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Derivatives of Exponential and Logarithmic Functions

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Presentation on theme: "Derivatives of Exponential and Logarithmic Functions"β€” Presentation transcript:

1 Derivatives of Exponential and Logarithmic Functions
Section 3.2 Derivatives of Exponential and Logarithmic Functions

2 Exponential Growth What are some things you can think of that grow exponentially?

3 Examples of Exponential Growth and Decay
Human Population growth (up to a point…)

4 Examples of Exponential Growth and Decay
Growth of Bacteria in a Petri Dish (again, up to a point) Decay of radioactive atoms (Carbon-14) Removal of drugs from body Example: 50% of caffeine is removed from your body approximately every 4 hours

5 Sec 3.2 Derivatives of Exponential and Logarithmic Functions
Formulas for derivatives of:

6 Derivative of 𝑓 π‘₯ = 𝑒 π‘₯ Find f’(1) for various values of h

7 Derivative of 𝑓 π‘₯ = 𝑒 π‘₯ Find f’(1) for various values of h
𝑓 β€² 1 = lim β„Žβ†’0 𝑓(π‘₯+β„Ž)βˆ’π‘“(π‘₯) β„Ž = lim β„Žβ†’0 𝑓 βˆ’π‘“(1) 0.1

8 Derivative of 𝑓 π‘₯ = 𝑒 π‘₯ Find f’(1) for various values of h
𝑓 β€² 1 = lim β„Žβ†’0 𝑓 βˆ’π‘“(1) =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.859

9 Derivative of 𝑓 π‘₯ = 𝑒 π‘₯ Find f’(1) for various values of h
𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.859 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.732 Smaller value of h = 0.01

10 Derivative of 𝑓 π‘₯ = 𝑒 π‘₯ Find f’(1) for various values of h
𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.859 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.732 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.720 Smaller value of h = 0.001

11 Derivative of 𝑓 π‘₯ = 𝑒 π‘₯ Find f’(1) for various values of h
𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.859 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.732 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.720 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.718 Smaller value of h =

12 Derivative of 𝑓 π‘₯ = 𝑒 π‘₯ Find f’(1) for various values of h
TheΒ number eΒ is a famous irrationalΒ number, and is one of the most importantΒ numbersΒ in mathematics. The first few digits are: (and more ...) It is often called Euler'sΒ numberΒ after Leonhard Euler.Β  eΒ is the base of the Natural Logarithms (invented by John Napier). Find f’(1) for various values of h 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.859 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.732 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.720 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.718 𝑓 β€² 1 =π‘™π‘–π‘š β„Žβ†’0 𝑒 βˆ’ 𝑒 =2.718 Getting close to β€œe”

13 Derivative Function of 𝑓 π‘₯ = 𝑒 π‘₯
Start with the limit definition of the derivative:

14 Derivative Function of 𝑓 π‘₯ = 𝑒 π‘₯
Start with the limit definition of the derivative:

15 Derivative Function of 𝑓 π‘₯ = 𝑒 π‘₯
Start with the limit definition of the derivative:

16 Derivative Function of 𝑓 π‘₯ = 𝑒 π‘₯
Start with the limit definition of the derivative:

17 Derivative Function of 𝑓 π‘₯ = 𝑒 π‘₯
Start with the limit definition of the derivative:

18 Try various small values of h to find limiting value
-0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005 Try various small values of h to find limiting value

19 h -0.01 -0.001 0.001 0.01 0.995 0.9995 1 1.0005 1.005 Limiting Value

20 h -0.01 -0.001 0.001 0.01 0.995 0.9995 1 1.0005 1.005

21 So h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005

22 Example: h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005

23 So Example: h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005

24 So Example: h -0.01 -0.001 0.001 0.01 0.995 0.9995 ? 1.0005 1.005

25 Derivative Function for 𝑓 π‘₯ = π‘Ž π‘₯

26 Derivative Function for 𝑓 π‘₯ = π‘Ž π‘₯
Need the β€œchain rule” (coming up) to understand and prove (later)

27 Derivative Function for 𝑓 π‘₯ = π‘Ž π‘₯
Examples:

28 Derivative Function for 𝑓 π‘₯ = π‘Ž π‘₯
Examples:

29 Derivative Function for 𝑓 π‘₯ = π‘Ž π‘₯
Examples:

30 Derivative Function for 𝑓 π‘₯ = π‘Ž π‘₯
Examples:

31 Derivative Function for 𝑓 𝑑 = 𝑒 π‘˜π‘‘

32 Derivative Function for 𝑓 𝑑 = 𝑒 π‘˜π‘‘
Need the β€œchain rule” (coming up) to understand and prove (later)

33 Derivative Function for 𝑓 𝑑 = 𝑒 π‘˜π‘‘

34 Derivative Function for 𝑓 π‘₯ =ln⁑(π‘₯)

35 Derivative Function for 𝑓 π‘₯ =ln⁑(π‘₯)
Will also prove after chain rule

36 Derivative Function for 𝑓 π‘₯ =ln⁑(π‘₯)

37 Derivative Function for 𝑓 π‘₯ =ln⁑(π‘₯)
Will also prove after chain rule

38 Derivative Function for 𝑓 π‘₯ =ln⁑(π‘₯)
Will also prove after chain rule

39 Derivative Function for 𝑓 π‘₯ =ln⁑(π‘₯)
Will also prove after chain rule

40 Derivative Function for 𝑓 π‘₯ =ln⁑(π‘₯)
Will also prove after chain rule

41 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000.

42 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009?

43 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9

44 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 π‘β„Žπ‘Žπ‘›π‘”π‘’ 𝑖𝑛 π‘π‘œπ‘π‘’π‘™π‘Žπ‘‘π‘–π‘œπ‘› π‘β„Žπ‘Žπ‘›π‘”π‘’ 𝑖𝑛 π‘‘π‘–π‘šπ‘’ = 𝑑𝑃 𝑑𝑑

45 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 𝑑𝑃 𝑑𝑑 = 𝑑 𝑑𝑑 𝑑

46 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 𝑑𝑃 𝑑𝑑 = 𝑑 𝑑𝑑 𝑑 =2020 𝑑 𝑑𝑑 𝑑

47 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 𝑑𝑃 𝑑𝑑 = 𝑑 𝑑𝑑 𝑑 =2020 𝑑 𝑑𝑑 𝑑 =2020 ln⁑(1.036) 𝑑

48 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 𝑑𝑃 𝑑𝑑 = 𝑑 𝑑𝑑 𝑑 =2020 𝑑 𝑑𝑑 𝑑 =2020 ln⁑(1.036) 𝑑

49 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Instantaneous Rate of Change at t = 9 𝑑𝑃 𝑑𝑑 = 𝑑 𝑑𝑑 𝑑 =2020 𝑑 𝑑𝑑 𝑑 =2020 ln =98.22

50 Applications Example 1 Population of Nevada, P, in millions can be approximated by 𝑃= 𝑑 Where t is years since the start of 2000. At what rate was the population growing at the beginning of 2009? Solution million people/year 𝑑𝑃 𝑑𝑑 = 𝑑 𝑑𝑑 𝑑 =2020 𝑑 𝑑𝑑 𝑑 =2020 ln =98.22

51 Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is 𝑓 𝑑 =27 𝑒 βˆ’0.14𝑑 ng/ml (nanograms/milliliter). What is the concentration 4 hours after it was administered? At what rate is the concentration changing at that time?

52 Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is 𝑓 𝑑 =27 𝑒 βˆ’0.14𝑑 ng/ml (nanograms/milliliter). What is the concentration 4 hours after it was administered? 𝑓 4 =27 𝑒 βˆ’0.14(4) =15.42 𝑛𝑔/π‘šπ‘™

53 Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is 𝑓 𝑑 =27 𝑒 βˆ’0.14𝑑 ng/ml (nanograms/milliliter). At what rate is the concentration changing at that time? 𝑓′ 𝑑 =27 (βˆ’0.14)𝑒 βˆ’0.14𝑑

54 Applications Example 2 At a time t hours after it was administered, the concentration of a drug in the body is 𝑓 𝑑 =27 𝑒 βˆ’0.14𝑑 ng/ml (nanograms/milliliter). At what rate is the concentration changing at that time? 𝑓 β€² (4)=27 βˆ’0.14 𝑒 βˆ’ =βˆ’2.16 𝑛𝑔 π‘šπ‘™ π‘π‘’π‘Ÿ β„Žπ‘œπ‘’π‘Ÿ


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