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π₯=4, π¦=5 π₯=21, π=29 π= 10 , π₯=1 π¦=4 2 , π₯=4 Warm Up r y π= ππ x π=ππ
A right triangle has side lengths x, y, and r. Find the unknown length. r y π₯=4, π¦=5 π₯=21, π=29 π= 10 , π₯=1 π¦=4 2 , π₯=4 The square has side lengths 14. The two curves are each of a circle with radius 14. Find the area of the shaded region. π= ππ x π=ππ π=π π=π π πππ
βπππ
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Quiz 7.1 & 7.2 Degree & Radian Conversions Coterminal Angles
Arc Length of a Sector Area of a Sector Apparent Size
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Section 7-3 The Sine and Cosine Functions
Objective: To use the definitions of sine and cosine to find values of these functions and to solve simple trigonometric equations.
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π πππ= πππ βπ¦π = π¦ π r ο± πππ βπ¦π = π₯ π cos π=
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Example 1 If the terminal ray of an angle ΞΈ in standard position passes through (-3, 2), find sin ΞΈ and cos ΞΈ. Solution: On a grid, locate (-3,2). Use this point to draw a right triangle, where one side is on the x-axis, and the hypotenuse is line segment between (-3,2) and (0,0). Start of Day 2
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π= β3 2 + 2 2 π=βπ π= ππ π²=π = 2 13 13 = 2 13 π πππ= π¦ π = β3 13 13
= = π πππ= π¦ π = β = β3 13 πππ π= π₯ π π= β π=βπ π= ππ π²=π
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Example 2 If the π πππ=β 5 13 , what quadrant is the angle in?
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= 12 13 πππ π= π₯ π π²=βπ π=ππ π₯= β β5 2 π=ππ π=Β±ππ 4th Quadrant, so
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π πππ= cos π= π¦ π π₯ π πππ βπ¦π = πππ βπ¦π =
r ο± πππ βπ¦π = π₯ π cos π= When the radius =1 on the unit circle, π πππ= π¦ 1 =π¦ πππ π= π₯ 1 =π₯
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Unit Circle The circle x2 + y2 = 1 has radius 1 and is therefore called the unit circle. This circle is the easiest one with which to work because sin ΞΈ and cos ΞΈ are simply the y- and x-coordinates of the point where the terminal ray of ΞΈ intersects the circle. When the radius =1 on the unit circle, π πππ= π¦ 1 =π¦ πππ π= π₯ 1 =π₯
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1 1 2 1 2
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II I III IV (β,+) (+,+) (β,β) (+,β) On Your Unit Circle:
Label the quadrants. Note the positive or negative x and y values in each quadrant. (cos, sin) (cos, sin) (β,+) (+,+) II I III IV (β,β) (+,β) (cos, sin) (cos, sin)
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You can determine the exact value of sine and cosine for many angles on the unit circle.
1 -1 β 2 2 Find: sin 90Β° sin 450Β° cos (-Ο) sin (β 2π 3 ) cos -315Β° Refer to graph file βUC Quadrantal Anglesβ
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Example 3 Degrees: π=90ΛΒ±360π Radians: π= π 2 Β±2ππ
Solve sin ΞΈ = 1 for ΞΈ in degrees and radians. Degrees: π=90ΛΒ±360π Radians: π= π 2 Β±2ππ
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Repeating Sin and Cos Values
For any integer n, π ππ (π Β± 360Β°π) = π ππβ‘π πππ (π Β± 360Β°π) =πππ β‘π π ππ (π Β±2ππ) = π ππβ‘π πππ (π Β±2ππ) =πππ β‘π The sine and cosine functions are periodic. They have a fundamental period of 360Λ or 2ο° radians.
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Homework Page 272 #1-27 odd, #33-41 odd
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