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Centripetal Force.

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Presentation on theme: "Centripetal Force."— Presentation transcript:

1 Centripetal Force

2 Acceleration in a Circle
Acceleration is a vector change in velocity compared to time. For small angle changes the acceleration vector points directly inward. This is called centripetal acceleration. dq

3 Centripetal Acceleration
Uniform circular motion takes place with a constant speed but changing velocity direction. The acceleration always is directed toward the center of the circle and has a constant magnitude.

4 Buzz Saw A circular saw is designed with teeth that will move at 40. m/s. The bonds that hold the cutting tips can withstand a maximum acceleration of 2.0 x 104 m/s2. Find the maximum diameter of the blade. Start with a = v2/r. r = v2/a. Substitute values: r = (40. m/s)2/(2.0 x 104 m/s2) r = m. Find the diameter: d = 0.16 m = 16 cm.

5 Law of Acceleration in Circles
Motion in a circle has a centripetal acceleration. There must be a centripetal force. Vector points to the center The centrifugal force that we describe is just inertia. It points in the opposite direction – to the outside It isn’t a real force

6 Conical Pendulum A 200. g mass hung is from a 50. cm string as a conical pendulum. The period of the pendulum in a perfect circle is 1.4 s. What is the angle of the pendulum? What is the tension on the string? q FT

7 Radial Net Force The mass has a downward gravitational force, -mg.
There is tension in the string. The vertical component must cancel gravity FTy = mg FT = mg / cos q FTr = mg sin q / cos q = mg tan q This is the net radial force – the centripetal force. q FT cos q FT FT sin q mg

8 Acceleration to Velocity
The acceleration and velocity on a circular path are related. q FT r mg tan q mg

9 Period of Revolution The pendulum period is related to the speed and radius. q L FT r mg tan q cos q = 0.973 q = 13°

10 Radial Tension The tension on the string can be found using the angle and mass. FT = mg / cos q = 2.0 N If the tension is too high the string will break!


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