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ISHIK UNIVERSITY FACULTY OF EDUCATION Mathematics Education Department
Orhan TUĞ (PhDc) Integratıon, fınıte sum and defınıte ıntegral 1 1
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. A Figure 5.1.9 Figure 5.1.8
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Upper and lower estimates of the area in Example 2
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Approximations of the area for n = 2, 4, 8 and 12 rectangles
Section 1 / Figure 1
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Approximating rectangles when sample points are not endpoints
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5. 1 Sigma notation
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The graph of a typical function y = ƒ(x) over [a, b]
The graph of a typical function y = ƒ(x) over [a, b]. Partition [a, b] into n subintervals a < x1 < x2 <…xn < b. Select a number in each subinterval ck. Form the product f(ck)xk. Then take the sum of these products. 5.2
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The curve of with rectangles from finer partitions of [a, b]
The curve of with rectangles from finer partitions of [a, b]. Finer partitions create more rectangles with shorter bases.
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The definite integral of f(x) on [a, b]
If f(x) is non-negative, then the definite integral represents the area of the region under the curve and above the x-axis between the vertical lines x =a and x = b
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Rules for definite integrals
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5.3 The Fundamental Theorem of Calculus
Where f(x) is continuous on [a,b] and differentiable on (a,b) Find the derivative of the function:
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The Fundamental Theorem of Calculus
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Indefinite Integrals Definite Integrals
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Try These
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Answers
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Indefinite Integrals and Net Change
The integral of a rate of change is the net change. but If the function is non-negative, net area = area. If the function has negative values, the integral must be split into separate parts determined by f(x) = 0. Integrate one part where f(x) > 0 and the other where f(x) < 0.
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Indefinite Integrals and Net Change
The integral of a rate of change is the net change. If the function is non-negative, displacement = distance. If the function has negative values, the integral Must be split into separate parts determined by v = 0. Integrate one part where v>0 and the other where v<0.
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5.5 Review of Chain rule
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If F is the antiderivative of f
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Check by differentiation
Let u = inside function of more complicated factor. Check by differentiation
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Check by differentiation
Let u = inside function of more complicated factor. Check by differentiation
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Substitution with definite integrals
Using a change in limits
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The average value of a function on [a, b]
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