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PARCC Mathematics Practice Questions
Additional Math Practice for the EOY Test, Grades 3-5
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Before you begin… First, let’s look at some tips and ideas that might help you to do better on the actual test. If you have questions, ask them! It’s always better to know too much Today’s practice questions give you an idea of the problem solving to expect on the test. They are not intended for you to practice on the computer, rather to practice your thinking skills. As you solve these problems, show your work! Remember HOW you solved the problem. After you finish the problem, you should have some time to talk to other students or groups to see how their methods were different from yours. Your peers are a great resource!
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Choosing Tools Which tools apply to the math test? What do you need to know about those tools? Are there any tools that would NOT be useful (or distract instead of help)? Brainstorm…what tools do you remember being introduced to? Which ones will be most useful for Math? Think/Pair/Share The following tools can be used in Math: Highlighter Answer Eliminator Ruler Protractor
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Tips Look out for scroll bars! If a problem has a “part A,” it will also have a “part B” and maybe even a “part C!” Make sure to scroll down to answer all parts of the question. Multiple Choice vs. Multiple Select Box shapes Check marks/bubbles Bold text Read each question carefully! What is the question asking you to answer? Use your highlighter! How could colors be utilized in Math? Flagging When should you flag? Skip or answer flagged questions? Review your answers! The test will tell you what you did and didn’t complete at the end, so use that information. What should you do with extra time? How can it best be used?
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Grade 3 Problems will appear first. Click to advance to the next slide. Then, click the box to reveal the solution. Good luck! Remember to read each question carefully and focus on what exactly the question is asking you to find.
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1.) Which expression could be used to find the value of 938 + 234?
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1.) Which expression could be used to find the value of 938 + 234?
The answer is d because the numbers are both broken apart. 938 is , and 234 is Combine them and you get answer choice d.
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2. ) Alexis draws a shape. Each piece is 1/4 the area of the shape
2.) Alexis draws a shape. Each piece is 1/4 the area of the shape. Which shape could be the one Alexis drew? a.) b.) c.) d.)
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2. ) Alexis draws a shape. Each piece is 1/4 the area of the shape
2.) Alexis draws a shape. Each piece is 1/4 the area of the shape. Which shape could be the one Alexis drew? a.) b.) c.) d.) The answer is b. There should be 4 pieces, and each piece should be of equal size. Choices a and d both have 4 pieces, but the sizes are not equal so b is the only sensible answer.
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3. ) Which two ways show how to find the value of 600 x 80
3.) Which two ways show how to find the value of 600 x 80? Select two correct answers. a.) 60 groups of 8 hundreds b.) 80 groups of 6 hundreds c.) 6 x 10 x 8 x 10 d.) 6 x 100 x 8 x 100 e.) 6 x 100 x 8 x 10
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3. ) Which two ways show how to find the value of 600 x 80
3.) Which two ways show how to find the value of 600 x 80? Select two correct answers. a.) 60 groups of 8 hundreds b.) 80 groups of 6 hundreds c.) 6 x 10 x 8 x 10 d.) 6 x 100 x 8 x 100 e.) 6 x 100 x 8 x 10 If you use the commutative property of multiplication, 600 x 80 is the same as 80 x 600. Answer b is correct because 80 groups of 6 hundreds means 80 groups of 600, or 80 x 600. E is correct because 600 = 6 x 100 and 80 = 8 x 10.
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4.) Which three shapes are parallelograms? a. b. c. d. e. f.
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4.) Which three shapes are parallelograms? a. b. c. d. e. f.
A parallelogram has 4 sides, with each pair of opposite sides being parallel. A, b, and d are all parallelograms.
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5.) Mickey is attending a pin show where he can buy, sell, and trade pins. He starts with 188 pins. Part A: The first day, Mickey buys 106 pins, sells 88 pins, and trades 6 pins. How many pins does he have after the first day of the show? Part B: The second day, Mickey buys 4 packages of 6 pins. He wants to split the pins equally between himself and his 7 friends. How many pins will each of his 7 friends receive?
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5.) Mickey is attending a pin show where he can buy, sell, and trade pins. He starts with 188 pins. Part A: The first day, Mickey buys 106 pins, sells 88 pins, and trades 6 pins. How many pins does he have after the first day of the show? He will have 206 pins – 88 = 206. The 6 pins that are traded do not affect his total, because he gets one pin for every pin he trades. Part B: The second day, Mickey buys 4 packages of 6 pins. He wants to split the pins equally between himself and his 7 friends. How many pins will each of his 7 friends receive? Each of his friends will receive 4 pins. If he gets 4 packages of 6 pins, he has 24 (6 x 4) pins in all. He is splitting them up between himself and 7 friends, so there are 8 people in all. 24 ÷ 8 = 4, so each person will receive 4 pins (including Mickey).
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Grade 4 Problems will appear first. Click to advance to the next slide. Then, click the box to reveal the solution. Good luck! Remember to read each question carefully and focus on what exactly the question is asking you to find.
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1. ) Ben is measuring the growth of a small tree in his backyard
1.) Ben is measuring the growth of a small tree in his backyard. The first time he measures it, it is 4 meters high. After a month, it had grown 2 centimeters. After two months, it had grown an additional 4 centimeters. How many centimeters high is the tree now?
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1. ) Ben is measuring the growth of a small tree in his backyard
1.) Ben is measuring the growth of a small tree in his backyard. The first time he measures it, it is 4 meters high. After a month, it had grown 2 centimeters. After two months, it had grown an additional 4 centimeters. How many centimeters high is the tree now? The tree is 406 centimeters high. It started at 4 meters, or 400 centimeters. Then it grew 2 centimeters, then it grew 4 centimeters = 406 centimeters.
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2. ) Olivia ran 5,279 feet in 10 minutes
2.) Olivia ran 5,279 feet in 10 minutes. Jose ran 6,105 feet in 10 minutes. What is the difference in the total distance each person ran?
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2. ) Olivia ran 5,279 feet in 10 minutes
2.) Olivia ran 5,279 feet in 10 minutes. Jose ran 6,105 feet in 10 minutes. What is the difference in the total distance each person ran? The difference is 826 feet. 6,105-5,279 is 826.
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3. ) Which three fractions are equivalent to 3/18. a. ) 1/9 b. ) 1/6 c
3.) Which three fractions are equivalent to 3/18? a.) 1/9 b.) 1/6 c.) 6/24 d.) 6/36 e.) 9/54 f.) 9/56
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3. ) Which three fractions are equivalent to 3/18. a. ) 1/9 b. ) 1/6 c
3.) Which three fractions are equivalent to 3/18? a.) 1/9 b.) 1/6 c.) 6/24 d.) 6/36 e.) 2/12 f.) 9/56 1/6 is 3/18 simplified, so it’s an equivalent fraction. 6/36 is 3/18 x 2/2 since 2/2 is the same thing as 1. 2/12 is 1/6 x 2/2 since 1/6 is equivalent to 3/18 and 2/2 is the same as multiplying the fraction by 1.
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4.) The school’s art teacher ordered 28 boxes of multicolored construction paper. Each box contains 12 packages of paper. Each package of paper contains 100 sheets. What is the total number of sheets of paper ordered for the art room?
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4.) The school’s art teacher ordered 28 boxes of multicolored construction paper. Each box contains 12 packages of paper. Each package of paper contains 100 sheets. What is the total number of sheets of paper ordered for the art room? She ordered 33,600 total sheets of paper. 28 x 12 = 336, and 336 x 100 = 33,600.
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5.) Two figures are shown. In figure 1, the measure of angle RST is 126°. Figure 1: The measures of angles RSM and MSW are shown in Figure 2. The measure of angle RST is still 126°. Figure 2: Part A: Which equation can be used to find the value of y? a.) y – 32 – 57 = 126 b.) y x 32 x 57 = 126 c.) y ÷ 32 ÷ 57 = 126 d.) y = 126 Part B: What is the value of y? S T 126° R M W S 32° 57° y° T R M W
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5.) Two figures are shown. In figure 1, the measure of angle RST is 126°. Figure 1: The measures of angles RSM and MSW are shown in Figure 2. The measure of angle RST is still 126°. Figure 2: Part A: Which equation can be used to find the value of y? a.) y – 32 – 57 = 126 b.) y x 32 x 57 = 126 c.) y ÷ 32 ÷ 57 = 126 d.) y = 126 Part B: What is the value of y? y = 37° = 89. If y + 89 = 126, we would subtract This gives us the missing angle, or 37°. S T 126° R M W S 32° 57° y° T R M W
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Grade 5 Problems will appear first. Click to advance to the next slide. Then, click the box to reveal the solution. Good luck! Remember to read each question carefully and focus on what exactly the question is asking you to find.
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1.) Solve x 5 – (10 – 2 x 4)
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1.) Solve x 5 – (10 – 2 x 4) Solution: 21 This is a problem where order of operations must be used. First, look at the parentheses and solve. You have both subtraction and multiplication, but multiplication must be done first according to PEMDAS. 2 x 4 = 8, and 10 – 8 = 2. Now the equation will read x Again, multiplication comes before addition and subtraction, so the equation will now look like this: – 2. Add and subtract in order = 23, 23 – 2 = 21. Your answer is 21.
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2. ) Kyle lives 3/5 mile from school. Aidan lives 4/7 mile from school
2.) Kyle lives 3/5 mile from school. Aidan lives 4/7 mile from school. How much farther, in miles, does Kyle live from the school than Aidan?
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2. ) Kyle lives 3/5 mile from school. Aidan lives 4/7 mile from school
2.) Kyle lives 3/5 mile from school. Aidan lives 4/7 mile from school. How much farther, in miles, does Kyle live from the school than Aidan? Kyle lives 1/35 of a mile farther than Aidan. To solve this problem, you must find a common denominator. The lowest common denominator between 5 and 7 is 35. Make two equivalent fractions with a denominator of 35 and subtract: 3/5 = 21/35 and 4/7 = 20/35. 21/ /35 = 1/35.
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3. ) Which figure is always a rhombus. a. ) rectangle b
3.) Which figure is always a rhombus? a.) rectangle b.) parallelogram c.) square d.) quadrilateral
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3. ) Which figure is always a rhombus. a. ) rectangle b
3.) Which figure is always a rhombus? a.) rectangle b.) parallelogram c.) square d.) quadrilateral A rhombus is a parallelogram that has opposite equal acute angles, opposite equal obtuse angles, and four equal sides (or, more simply- a parallelogram with 4 equal sides). Squares have all of these features, therefore they are always rhombuses.
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4.) Solve. 1/6 + 2/3 – 1/4 = a.) 7/12 b.) 5/12 c.) 13/12 d.) 11/12
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4. ) Solve. 1/6 + 2/3 – 1/4 = a. ) 7/12 b. ) 5/12 c. ) 13/12 d
4.) Solve. 1/6 + 2/3 – 1/4 = a.) 7/12 b.) 5/12 c.) 13/12 d.) 11/12 First find a common denominator for 1/6 and 2/3. You can turn 2/3 into a fraction with 6 as a denominator, or 4/6. Add 1/6 and 4/6 to get 5/6. Then, find a common denominator between 5/6 and ¼. Both 6 and 4 share 12 as a common multiple, so you can change them to fractions with 12 as a denominator. 5/6 turns into 10/12 and ¼ turns into 3/12. 10/12 – 3/12 = 7/12.
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5. ) Select two correct statements. a
5.) Select two correct statements. a.) The product of 9/10 and 6 is greater than 6. b.) The product of 9/10 and 6 is less than 9/10. c.) The product of 1 ¼ and 3 is greater than 1 ¼. d.) The product of 1 ¼ and 3 is less than 3. e.) The product of 18/7 and 3/2 is greater than 18/7. f.) The product of 18/7 and 3/2 is less than 3/2.
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5. ) Select two correct statements. a
5.) Select two correct statements. a.) The product of 9/10 and 6 is greater than 6. b.) The product of 9/10 and 6 is less than 9/10. c.) The product of 1 ¼ and 3 is greater than 1 ¼. d.) The product of 1 ¼ and 3 is less than 3. e.) The product of 18/7 and 3/2 is greater than 18/7. f.) The product of 18/7 and 3/2 is less than 3/2. The first thing you need to know here is that “product” means “multiply.” If you multiplied all of these fractions, you’d find that c and e are the only true statements. The product of 1 ¼ and 3 is 3 ¾, which is greater than 1 ¼ (answer a). The product of 18/7 and 3/2 is 27/7 or 3 6/7, which is greater than 18/7 (answer e).
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Good luck! Remember the tips and problem solving strategies you used and learned from your classmates. Remember to read carefully, use the tools that work best for you, and take your time. Good luck on the test!
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