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Derivatives of Exponential and Logarithmic Functions
Section 3.2 Derivatives of Exponential and Logarithmic Functions
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Exponential Growth What are some things you can think of that grow exponentially?
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Examples of Exponential Growth and Decay
Human Population growth (up to a pointβ¦)
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Examples of Exponential Growth and Decay
Growth of Bacteria in a Petri Dish (again, up to a point) Decay of radioactive atoms (Carbon-14) Removal of drugs from body Example: 50% of caffeine is removed from your body approximately every 4 hours
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Sec 3.2 Derivatives of Exponential and Logarithmic Functions
Formulas for derivatives of:
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Derivative of π π₯ = π π₯ Find fβ(1) for various values of h
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Derivative of π π₯ = π π₯ Find fβ(1) for various values of h
π β² 1 = lim ββ0 π(π₯+β)βπ(π₯) β = lim ββ0 π βπ(1) 0.1
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Derivative of π π₯ = π π₯ Find fβ(1) for various values of h
π β² 1 = lim ββ0 π βπ(1) =πππ ββ0 π β π =2.859
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Derivative of π π₯ = π π₯ Find fβ(1) for various values of h
π β² 1 =πππ ββ0 π β π =2.859 π β² 1 =πππ ββ0 π β π =2.732 Smaller value of h = 0.01
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Derivative of π π₯ = π π₯ Find fβ(1) for various values of h
π β² 1 =πππ ββ0 π β π =2.859 π β² 1 =πππ ββ0 π β π =2.732 π β² 1 =πππ ββ0 π β π =2.720 Smaller value of h = 0.001
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Derivative of π π₯ = π π₯ Find fβ(1) for various values of h
π β² 1 =πππ ββ0 π β π =2.859 π β² 1 =πππ ββ0 π β π =2.732 π β² 1 =πππ ββ0 π β π =2.720 π β² 1 =πππ ββ0 π β π =2.718 Smaller value of h =
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Derivative of π π₯ = π π₯ Find fβ(1) for various values of h
TheΒ number eΒ is a famous irrationalΒ number, and is one of the most importantΒ numbersΒ in mathematics. The first few digits are: (and more ...) It is often called Euler'sΒ numberΒ after Leonhard Euler.Β eΒ is the base of the Natural Logarithms (invented by John Napier). Find fβ(1) for various values of h π β² 1 =πππ ββ0 π β π =2.859 π β² 1 =πππ ββ0 π β π =2.732 π β² 1 =πππ ββ0 π β π =2.720 π β² 1 =πππ ββ0 π β π =2.718 π β² 1 =πππ ββ0 π β π =2.718 Getting close to βeβ
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Derivative Function of π π₯ = π π₯
Start with the limit definition of the derivative:
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Derivative Function of π π₯ = π π₯
Start with the limit definition of the derivative:
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Derivative Function of π π₯ = π π₯
Start with the limit definition of the derivative:
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Derivative Function of π π₯ = π π₯
Start with the limit definition of the derivative:
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Derivative Function of π π₯ = π π₯
Start with the limit definition of the derivative:
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Try various small values of h to find limiting value
-0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005 Try various small values of h to find limiting value
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h -0.01 -0.001 0.001 0.01 0.995 0.9995 1 1.0005 1.005 Limiting Value
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h -0.01 -0.001 0.001 0.01 0.995 0.9995 1 1.0005 1.005
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So h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005
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Example: h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005
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So Example: h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005
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So Example: h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005
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Derivative Function for π π₯ = π π₯
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Derivative Function for π π₯ = π π₯
Need the βchain ruleβ (coming up) to understand and prove (later)
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Derivative Function for π π₯ = π π₯
Examples:
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Derivative Function for π π₯ = π π₯
Examples:
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Derivative Function for π π₯ = π π₯
Examples:
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Derivative Function for π π₯ = π π₯
Examples:
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Derivative Function for π π‘ = π ππ‘
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Derivative Function for π π‘ = π ππ‘
Need the βchain ruleβ (coming up) to understand and prove (later)
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Derivative Function for π π‘ = π ππ‘
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Derivative Function for π π₯ =lnβ‘(π₯)
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Derivative Function for π π₯ =lnβ‘(π₯)
Will also prove after chain rule
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Derivative Function for π π₯ =lnβ‘(π₯)
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Derivative Function for π π₯ =lnβ‘(π₯)
Will also prove after chain rule
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Derivative Function for π π₯ =lnβ‘(π₯)
Will also prove after chain rule
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Derivative Function for π π₯ =lnβ‘(π₯)
Will also prove after chain rule
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Derivative Function for π π₯ =lnβ‘(π₯)
Will also prove after chain rule
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000.
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009?
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 πβππππ ππ ππππ’πππ‘πππ πβππππ ππ π‘πππ = ππ ππ‘
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 ππ ππ‘ = π ππ‘ π‘
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 ππ ππ‘ = π ππ‘ π‘ =2020 π ππ‘ π‘
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 ππ ππ‘ = π ππ‘ π‘ =2020 π ππ‘ π‘ =2020 lnβ‘(1.036) π‘
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 ππ ππ‘ = π ππ‘ π‘ =2020 π ππ‘ π‘ =2020 lnβ‘(1.036) π‘
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 ππ ππ‘ = π ππ‘ π‘ =2020 π ππ‘ π‘ =2020 ln =98.22
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Applications Example 1 Population of Nevada, P, in millions can be approximated by π= π‘ Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Solution million people/year ππ ππ‘ = π ππ‘ π‘ =2020 π ππ‘ π‘ =2020 ln =98.22
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Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is π π‘ =27 π β0.14π‘ ng/ml (nanograms/milliliter). What is the concentration 4 hours after it was administered? At what rate is the concentration changing at that time?
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Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is π π‘ =27 π β0.14π‘ ng/ml (nanograms/milliliter). What is the concentration 4 hours after it was administered? π 4 =27 π β0.14(4) =15.42 ππ/ππ
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Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is π π‘ =27 π β0.14π‘ ng/ml (nanograms/milliliter). At what rate is the concentration changing at that time? πβ² π‘ =27 (β0.14)π β0.14π‘
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Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is π π‘ =27 π β0.14π‘ ng/ml (nanograms/milliliter). At what rate is the concentration changing at that time? π β² (4)=27 β0.14 π β =β2.16 ππ ππ πππ βππ’π
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