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Card Shuffling How many perfect shuffles will return a full deck

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Presentation on theme: "Card Shuffling How many perfect shuffles will return a full deck"— Presentation transcript:

1 Card Shuffling How many perfect shuffles will return a full deck
of cards to their original order?

2 Perfect Shuffle Divide 52 cards into 2 equal piles
Shuffle by interlacing cards Keep top card fixed (Out Shuffle) 8 shuffles => original order

3 For example

4 A Model for Card Shuffling
Label the positions 0-51 Then 0->0 and 26 ->1 1->2 and 27 ->3 2->4 and 28 ->5 … in general? f(x) = 2x mod 51

5 The Order of a Shuffle Minimum integer k such that 2 k x = x mod 51 for all x in {0,1,…,51} In particular, this has to hold when x = 1 Minimum integer k such that 2 k - 1= 0 mod 51 Thus, 51 divides 2 k - 1 k= 6, 2 k - 1 = 63 = (3)(3)(7) k= 7, 2 k - 1 = 127 (prime) k= 8, 2 k - 1 = 255 = (5)(51) = 0 mod 51

6 The Out Shuffle

7 The In Shuffle

8 Model for shuffling n Cards
p = position In Shuffles Out Shuffles

9 Order of a Shuffle 8 Out Shuffles for 52 Cards In General?
o (O,2n-1) = o (O,2n) o (I,2n-1) = o (O,2n) => o (O,2n-1) = o (I,2n-1) o (I,2n-2) = o (O,2n) Therefore, only need o (O,2n)

10 o (O,2n) = Order for 2n Cards
1 shuffle: O(p) = 2p mod (2n-1), 0<p<N-1 2 shuffles: O2(p) = 2 O(p) mod (2n-1) = 22 p mod (2n-1) k shuffles: Ok(p) = 2kp mod (2n-1) Order: o (O,2n) = smallest k such that Ok(p) = p mod (2n-1) for all p between 0 and 2n Which means 2k = 1 mod (2n-1) => (2n – 1) | (2k – 1)

11 The Orders of Perfect Shuffles
n o(O,n) o(I,n) n o(O,n) o(I,n)


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