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Section 9.1: Three Dimensional Coordinate Systems

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1 Section 9.1: Three Dimensional Coordinate Systems
Practice HW from Stewart Textbook (not to hand in) p. 641 # 1, 2, 3, 7, 10, 11, 13, 14, 15b, 16

2 3-D Coordinate Axes z y x

3 Points are located using ordered triples (x, y, z).

4 Example 1: Plot the points (1, 1, 1), (2, 5, 0),
(-2, 3, 4), (1, 1, -4), and (2, -5, 3). Solution:

5 z y x

6 Note: The 3-D coordinate axes divides the
coordinate system into 3 distinct planes – the x-y plane z = 0, the y-z plane x = 0, and the x-z plane y = 0.

7

8

9

10 Suppose we are now given the two points and in 3D space.
z y x

11 Then

12 Example 2: Find the distance and midpoint
between the points (2, 1, 4) and (6, 5, 2). Solution:

13

14 Recall: An isosceles triangle is a triangle where
the lengths of two of its sides are equal. A right triangle is a triangle with a 90 degree angle where the sum of squares of the shorter sides equals the square of the hypotenuse.

15 c a x x b Icosceles Triangle Right Triangle

16 Example 3: Find the lengths of the sides of the
triangle PQR if P = (1, -3, -2), Q = (5, -1, 2) and R = (-1, 1, 2). Deterrmine if the resulting triangle is an isosceles or a right triangle. Solution: (In typewritten notes)

17 Standard Equation of a Sphere
z y x

18 Standard Equation of a Sphere
The standard equation of a sphere with radius r and center is given by In particular, if the center of the sphere is at the origin, that is, if , then the equation becomes

19 Fact: When the standard equation of a sphere is
expanded and simplify, we obtain the general equation of a sphere

20 General Equation of a Sphere

21 Example 4: Find the standard and general
equation of a sphere that passes through the point (2, 1, 4) and has center (4, 3, 3). Solution:

22

23

24 Example 5: Find the center and radius of the
sphere Solution:

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