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MATH:7450 (22M:305) Topics in Topology: Scientific and Engineering Applications of Algebraic Topology Oct 21, 2013: Cohomology Fall 2013 course offered through the University of Iowa Division of Continuing Education Isabel K. Darcy, Department of Mathematics Applied Mathematical and Computational Sciences, University of Iowa
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triangle-zigzag.py from dionysus import Simplex, ZigzagPersistence, \ vertex_cmp, data_cmp \ # ,enable_log complex = {Simplex((0,), ): None, # A Simplex((1,), ): None, # B Simplex((2,), ): None, # C Simplex((0,1), ): None, # AB Simplex((1,2), ): None, # BC Simplex((0,2), ): None, # CA Simplex((0,1,2), 5): None} # ABC
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print "Complex:" for s in sorted(complex.keys()): print s print triangle idarcy$ python2.7 triangle-zigzag.py Complex: <0> <1> <2> <0, 1> <1, 2> <0, 2> <0, 1, 2>
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#enable_log("topology/persistence")
zz = ZigzagPersistence() # Add all the simplices b = 1 for s in sorted(complex.keys(), data_cmp): print "%d: Adding %s" % (b, s) 1: Adding <0> 2: Adding <1> 3: Adding <2> 1 2
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# Add all the simplices b = 1 for s in sorted(complex.keys(), data_cmp): print "%d: Adding %s" % (b, s) i,d = zz.add([complex[ss] for ss in s.boundary], b) complex[s] = i if d: print "Interval (%d, %d)" % (d, b-1) b += 1
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i,d = zz.add([complex[ss] for ss in s.boundary], b) complex[s] = i
# Add all the simplices b = 1 for s in sorted(complex.keys(), data_cmp): print "%d: Adding %s" % (b, s) i,d = zz.add([complex[ss] for ss in s.boundary], b) complex[s] = i if d: print "Interval (%d, %d)" % (d, b-1) b += 1 4: Adding <0, 1> Interval (2, 3) 5: Adding <1, 2> Interval (3, 4) 6: Adding <0, 2> 7: Adding <0, 1, 2> Interval (6, 6) 1 2
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# Remove all the simplices
for s in sorted(complex.keys(), data_cmp, reverse = True): print "%d: Removing %s" % (b, s) d = zz.remove(complex[s], b) del complex[s] if d: print "Interval (%d, %d)" % (d, b-1) b += 1 8: Removing <0, 1, 2> 9: Removing <0, 2> Interval (8, 8) 10: Removing <1, 2> 11: Removing <0, 1> 1 2
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12: Removing <2> Interval (10, 11) 13: Removing <1> Interval (11, 12) 14: Removing <0> Interval (1, 13) 1 2
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NKI (2002) breast cancer data:
gene expression levels of 24,000 from 272 tumors Data = 272 points living in R24000
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NKI (2002) breast cancer data:
gene expression levels of 24,000 from 272 tumors Data = 272 points living in R24000 In reality one cleans the data first, removing unreliable data, etc. One may also remove dimensions (genes) that appear irrelevant.
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NKI (2002) breast cancer data:
gene expression levels of 24,000 from 272 tumors Data = 272 points living in R24000 Since our dataset consists of only 272 points, it can’t be dimensional.
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For example, suppose our very fake data is
{ (9, 8, 7, 6, 5, 4, 3, 2, 3) ti | i = 1, 2, 3, … 1000 } = { (9, 8, 7, 6, 5, 4, 3, 2, 3), { (18, 16, 14, 12, 10, 8, 6, 4, 6), … }
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Dimensionality Reduction:
Given dataset D RN Want: embedding f: D Rn where n << N which “preserves” the structure of the data. Example: { (9, 8, 7, 6, 5, 4, 3, 2, 3) ti | i = 1, 2, 3, … 1000 } R9 f: D R, f((9, 8, 7, 6, 5, 4, 3, 2, 3) ti) = ti U U
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Example: Principle component analysis (PCA)
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Many reduction methods:
f1: D R, f2: D R, … fn: D R (f1, f2, … fn): D Rn Many are linear, M: RN Rn, Mx = y But there are also non-linear dimensionality reduction algorithms.
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f1: D R, f2: D R, … fn: D R (f1, f2, … fn): D Rn
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Goal f1: D S1, f2: D S1, … fn: D S1
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Note S1 is a ring:
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Cohomology and circular coordinates:
Let X = finite simplicial complex. X0 = set of 0-simplices = vertices. X1 = set of 1-simplices = edges. X2 = set of 2-simplices = faces. . v2 e2 e1 e3 v1 v3
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Homology Let X = finite simplicial complex. C0 = set of 0-chains = linear combinations of vertices C1 = set of 1-chains = linear combinations of edges. C2 = set of 2-chains = linear combinations of faces. . v2 e2 e1 e3 v1 v3
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Cohomology and circular coordinates:
Let X = finite simplicial complex, R a ring. C0 = set of 0-cochains = { f : C0 R | f homomorphism} C1 = set of 1-cochains = { f : C1 R | f homomorphism} C2 = set of 2-cochains = { f : C2 R | f homomorphism} .
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Cohomology and circular coordinates:
Let X = finite simplicial complex, R a ring. C0(X, R) = set of 0-cochains = { f : X0 R } C1(X, R) = set of 1-cochains = { f : X1 R } C2(X, R) = set of 2-cochains = { f : X2 R } .
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→ Proposition 1: Let α ∈ C1(X;Z) be a cocycle.
Then there exists a continuous function θ : X → S1 which maps each vertex to 0, and each edge ab around the entire circle with winding number α(ab). v2 e2 e1 e3 v1 v3 →
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Proposition 2: 2 Let α ∈ C1(X;R) be a cocycle
Proposition 2: 2 Let α ∈ C1(X;R) be a cocycle. Suppose there exists α ∈ C1(X;Z) and f ∈ C0(X;R) such that α = α + d0f . Then there exists a continuous function θ : X → S1 which maps each edge ab linearly to an interval of length α(ab), measured with sign. v2 e2 e1 e3 v1 v3 →
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θ : X → R/Z = S1
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(d1α)(abc) = α(bc)− α(ac)+α(ab).
coboundary maps d0 : C0 = { f : X0 R } → C1 = { f : X1 R } (d0f )(ab) = f (b)− f (a) d1 : C1 = { f : X1 R } → C2 = { f : X2 R } (d1α)(abc) = α(bc)− α(ac)+α(ab).
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Let α ∈ Ci , di : Ci = { f : Xi R } → Ci+1 = { f : Xi+1 R } α is a cocycle if diα = 0. α is a coboundary if there exists f in Ci-1 s.t. di-1f = α Note d1 d0 f = 0 for any f ∈ C0. (d0f )(ab) = f (b) − f (a) (d1d0f )(abc) = d0f(bc) − d0f(ac) + d0f(ab) = d0f(c) - d0f(b) - d0f(c) + d0f(a) + d0f(b) - d0f(a)
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d1 d0 f = 0 implies Im (d0 ) ⊆ Ker (d1 ).
H1 (X;A ) = Ker (d1 )/ Im (d0 ). Two cocycles α,β are cohomologous if α − β is a coboundary.
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d1 d0 f = 0 implies Im (d0 ) ⊆ Ker (d1 ).
H1 (X;A ) = Ker (d1 )/ Im (d0 ). v2 e2 e1 e3 v1 v3
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d1 d0 f = 0 implies Im (d0 ) ⊆ Ker (d1 ).
H1 (X;A ) = Ker (d1 )/ Im (d0 ). v2 e2 e1 e3 v1 v3 0 C0 C1 0
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C0(X, R) = set of 0-cochains = { f : X0 R }
v2 e2 e1 e3 v1 v3
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C0(X, R) = set of 0-cochains = { f : X0 R }
= { f | f(v1) = r1, f(v2) = r2, f(v3) = r3; (r1, r2, r3) in R3 } C1(X, R) = set of 1-cochains = { f : X1 R } = { f | f(e1) = r1, f(e2) = r2, f(e3) = r3; (r1, r2, r3) in R3 } v2 e2 e1 e3 v1 v3
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Hi (X;A ) = Ker (di )/ Im (di-1 ).
C0(X, R) = set of 0-cochains = { f : X0 R } = { f | f(v1) = r1, f(v2) = r2, f(v3) = r3; (r1, r2, r3) in R3 } C1(X, R) = set of 1-cochains = { f : X1 R } = { f | f(e1) = r1, f(e2) = r2, f(e3) = r3; (r1, r2, r3) in R3 } Hi (X;A ) = Ker (di )/ Im (di-1 ). 0 C0 C1 0 v2 e2 e1 e3 v1 v3
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