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Force acting on a charged particle moving through a magnetic field
© D Hoult 2008
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Consider a conductor of length L, having n free electrons per unit volume. A current, I is flowing through it
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Consider a conductor of length L, having n free electrons per unit volume. A current, I is flowing through it
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In this piece of conductor there are
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In this piece of conductor there are NAL free electrons
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In this piece of conductor there are NAL free electrons
If all these electrons pass through end x in time t then the current, I is given by
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In this piece of conductor there are NAL free electrons
If all these electrons pass through end x in time t then the current, I is given by n A L e t
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If there is a magnetic field of flux density B at 90° to the current, the conductor will experience a force of magnitude
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If there is a magnetic field of flux density B at 90° to the current, the conductor will experience a force of magnitude I L B
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If there is a magnetic field of flux density B at 90° to the current, the conductor will experience a force of magnitude I L B This is the sum of the forces on all the electrons, so the force F acting on each electron is given by
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If there is a magnetic field of flux density B at 90° to the current, the conductor will experience a force of magnitude I L B This is the sum of the forces on all the electrons, so the force F acting on each electron is given by I L B I B F = = n A L n A
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Substituting for I gives
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Substituting for I gives
n A L e B F = = t n A
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Substituting for I gives
n A L e B L e B F = = t n A t
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but L/t is
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but L/t is the (drift) velocity of the electrons
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but L/t is the (drift) velocity of the electrons
therefore
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but L/t is the (drift) velocity of the electrons
therefore F = e v B
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In general the magnitude of the force acting on a charged particle moving with velocity v, at 90° to a magnetic field of flux density B, is given by F = q v B where q is the charge on the particle
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If the particle moves at angle q to the field
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If the particle moves at angle q to the field
the magnitude of the component of its velocity at 90° to the field is
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If the particle moves at angle q to the field
the magnitude of the component of its velocity at 90° to the field is v cos a
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If the particle moves at angle q to the field
the magnitude of the component of its velocity at 90° to the field is v cos a = v sin q Therefore, in general F =
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If the particle moves at angle q to the field
the magnitude of the component of its velocity at 90° to the field is v cos a = v sin q Therefore, in general F = q v B sin q
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