axis, y = 0
At every point on the y axis, x = 0 Draw a set of axes from -5 to 5 Draw the line y = 2 Draw the line x = 3 Draw the line y = -1 Draw the line x = -2 Draw the line y = 0 Draw the line x = 0
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Drawing graphs of linear functions
Linear functions in general come in the form: y=mx = c This will always produce a straight line. m is the gradient of the line (how steep it is) c is the point where the line crosses the y axis. (also known as the y-intercept)
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Drawing graphs of linear functions
When we know the equation of the line we can create a table for it. Populate the table with the values of at least 2 points (3 is better) Plot these points on a graph Join the points with a straight line
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Exercise 14.1 Q1, Q2, Q4, Extension Q11 and Q12 Group activity – on the board complete activity on page 125
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The gradient (m) The gradient of a line is found by dividing the distance up by the distance along Demonstrate the line y = 3x y=mx = c , in this case the gradient is 3, so m is 3 x -1 1 2 3 4 y -3 6 9 12
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The intercept (c) In y =mx + c Imagine that x = 0
Remember x = 0 along the y axis. When x = 0, mx = 0 so you are left with the equation y = c, so the coordinate shows the point where a straight line crosses the y axis is (0, c) Exercise 14.2 Q2, Q3, Q4 Extension Q12
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The gradient intercept method
If you have an equation of a line, you can substitute x= 0 and find where it crosses the y axis You can also substitute y=0 and to find where it crosses the x axis Now you have 2 points, you can use this to draw the line (unless they both come to 0, then you’ll need another point aswell) Exercise 14.3 Q1 Extension Q5
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Solve linear equations with graphs
Lines with different gradients will cross each other. Here are 2 lines with different gradients y = x and y = 8 - x Where the lines cross, the y value and the x value will be the same in both equations If we substitute the y out, we end up with x + 1 = 8 – x We could use algebra to solve for x, or we can draw the lines on a graph and take the coordinates of where they cross on a graph Ex 14.4 Q1
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Parallel and perpendicular gradients
Gradients of a parallel line is the sme Gradients of a perpendicular line is minus the reciprocal Create an example from gradient of y = 2x The gradients of perpendicular lines always multiply together to give -1 Ex 14.5 Q2 Extension Q6
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Rearranging equations
Sometimes the equations of straight lines are given in other forms. E.g. px + qy = r You will be asked to rearrange them into the form y=mx+c This will come up in the test, so practice a few from Ex14.6
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Homework Make notes on the ‘what you need to know’ section on page 134
Try a few from review exercise 14 Remember the section reviews which need to be handed in.
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Section Review Deadlines
Number Section Review - 9th December Algebra Section Review – 6th January Shape Space and Measure Section Review – 14th April Data Handling Section Review – 5th May
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