1. Chapter 10
Created by Bethany Stubbe and Stephan Kogitz

2. Two-Sample Tests of Hypothesis
Chapter Ten
Two-Sample Tests of Hypothesis
GOALS
When you have completed this chapter, you will be able to:
ONE
Conduct a test of hypothesis about the difference between two independent populations means.
TWO
Conduct a test of hypothesis about the difference between two population proportions.

3. Two Sample Tests of Hypothesis
Chapter Ten continued
Two Sample Tests of Hypothesis
GOALS
When you have completed this chapter, you will be able to:
THREE
Conduct a test of a hypothesis about the mean difference between paired or dependent observations.
FOUR
Understand the difference between dependent and independent samples.

4. Comparing two populations
We wish to know whether the distribution of the differences in sample means has a mean of 0.
If both samples contain at least 30 observations we use the z distribution as the test statistic.

5. Comparing Two Population Means
No assumptions about the shape of the populations are required.
The samples are from independent populations.

6. Comparing Two Population Means
The formula for computing the value of z is:

7. EXAMPLE 1
Two cities, Bradford and Kane, are separated only by the Conewango River. There is competition between the two cities. The local paper recently reported that the mean household income in Bradford is $38,000 with a standard deviation of $6,000 for a sample of 40 households. The same article reported the mean income in Kane is $35,000 with a standard deviation of $7,000 for a sample of 35 households. At the .01 significance level, can we conclude the mean income in Bradford is more?

8. EXAMPLE 1 continued Step 1: State the null and alternate hypotheses.
H0: µB ≤ µK ; H1: µB > µK
Step 2: State the level of significance. The .01 significance level is stated in the problem.

9. EXAMPLE 1 continued
Step 3: Find the appropriate test statistic. Because both samples are more than 30, we can use z as the test statistic.
Step 4: State the decision rule. The null hypothesis is rejected if z is greater than

10. Example 1 continued
Step 5: Compute the value of z and make a decision.

11. Example 1 continued The p-value is:
The decision is to not reject the null hypothesis. We cannot conclude that the mean household income in Bradford is larger.
The p-value is:
P(z > 1.98) = = .0239

12. Two Sample Tests of Proportions
We investigate whether two samples came from populations with an equal proportion of successes.

13. Two Sample Tests of Proportions
The two samples are pooled using the following formula.
where X1 and X2 refer to the number of successes in the respective samples of n1 and n2.

14. Two Sample Tests of Proportions
The value of the test statistic is computed from the following formula.

15. Example 2
Are unmarried workers more likely to be absent from work than married workers? A sample of 250 married workers showed 22 missed more than 5 days last year, while a sample of 300 unmarried workers showed 35 missed more than five days. Use a .05 significance level.

16. Example 2 continued
The null hypothesis is rejected if the computed value of z is greater than 1.65.
The pooled proportion is

17. Example 2 continued The null and the alternate hypothesis are:
H0: πU ≤ πM H1: πU > πM

18. Example 2 continued
The value of the test statistic is

19. Example 2 continued
The null hypothesis is not rejected. We cannot conclude that a higher proportion of unmarried workers miss more days in a year than the married workers.
The p-value is:
P(z > 1.10) = = .1457

20. Small Sample Tests of Means
The t distribution is used as the test statistic if one or more of the samples have less than 30 observations.

21. Small Sample Tests of Means
The required assumptions are:
1. Both populations must follow the normal distribution.
2. The populations must have equal standard deviations.
3. The samples are from independent populations.

22. Small sample test of means continued
Finding the value of the test statistic requires two steps.
1. Pool the sample standard deviations.

23. Small sample test of means continued
2. Determine the value of t from the following formula.

24. EXAMPLE 3
A recent consumer study compared the battery life of two brands of portable CD players. A sample of 15 Brand A players revealed a mean of 33.7 hours with a standard deviation of 2.4 hours. A sample of 12 Brand B players revealed a mean of 35.7 hours with a standard deviation of At the .05 significance level can we conclude that the battery life is higher in Brand B players?

25. Example 3 continued Step 1: State the null and alternate hypotheses.
H0: µD ≥ µI ; H1: µD < µI
Step 2: State the level of significance.The .05 significance level is stated in the problem.

26. Example 3 continued
Step 3: Find the appropriate test statistic. Both samples are less than 30, so we use the t distribution.
Step 4: The decision rule is to reject H0 if
t< There are 25 degrees of freedom.

27. EXAMPLE 3 continued
Step 5: We compute the pooled variance:

28. Example 3continued
We compute the value of t as follows.

29. Example 3 continued
H0 is not rejected. There is insufficient sample evidence to claim a higher battery life in Brand B CD players.

30. Hypothesis Testing Involving Paired Observations
Dependent samples are samples that are paired or related in some fashion. For example:
If you wished to buy a car you would look at the same car at two (or more) different dealerships and compare the prices.
If you wished to measure the effectiveness of a new diet you would weigh the dieters at the start and at the finish of the program.

31. Hypothesis Testing Involving Paired Observations
Use the following test when the samples are dependent:
where is the mean of the differences, sd is the standard deviation of the differences, and n is the number of pairs (differences)

32. EXAMPLE 4
An independent testing agency is comparing the daily rental cost for renting a compact car from Hertz and Avis. A random sample of eight cities revealed the following information. At the .05 significance level can the testing agency conclude that there is a difference in the rental charged?

33. Example 4 City Hertz Avis Edmonton $42 $40 Calgary 56 52 Fredericton45 43
Montreal 48
Regina 37 32
Toronto
Saint John 41 39
Vancouver 46 50

34. EXAMPLE 4 continued
The null hypothesis and the alternate hypothesis are:Step 1:
H0 is rejected if t < or t > We use the t distribution with 7 degrees of freedom.

35. Example 4 continued City Hertz Avis d d2 Calgary 42 40 2 4
Charlottetown
Fredericton
Montreal
Regina
Toronto
Saint John
Vancouver

36. Example 4 continued

37. Example 4 continued
Because is less than the critical value, do not reject the null hypothesis. There is no difference in the mean amount charged by Hertz and Avis.